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Recall that the Taylor series for \(f(x)=1 /(1-x)\) about 0 is the geometric series \(\sum_{k=0}^{\infty} x^{k} .\) Show that this series can also be found as a binomial series.

Short Answer

Expert verified
Question: Show that the Taylor series for f(x) = 1 / (1-x) can also be found as a binomial series. Answer: By rewriting f(x) = 1 / (1-x) in the form of (1+y)^n as (1-(-x))^(-1) and applying the binomial series formula, we obtain the series ∑(-1)^k (-x)^k. Simplifying the powers of -1, we get ∑1^k x^k, which is the same as the given geometric series ∑x^k. Thus, the Taylor series for f(x) = 1 / (1-x) can also be found as a binomial series.

Step by step solution

01

Recall the Binomial series formula

The binomial series formula is given by: $$(1+y)^n = \sum_{k=0}^{\infty} \binom{n}{k} y^k $$ Where n is any real number and \(|y|<1\).
02

Rewrite 1 / (1-x) in the form of (1+y)^n

Let's rewrite f(x) in the form of (1+y)^n, so we need to find y and n: $$1 /(1-x) = \frac{1}{1-(-x)} = (1-(-x))^{-1}$$ Now we can see that y = -x and n = -1.
03

Apply the binomial series formula to (1-y)^{-1}

Now, plug y = -x and n = -1 into the binomial series formula: \((1-(-x))^{-1} = \sum_{k=0}^{\infty} \binom{-1}{k} (-x)^k\)
04

Simplify the binomial coefficient

The binomial coefficient can be simplified as: $$\binom{-1}{k} = \frac{(-1)(-2)...(-k+1)}{k!} = \frac{(-1)^k}{k!} \cdot \frac{k!}{k!}=(-1)^k$$
05

Substitute the simplified binomial coefficient back

Now, substitute the simplified binomial coefficient back into the series: \(\sum_{k=0}^{\infty} \binom{-1}{k} (-x)^k = \sum_{k=0}^{\infty} (-1)^k (-x)^k\)
06

Simplify the series further

We can simplify the series further by looking at the powers of -1: $$\sum_{k=0}^{\infty} (-1)^k (-x)^k = \sum_{k=0}^{\infty} (-1 \cdot (-1))^k x^k = \sum_{k=0}^{\infty} 1^k x^k$$
07

Compare the binomial and geometric series

Finally, compare the simplified binomial series with the given geometric series: $$\sum_{k=0}^{\infty} x^k = \sum_{k=0}^{\infty} 1^k x^k$$ The series are the same. Therefore, it is shown that the Taylor series for f(x) = 1 / (1-x) can also be found as a binomial series.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Series
A binomial series is an expansion of the form \( (1+y)^n \) where \( n \) is any real number and \( y \) is a variable. Such a series becomes particularly useful when dealing with expressions that can be written in the form of \( 1 + y \). When we expand this expression using the binomial theorem, we get an infinite series for certain values of \( n \) that are not positive integers.

In the context of Taylor series, which are used to represent a function as an infinite sum of terms, the binomial series provides a straightforward expansion for functions of the form \( (1+x)^n \). It's critical to note that the series converges when \( |y| < 1 \) for any real number \( n \) — a condition for the validity of the expansion.

Using the binomial series to express \( 1 / (1-x) \) as shown in the given textbook solution introduces students to a flexible method for dealing with more complex functions that can be rewritten to fit the \( (1+y)^n \) pattern. This technique not only simplifies the problem but also broadens the understanding of series expansion and convergence.
Geometric Series
A geometric series is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the ratio. The series is of the form \( \[\sum_{k=0}^{\infty} ar^k\] \) where \( a \) is the first term, and \( r \) is the common ratio, with \( |r| < 1 \) for convergence. It's an essential concept in algebra and calculus.

In the given exercise, we encounter the simplest form of the geometric series, where \( a = 1 \) and the common ratio \( r = x \) with \( |x| < 1 \) to assure convergence of the series. As part of understanding Taylor series, recognizing that the function \( f(x) = 1 / (1-x) \) can be represented as a geometric series helps students to analyze and compute such functions' values efficiently for a given \( x \) within the region of convergence. Moreover, geometric series are foundational for various applications across mathematics and applied sciences.
Binomial Coefficient
The binomial coefficient, denoted as \( \binom{n}{k} \) and read as 'n choose k,' represents the number of ways to choose \( k \) elements from a set of \( n \) distinct elements without considering the order of selection. Mathematically, the binomial coefficient is defined as \( \frac{n!}{k!(n-k)!} \) where \( ! \) denotes factorial, which is the product of all positive integers up to that number.

Understanding binomial coefficients is vital for grasping the binomial theorem, which generalizes the pattern when multiplying a binomial like \( (a+b) \) multiple times. In the context of Taylor and binomial series, these coefficients determine the weights of the terms in the expansion.

The effectiveness of the binomial coefficient in the exercise solution reveals its power in simplifying complex expressions involving factorials, especially when dealing with negative or fractional powers. This mathematical tool is indispensable for students learning combinatorics, probability, algebra, and calculus.

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Most popular questions from this chapter

Use Taylor series to evaluate the following limits. Express the result in terms of the parameter(s). $$\lim _{x \rightarrow 0} \frac{e^{a x}-1}{x}$$

Identify the functions represented by the following power series. $$\sum_{k=0}^{\infty}(-1)^{k} \frac{x^{k}}{3^{k}}$$

Here is an alternative way to evaluate higher derivatives of a function \(f\) that may save time. Suppose you can find the Taylor series for \(f\) centered at the point a without evaluating derivatives (for example, from a known series). Explain why \(f^{(k)}(a)=k !\) multiplied by the coefficient of \((x-a)^{k} .\) Use this idea to evaluate \(f^{(3)}(0)\) and \(f^{(4)}(0)\) for the following functions. Use known series and do not evaluate derivatives. $$f(x)=e^{\cos x}$$

a. Use any analytical method to find the first four nonzero terms of the Taylor series centered at 0 for the following functions. You do not need to use the definition of the Taylor series coefficients. b. Determine the radius of convergence of the series. $$f(x)=\frac{e^{x}+e^{-x}}{2}$$

Suppose you approximate \(f(x)=\sec x\) at the points \(x=-0.2,-0.1,0.0,0.1,\) and 0.2 using the Taylor polynomials \(p_{2}(x)=1+x^{2} / 2\) and \(p_{4}(x)=1+x^{2} / 2+5 x^{4} / 24 .\) Assume that the exact value of sec \(x\) is given by a calculator. a. Complete the table showing the absolute errors in the approximations at each point. Show two significant digits. b. In each error column, how do the errors vary with \(x\) ? For what values of \(x\) are the errors largest and smallest in magnitude?

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