/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 54 Write each repeating decimal fir... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Write each repeating decimal first as a geometric series and then as a fraction (a ratio of two integers). $$5.12 \overline{83}=5.12838383 \ldots$$

Short Answer

Expert verified
Question: Convert the repeating decimal 5.12$\overline{83}$ into a fraction. Answer: The repeating decimal 5.12$\overline{83}$ can be converted into the fraction $\frac{14789}{2475}$.

Step by step solution

01

Separate the Repeating and Non-Repeating Parts

We have the repeated decimal: $$5.12 \overline{83} = 5.12838383 \ldots$$ The non-repeating part is \(5.12\), and the repeating part is \(0.\overline{83}\).
02

Write the Repeating Decimal as a Geometric Series

To write the repeating part as a geometric series, we can express it as the sum of its terms: $$0.\overline{83} = 0.83 + 0.0083 + 0.000083 + \ldots$$ This can be written as an infinite geometric series: $$0.\overline{83} = 83\left(\frac{1}{100}\right)^1 + 83\left(\frac{1}{100}\right)^2 + 83\left(\frac{1}{100}\right)^3 + \cdots$$ This is a geometric series with the first term \(a = 83\left(\frac{1}{100}\right)^1\) and the common ratio \(r = \frac{1}{100}\).
03

Find the Sum of the Geometric Series

To find the sum of the geometric series, we can use the formula for the sum of an infinite geometric series, given by: $$S = \frac{a}{1 - r}$$ Substituting the values for \(a\) and \(r\), we have: $$S = \frac{83\left(\frac{1}{100}\right)^1}{1 - \frac{1}{100}} = \frac{83\left(\frac{1}{100}\right)}{\frac{99}{100}}$$ Which simplifies to: $$S = \frac{83}{99}$$
04

Combine the Non-Repeating and Repeating Parts as a Fraction

Now that we have the fraction for the repeating part, we can add it to the non-repeating part to find our final result: $$5.12 \overline{83} = 5.12 + 0.\overline{83}$$ Let's express \(5.12\) as a fraction: $$5.12 = \frac{512}{100}$$ Now, we add the two fractions: $$\frac{512}{100} + \frac{83}{99} = \frac{512 \cdot 99 + 83 \cdot 100}{100 \cdot 99} = \frac{50656 + 8300}{9900} = \frac{58956}{9900}$$ Reducing this fraction to its lowest terms, we have: $$\frac{58956}{9900} = \frac{29578}{4950} = \frac{14789}{2475}$$
05

Write the Final Result

Now, we have written the repeating decimal as a fraction. $$5.12\overline{83} = \frac{14789}{2475}$$

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Geometric Series
A geometric series is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio. We often encounter geometric series in mathematics when dealing with repeating decimals.

For example, the repeating decimal portion of the number in our exercise, which is 0.0083 repeated, can be expressed as the infinite geometric series: \[\begin{equation}0.\bar{83} = 83\left(\frac{1}{100}\right)^1 + 83\left(\frac{1}{100}\right)^2 + 83\left(\frac{1}{100}\right)^3 + \cdots\end{equation}\]Each term in this series is a product of the initial term, 83, and a power of \(\frac{1}{100}\), making it a textbook example of a geometric series.
Sum of an Infinite Geometric Series
The sum of an infinite geometric series can be determined using a specific formula, provided the series converges, meaning the absolute value of the common ratio is less than 1. The formula is given by \[\begin{equation}S = \frac{a}{1 - r}\end{equation}\]where \(S\) is the sum of the series, \(a\) is the first term, and \(r\) is the common ratio. In the context of our repeating decimal, we applied this formula to find that the sum of the repeating portion \(0.\bar{83}\) is \(\frac{83}{99}\). This elegant technique allows us to transform something seemingly infinite and complex into a simple, rational number.
Expressing Decimals as Fractions
Expressing a decimal as a fraction involves identifying the repeating and non-repeating parts of the decimal, if any, and then converting each into fraction form. The non-repeating part is straightforward to convert, as we just count the number of decimal places, place the decimal as the numerator, and the corresponding power of 10 as the denominator.

For the repeating part, as in the example \(0.\bar{83}\), we can use the geometric series method to write it as a fraction. This two-pronged approach lets us translate any decimal—repeating or not—into a fraction, which can be a more manageable form, especially for further mathematical operations.
Fraction Simplification
Fraction simplification is the process of reducing a fraction to its simplest form, where the numerator and the denominator are the smallest possible integers that have the same ratio as the original fraction. To simplify a fraction, we need to find the greatest common divisor (GCD) of the numerator and denominator and divide both by that number.

For instance, in our problem, the final fraction obtained was \(\frac{58956}{9900}\). By finding the GCD of 58956 and 9900, we can simplify the fraction down to \(\frac{14789}{2475}\), its simplest form. Simplifying fractions makes them easier to understand and work with, as it gives us the most reduced version of the ratio, eliminating any factor common to both the numerator and the denominator.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider the following situations that generate a sequence. a. Write out the first five terms of the sequence. b. Find an explicit formula for the terms of the sequence. c. Find a recurrence relation that generates the sequence. d. Using a calculator or a graphing utility, estimate the limit of the sequence or state that it does not exist. Jack took a \(200-\mathrm{mg}\) dose of a painkiller at midnight. Every hour, \(5 \%\) of the drug is washed out of his bloodstream. Let \(d_{n}\) be the amount of drug in Jack's blood \(n\) hours after the drug was taken, where \(d_{0}=200 \mathrm{mg}\)

Consider the following infinite series. a. Write out the first four terms of the sequence of partial sums. b. Estimate the limit of \(\left\\{S_{n}\right\\}\) or state that it does not exist. $$\sum_{k=1}^{\infty} \frac{3}{10^{k}}$$

Find a formula for the nth term of the sequence of partial sums \(\left\\{S_{n}\right\\} .\) Then evaluate lim \(S_{n}\) to obtain the value of the series or state that the series diverges.\(^{n \rightarrow \infty}\) $$\sum_{k=1}^{\infty}\left(\tan ^{-1}(k+1)-\tan ^{-1} k\right)$$

Consider the following sequences defined by a recurrence relation. Use a calculator, analytical methods, and/or graphing to make a conjecture about the limit of the sequence or state that the sequence diverges. $$a_{n+1}=2 a_{n}\left(1-a_{n}\right) ; a_{0}=0.3$$

Use Theorem 8.6 to find the limit of the following sequences or state that they diverge. $$\left\\{\frac{3^{n}}{n !}\right\\}$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.