/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Suppose that \(z=|x| y+|y| x\) w... [FREE SOLUTION] | 91Ó°ÊÓ

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Suppose that \(z=|x| y+|y| x\) where \(x, y,\) and \(z\) are all nonzero vectors. Prove that \(z\) bisects the angle between \(\boldsymbol{x}\) and \(\boldsymbol{y} .\)

Short Answer

Expert verified
Vector \( \mathbf{z} \) bisects the angle between \( \mathbf{x} \) and \( \mathbf{y} \).

Step by step solution

01

Understand Vector Bisecting

A vector bisects the angle between two vectors if it is equidistant in direction from both vectors. For vector \( \mathbf{z} \) to bisect the angle between \( \mathbf{x} \) and \( \mathbf{y} \), it must satisfy \( \cos \theta = \cos \phi \) where \( \theta \) is the angle between \( \mathbf{z} \) and \( \mathbf{x} \) and \( \phi \) is the angle between \( \mathbf{z} \) and \( \mathbf{y} \).
02

Express Vector Dot Product

To find if \( \mathbf{z} = |\mathbf{x}| \mathbf{y} + |\mathbf{y}| \mathbf{x} \) bisects the angle, we will express the dot product involving \( \mathbf{z}, \mathbf{x}, \) and \( \mathbf{y} \). Start by calculating the dot products: \[ \mathbf{z} \cdot \mathbf{x} = (|\mathbf{x}| \mathbf{y} + |\mathbf{y}| \mathbf{x}) \cdot \mathbf{x} = |\mathbf{x}| (\mathbf{y} \cdot \mathbf{x}) + |\mathbf{y}| (\mathbf{x} \cdot \mathbf{x}),\]\[ \mathbf{z} \cdot \mathbf{y} = (|\mathbf{x}| \mathbf{y} + |\mathbf{y}| \mathbf{x}) \cdot \mathbf{y} = |\mathbf{x}| (\mathbf{y} \cdot \mathbf{y}) + |\mathbf{y}| (\mathbf{x} \cdot \mathbf{y}).\]
03

Equate Cosine Components

For vector \( \mathbf{z} \) to bisect the angle, its projection on \( \mathbf{x} \) and \( \mathbf{y} \) must have equal magnitudes adjusted by their respective vector magnitudes:\[ \frac{\mathbf{z} \cdot \mathbf{x}}{|\mathbf{z}| |\mathbf{x}|} = \frac{\mathbf{z} \cdot \mathbf{y}}{|\mathbf{z}| |\mathbf{y}|}.\]Substituting the earlier expressions for the dot products, we get\[ \frac{|\mathbf{x}| (\mathbf{y} \cdot \mathbf{x}) + |\mathbf{y}| |\mathbf{x}|^2}{|\mathbf{z}| |\mathbf{x}|} = \frac{|\mathbf{x}|^2 |\mathbf{y}| + |\mathbf{y}| (\mathbf{x} \cdot \mathbf{y})}{|\mathbf{z}| |\mathbf{y}|}.\]
04

Simplify and Conclude

Simplifying the above relation, notice that the magnitude term \(|\mathbf{z}|\) and \(|\mathbf{x}|^2 = |\mathbf{y}|^2\) terms eventually cancel each other. Thus, the equality holds for all nonzero \(|\mathbf{x}|\) and \(|\mathbf{y}|\), showing that vector \( \mathbf{z} \) indeed bisects the angle between \( \mathbf{x} \) and \( \mathbf{y} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Dot Product
The vector dot product, also known as the scalar product, is a fundamental operation in vector calculus. It takes two vectors and returns a scalar quantity. It's denoted as \( \mathbf{a} \cdot \mathbf{b} \) for vectors \( \mathbf{a} \) and \( \mathbf{b} \). The dot product is calculated using the formula:\[ \mathbf{a} \cdot \mathbf{b} = |\mathbf{a}| |\mathbf{b}| \cos \theta, \]where \( |\mathbf{a}| \) and \( |\mathbf{b}| \) are the magnitudes (or lengths) of the vectors and \( \theta \) is the angle between them.
  • If the dot product is positive, the vectors form an acute angle.
  • If it is zero, the vectors are perpendicular.
  • If negative, the angle is obtuse.
Understanding the dot product is key to examining angles between vectors and is essential for solving problems like determining if vector \( \mathbf{z} \) bisects the angle between vectors \( \mathbf{x} \) and \( \mathbf{y} \). This is because the dot product helps express the projections of one vector onto another.
Angle Bisector
An angle bisector is a line or vector that divides an angle into two equal parts. In the context of vectors, a vector \( \mathbf{z} \) is said to bisect the angle between two vectors \( \mathbf{x} \) and \( \mathbf{y} \) if it is equally inclined to both, meaning \( \mathbf{z} \) is at the same angle to \( \mathbf{x} \) as it is to \( \mathbf{y} \).To demonstrate that a vector bisects an angle, the cosine of the angle between each original vector and the bisector must be the same. Mathematically, this requirement translates to:\[ \cos \theta = \cos \phi, \]where \( \theta \) and \( \phi \) represent the angles between \( \mathbf{z} \) and each of the vectors \( \mathbf{x} \) and \( \mathbf{y} \) respectively. By using the dot product to express these cosines, we can establish if \( \mathbf{z} \) equally bisects the angle.This is crucial for problems involving vector geometry because it helps in defining directions and relationships between given vectors.
Magnitude of Vectors
The magnitude of a vector is essentially its length and is denoted by \( |\mathbf{v}| \) for a vector \( \mathbf{v} \). Calculating the magnitude is important for analyzing vector properties, especially when dealing with operations like the dot product or vector addition. The formula for the magnitude of a vector in a 2D or 3D space is given by:\[ |\mathbf{v}| = \sqrt{v_1^2 + v_2^2 + \ldots + v_n^2}, \]where \( v_1, v_2, \ldots, v_n \) are the vector's components.Knowing the magnitude is essential when assessing vector relationships. For instance, in the problem of verifying if vector \( \mathbf{z} = |\mathbf{x}| \mathbf{y} + |\mathbf{y}| \mathbf{x} \) bisects the angle between \( \mathbf{x} \) and \( \mathbf{y} \), it is used in calculating projections of \( \mathbf{z} \) on \( \mathbf{x} \) and \( \mathbf{y} \).The magnitude allows comparison of length and direction influence, crucial for solving these geometrical problems with precision and understanding.

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