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Find the function represented by the following series and find the interval of convergence of the series. (Not all these series are power series.) $$\sum_{k=0}^{\infty}(\sqrt{x}-2)^{k}$$

Short Answer

Expert verified
Based on the given solution, determine the function representation for the given series and its interval of convergence. The function represented by the given series is: $$f(x) = \frac{1}{1 - (\sqrt{x}-2)}$$ The interval of convergence for the given series is: $(1, 9)$.

Step by step solution

01

Identify the Type of Series

The given series can be written as: $$\sum_{k=0}^{\infty}(\sqrt{x}-2)^{k}$$ This series is a geometric series with a common ratio of \((\sqrt{x}-2)\) and the first term when \(k=0\) is 1.
02

Find the Function Representation

For an infinite geometric series, the formula for the sum is: $$S = \frac{a}{1 - r}$$ Where \(a\) is the first term and \(r\) is the common ratio. In our case, the first term \(a = 1\) and the common ratio \(r = (\sqrt{x}-2)\). Plugging these values into the formula, we get: $$S(x) = \frac{1}{1 - (\sqrt{x}-2)}$$ The function represented by the given series is: $$f(x) = \frac{1}{1 - (\sqrt{x}-2)}$$
03

Find the Interval of Convergence

To find the interval of convergence, we will use the ratio test. The ratio test states that the series converges absolutely if: $$\lim_{k \to \infty} \frac{|a_{k+1}|}{|a_k|} = \lim_{k \to \infty} \frac{|(\sqrt{x}-2)^{k+1}|}{|(\sqrt{x}-2)^k|} < 1$$ By simplifying the limit, we get: $$\lim_{k \to \infty} |\sqrt{x}-2| = |\sqrt{x}-2| < 1$$ Now, we need to find the interval of x values satisfying this inequality: $$-1 < \sqrt{x}-2 < 1$$ Add 2 to all sides of the inequality to isolate \(\sqrt{x}\): $$1 < \sqrt{x} < 3$$ Now, square all sides of the inequality to get rid of the square root: $$1^2 < (\sqrt{x})^2 < 3^2$$ $$1 < x < 9$$ The interval of convergence for the given series is \((1, 9)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Series Convergence
Understanding when a series converges is fundamental in mathematics. Specifically, a series is said to converge if the sum of its infinite terms approaches a finite value as more terms are added. This idea of convergence is pivotal when dealing with infinite series, such as geometric series, that have a specific pattern in how the terms are derived and added.

For a geometric series, where each term is derived by multiplying the previous term by a constant known as the common ratio (denoted as \( r \)), convergence can be neatly determined. In general, a geometric series
  • Converges if the absolute value of the common ratio \(|r| < 1\).
  • Diverges if \(|r| \geq 1\).
This condition ensures that as we proceed to add more terms, the terms become smaller and in turn, the series approaches a specific sum.

In the exercise mentioned, the series is a geometric one with a common ratio of \((\sqrt{x} - 2)\). Thus, checking if \(|\sqrt{x} - 2| < 1\) helps us verify if and where this series converges.
Interval of Convergence
The interval of convergence is essentially the set of all values for which a given series converges. Finding this interval can sometimes be a straightforward task, especially with geometric series, due to their predictable nature.

In our problem, after establishing that the series converges when \(|\sqrt{x} - 2| < 1\), this inequality gives us a way to explore when the series converges:
  • First, solve the inequality \(-1 < \sqrt{x} - 2 < 1\).
  • Adding 2 to each part, we get \(1 < \sqrt{x} < 3\).
  • Squaring each part to remove the square root, we see that \(1 < x < 9\).
This leads us to the interval of convergence \((1, 9)\), meaning the series converges for all \(x\) between 1 and 9, exclusive.
Ratio Test
The ratio test is a powerful tool in determining series convergence, especially useful for series where each term is multiplied by a consistent formula or function. This test helps us assess whether the absolute value of the ratio of consecutive terms points toward a limit that is less than one.

Here's a clearer view of how it works:
  • For a series \( \sum a_k \), consider the limit \( \lim_{k \to \infty} \left| \frac{a_{k+1}}{a_k} \right| \).
  • If this limit is less than 1, the series converges absolutely.
  • If greater than 1, or if it tends toward infinity, the series diverges.
  • When the ratio equals 1, the test is inconclusive and other methods are needed.
In our case, with the geometric series involving \((\sqrt{x} - 2)^k\), simplifying the ratio for the consecutive terms brings us to \( \lim_{k \to \infty} |\sqrt{x} - 2| < 1 \). This simplicity often makes the ratio test a favored approach when dealing with power or geometric series, offering a direct path toward identifying the series' convergence behavior.

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