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Functions to power series Find power series representations centered at 0 for the following functions using known power series. Give the interval of convergence for the resulting series. $$f(x)=\frac{1}{1+x^{2}}$$

Short Answer

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Question: Find the power series representation for the function $$f(x)=\frac{1}{1+x^{2}}$$ and determine its interval of convergence. Answer: The power series representation for the given function $$f(x)=\frac{1}{1+x^{2}}$$ is: $$f(x) = 1 + x^2 + x^4 + x^6 + ...$$ The interval of convergence for this power series is \(-1<x<1\).

Step by step solution

01

Use the geometric series formula

We have the geometric series formula: $$\frac{1}{1-y} = 1 + y + y^2 + y^3 + ...$$ for |y| < 1.
02

Substitute the given function

We have the given function: $$f(x)=\frac{1}{1+x^{2}}$$ Compared to the geometric series, we can see that y = x^2. So, we substitute this into the geometric series formula: $$f(x) = 1 + x^2 + (x^2)^2 + (x^2)^3 + ...$$
03

Simplify the power series

Now, let's simplify this power series: $$f(x) = 1 + x^2 + x^4 + x^6 + ...$$
04

Determine the interval of convergence

The interval of convergence for the geometric series is |y| < 1. Since y = x^2, we have: $$|x^2| < 1$$ $$|-1 < x^2 < 1$$ $$-1 < x < 1$$ Hence, the interval of convergence for the power series is \(-1<x<1\).
05

Write the final answer

Therefore, the power series representation for the given function $$f(x)=\frac{1}{1+x^{2}}$$ is: $$f(x) = 1 + x^2 + x^4 + x^6 + ...$$ And the interval of convergence is \(-1<x<1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Geometric Series
Imagine having a set of numbers where each term is a constant multiple of the previous one. This is the essence of a geometric series, a critical concept in calculus and analytic geometry. Specifically, a geometric series takes the form \(1 + y + y^2 + y^3 + \ldots\) for some variable \(y\), where each term is generated by multiplying the previous term by \(y\).

In our exercise, we leveraged the geometric series to represent the function \(f(x)=\frac{1}{1+x^{2}}\) by equating the variable \(y\) with \(x^2\), since the structure of \(f(x)\) strongly resembles the formula for a geometric series. The power of the geometric series lies in its simplicity and the ease with which it can handle functions involving squares, such as \(x^2\), making complex calculus concepts like power series representation far more approachable.
Interval of Convergence
The interval of convergence is a fancy way of saying 'the range where a series works' - that is, the values for which it converges to a limit rather than ballooning to infinity or jumping around without settling down. For a geometric series, this interval is based on the absolute value of the ratio between successive terms being less than 1, which is expressed as \( |y| < 1 \).

During our exercise, we used this simple rule to nail down the interval of convergence for the power series representation of \(f(x)\). We discovered that \(f(x)\) converges when \(x\) lies between -1 and 1, which gives us the interval of convergence \( -1 < x < 1 \). Anything outside this range would lead the series to diverge, meaning it wouldn’t represent our function accurately.
Calculus
At the core of understanding motion, growth, and an infinite number of patterns in the natural world is calculus, a branch of mathematics that involves the study of change. It allows us to describe and analyze the behaviors and relationships of variables within functions. It’s what we used in our exercise to identify a power series representation, which is a method of expressing functions as an infinite sum of terms calculated from the function's derivatives at a point.

In essence, using calculus in our example helped us to take a complex function like \(f(x)=\frac{1}{1+x^{2}}\) and break it down into simpler, infinitely repeating patterns—like a fractal made up of algebraic pieces that describe the whole picture more manageably.
Functions
Think of functions as special relationships where every input is connected to exactly one output. It's like having a cosmic vending machine where you select an input and the output is predetermined—you always know what you're going to get. They are fundamental tools in mathematics for modeling relationships and changes between quantities.

In the given exercise, we analyzed the function \(f(x)\) and found a way to express it using a power series, which is essentially a way of breaking down the function into a sum of its parts (in this case, powers of \(x\)). The ability to manipulate and represent functions in various forms, such as power series, is a valuable skill in mathematics, especially in calculus where understanding the nuanced behavior of functions is essential.

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Most popular questions from this chapter

Use a Taylor series to approximate the following definite integrals. Retain as many terms as needed to ensure the error is less than \(10^{-4}.\) $$\int_{0}^{0.4} \ln \left(1+x^{2}\right) d x$$

Suppose you approximate \(f(x)=\sec x\) at the points \(x=-0.2,-0.1,0.0,0.1,\) and 0.2 using the Taylor polynomials \(p_{2}(x)=1+x^{2} / 2\) and \(p_{4}(x)=1+x^{2} / 2+5 x^{4} / 24 .\) Assume that the exact value of sec \(x\) is given by a calculator. a. Complete the table showing the absolute errors in the approximations at each point. Show two significant digits. b. In each error column, how do the errors vary with \(x\) ? For what values of \(x\) are the errors largest and smallest in magnitude?

Elliptic integrals The period of a pendulum is given by $$ T=4 \sqrt{\frac{\ell}{g}} \int_{0}^{\pi / 2} \frac{d \theta}{\sqrt{1-k^{2} \sin ^{2} \theta}}=4 \sqrt{\frac{\ell}{g}} F(k) $$ where \(\ell\) is the length of the pendulum, \(g \approx 9.8 \mathrm{m} / \mathrm{s}^{2}\) is the acceleration due to gravity, \(k=\sin \left(\theta_{0} / 2\right),\) and \(\theta_{0}\) is the initial angular displacement of the pendulum (in radians). The integral in this formula \(F(k)\) is called an elliptic integral, and it cannot be evaluated analytically. a. Approximate \(F(0.1)\) by expanding the integrand in a Taylor (binomial) series and integrating term by term. b. How many terms of the Taylor series do you suggest using to obtain an approximation to \(F(0.1)\) with an error less than \(10^{-3} ?\) c. Would you expect to use fewer or more terms (than in part (b)) to approximate \(F(0.2)\) to the same accuracy? Explain.

Use an appropriate Taylor series to find the first four nonzero terms of an infinite series that is equal to the following numbers. $$\sin 1$$

Consider the following common approximations when \(x\) is near zero. a. Estimate \(f(0.1)\) and give a bound on the error in the approximation. b. Estimate \(f(0.2)\) and give a bound on the error in the approximation. $$f(x)=\cos x \approx 1-x^{2} / 2$$

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