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Evaluate each geometric sum. $$\sum_{k=0}^{8} 3^{k}$$

Short Answer

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Question: Evaluate the sum of the finite geometric series: $$\sum_{k=0}^{8} 3^{k}$$ Answer: The sum of the given finite geometric series is 9841.

Step by step solution

01

Identify the first term (a) and the common ratio (r)

The first term in the given geometric series is: $$a = 3^0 = 1$$ The common ratio is the number whose power we raise to get each term: $$r = 3$$
02

Determine the number of terms (n) in the series

The summation is given by: $$\sum_{k=0}^{8} 3^{k}$$ This means we have to sum up the terms from \(3^0\) to \(3^8\). Since there are 9 terms in total (\(0, 1, 2, \ldots, 8\)), we have: $$n = 9$$
03

Apply the formula for the sum of a finite geometric series

Using the formula \(S_n = \frac{a(1-r^n)}{1-r}\), we have: $$S_n = \frac{1(1-3^9)}{1-3}$$
04

Calculate the solution

Plugging in the values, we get: $$S_n = \frac{1(1-19683)}{1-3} = \frac{-19682}{-2} = 9841$$ So, the sum of the given geometric series is 9841.

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