/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 47 Determine whether the following ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Determine whether the following series converge absolutely, converge conditionally, or diverge. $$\sum_{k=1}^{\infty} \frac{(-1)^{k+1}}{k^{3 / 2}}$$

Short Answer

Expert verified
Answer: The series converges absolutely.

Step by step solution

01

Apply the Absolute Convergence Test (Series Test)

We will test for absolute convergence by examining the series obtained by replacing each term with its absolute value: $$\sum_{k=1}^{\infty} \left|\frac{(-1)^{k+1}}{k^{3 / 2}}\right| = \sum_{k=1}^{\infty} \frac{1}{k^{3 / 2}}$$ This is a p-series with \(p = 3/2 > 1\). P-series with \(p > 1\) are known to converge, so the given series converges absolutely.
02

Conclusion

Since the series converges absolutely, it must also converge. There is no need to test for conditional convergence or divergence. The series $$\sum_{k=1}^{\infty} \frac{(-1)^{k+1}}{k^{3 / 2}}$$ converges absolutely.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

p-series Convergence
Understanding the convergence of p-series is essential when we're dealing with infinite series. A p-series is expressed in the form \[\sum_{k=1}^\infty \frac{1}{k^p}\]\, where \( p \) is a real number. The convergence of a p-series depends on the value of \( p \).
When \( p > 1 \), the p-series converges because the terms of the series become small quickly enough such that their sum approaches a finite limit. If we imagine adding slices of bread to create a sandwich that's only so thick, there's a point where additional slices don't noticeably increase its size—it's similar with these series.
However, for \( p \leq 1 \), the series diverges, meaning the sum grows without bound. Picture trying to stack infinitely many books on a shelf; if each book isn't thin enough, eventually, they'll spill over!
In the given exercise, we have \( p = \frac{3}{2} \), which is greater than 1. This tells us that the series converges, and more specifically, it converges absolutely.
Conditional Convergence
Now, let's talk about conditional convergence. A series is said to be conditionally convergent if it converges but does not converge absolutely.
This means that if we were to take the absolute values of all the terms and sum them up, the series would diverge. It's like having a rowdy group of people who can only form a neat queue under certain rules—remove the rules, and chaos ensues!
To test for conditional convergence, one generally uses the Alternating Series Test or other relevant tests. However, since the exercise we're looking at results in a conclusion of absolute convergence, the series converges without any need to consider if it's only conditionally convergent. It fits together nicely, with or without the absolute value.
Infinite Series
Lastly, the broad concept that encompasses both p-series and conditional convergence is the infinite series. An infinite series is essentially a sum of an infinite sequence of numbers, which may or may not have a finite sum.
Imagine you're pouring sand into a bucket – if you add the sand grain by grain, endlessly, will the bucket eventually fill up? The answer depends on how you're adding the grains (the series) and how big the bucket is (whether the series converges).
Mathematically, the sum of an infinite series can be found using various tests, such as the Ratio Test, Root Test, Integral Test, and others. However, understanding the behavior of p-series is a useful tool in identifying the convergence of more complex series related to them.
The series in the exercise clearly falls under the infinite series category since it has an infinite number of terms. As the solution indicates, by testing the series after removing the alternating sign pattern (which shows absolute convergence), we've learned that our 'bucket' will indeed fill up, marking the series as clearly convergent.

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Most popular questions from this chapter

The Greeks solved several calculus problems almost 2000 years before the discovery of calculus. One example is Archimedes' calculation of the area of the region \(R\) bounded by a segment of a parabola, which he did using the "method of exhaustion." As shown in the figure, the idea was to fill \(R\) with an infinite sequence of triangles. Archimedes began with an isosceles triangle inscribed in the parabola, with area \(A_{1}\), and proceeded in stages, with the number of new triangles doubling at each stage. He was able to show (the key to the solution) that at each stage, the area of a new triangle is \(\frac{1}{8}\) of the area of a triangle at the previous stage; for example, \(A_{2}=\frac{1}{8} A_{1},\) and so forth. Show, as Archimedes did, that the area of \(R\) is \(\frac{4}{3}\) times the area of \(A_{1}\).

A ball is thrown upward to a height of \(h_{0}\) meters. After each bounce, the ball rebounds to a fraction r of its previous height. Let \(h_{n}\) be the height after the nth bounce and let \(S_{n}\) be the total distance the ball has traveled at the moment of the nth bounce. a. Find the first four terms of the sequence \(\left\\{S_{n}\right\\}\) b. Make a table of 20 terms of the sequence \(\left\\{S_{n}\right\\}\) and determine \(a\) plausible value for the limit of \(\left\\{S_{n}\right\\}\) $$h_{0}=20, r=0.5$$

Consider the following infinite series. a. Write out the first four terms of the sequence of partial sums. b. Estimate the limit of \(\left\\{S_{n}\right\\}\) or state that it does not exist. $$\sum_{k=1}^{\infty}(-1)^{k} k$$

Assume that \(\sum_{k=1}^{\infty} \frac{1}{k^{2}}=\frac{\pi^{2}}{6}\) (Exercises 65 and 66 ) and that the terms of this series may be rearranged without changing the value of the series. Determine the sum of the reciprocals of the squares of the odd positive integers.

Prove that if \(\left\\{a_{n}\right\\} \ll\left\\{b_{n}\right\\}\) (as used in Theorem 8.6 ), then \(\left\\{c a_{n}\right\\} \ll\left\\{d b_{n}\right\\},\) where \(c\) and \(d\) are positive real numbers.

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