/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 30 Several terms of a sequence $$\l... [FREE SOLUTION] | 91Ó°ÊÓ

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Several terms of a sequence $$\left\\{a_{n}\right\\}_{n=1}^{\infty} \text { are given.}$$ a. Find the next two terms of the sequence. b. Find a recurrence relation that generates the sequence (supply the initial value of the index and the first term of the sequence). c. Find an explicit formula for the nth term of the sequence. $$\\{64,32,16,8,4, \dots\\}$$

Short Answer

Expert verified
Based on the above solution, the given sequence is a geometric sequence with each term being half of the previous one. The recurrence relation for the sequence is $$a_{n+1} = \frac{1}{2}a_n,\ \text {for}\ n \geq 1, \text{with}\ a_1=64$$, and the explicit formula for the nth term is $$a_n = 64\left(\frac{1}{2}\right)^{n-1}$$. The next two terms of the sequence are 4 and 2.

Step by step solution

01

Identify the pattern of the sequence

First, let's examine the given terms carefully: $$64, 32, 16, 8, 4, \dots$$ If we look closely at these terms, we can see that each term is half of the previous one. Therefore, the pattern appears to involve dividing by 2.
02

Find the next two terms

Using the pattern identified in Step 1, we can find the next two terms of the sequence by dividing each of the last given terms by 2: $$\frac{8}{2} = 4$$ $$\frac{4}{2} = 2$$ So, the next two terms are 4 and 2.
03

Find a recurrence relation

Since we observed that each term is half of the previous term, we can write the recurrence relation as: $$a_{n+1} = \frac{1}{2}a_n$$ Now we need to supply the initial value of the index and the first term of the sequence. It is given that the first term is 64, and the index starts from 1. So, we have: n = 1 $$a_1 = 64$$ Thus, the recurrence relation is: $$a_{n+1} = \frac{1}{2}a_n,\ \text {for}\ n \geq 1, \text{with}\ a_1=64$$
04

Find an explicit formula for the nth term

To compute the formula for the nth term, first let's look at the first few terms: $$a_1 = 64, \hspace{5mm} a_2 = \frac{1}{2}a_1, \hspace{5mm} a_3 = \frac{1}{2}a_2, \hspace{5mm} \ldots$$ We can see that: $$a_2 = \frac{1}{2}a_1 = \frac{1}{2}^{1}a_1$$ $$a_3 = \frac{1}{2}a_2 = \frac{1}{2}\left(\frac{1}{2}a_1\right) = \frac{1}{2}^{2}a_1$$ So, following this pattern, we can express the nth term as: $$a_n = \frac{1}{2}^{(n-1)}a_1$$ Considering that $$a_1 = 64$$, we find the explicit formula for the nth term to be: $$a_n = 64\left(\frac{1}{2}\right)^{n-1}$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Geometric Sequence
A geometric sequence is a sequence of numbers where each term after the first is found by multiplying the previous term by a fixed, non-zero number called the common ratio. When examining sequences such as \( \[64, 32, 16, 8, 4, \ldots\] \), we notice that each term is obtained by multiplying the preceding term by \( \frac{1}{2} \), which in this case is the common ratio. In general, a geometric sequence can be written as \( a, ar, ar^2, ar^3, \ldots \) where \( a \) is the first term and \( r \) is the common ratio.

Understanding geometric sequences can help you predict future terms and model real-world situations like exponential growth or decay. The key characteristic that defines such sequences is the constant ratio between consecutive terms; this makes them distinct from other types of sequences, like arithmetic sequences, which have a constant difference instead of a ratio.
Explicit Formula
An explicit formula of a sequence allows us to find any term of the sequence without having to compute all the preceding terms. It defines the nth term of a sequence as a function of \( n \). For the sequence in our exercise, the explicit formula is \( a_n = 64\left(\frac{1}{2}\right)^{n-1} \). This formula means that to find the nth term, you simply raise \( \frac{1}{2} \) to the power of \( n - 1 \) and multiply by 64. This explicit formula reflects the properties of a geometric sequence wherein each term is derived from the first term multiplied by the common ratio to the power of \( n - 1 \).

Explicit formulas are incredibly powerful as they can save time and effort, especially when dealing with large values of \( n \). They provide a direct way to calculate terms in a sequence and are extremely useful for mathematical analysis and applications.
Sequence and Series
When talking about sequences, like the geometric sequence previously discussed, we refer to an ordered list of numbers. A series, on the other hand, is the sum of the terms of a sequence. It's important to distinguish between the individual terms of a sequence and the sum of those terms which makes up a series.

For instance, the series formed by summing the first \( n \) terms of the geometric sequence \( 64, 32, 16, 8, 4, \ldots \) is represented as \( 64 + 32 + 16 + 8 + 4 + \ldots \). Sequences and series are fundamental concepts in mathematics and are particularly important in topics such as calculus, financial calculations, and the study of functions.
Arithmetic Operations in Sequences
Sequences often require the use of arithmetic operations to analyze or find their terms. In the case of geometric sequences, multiplication and division are used to move from one term to the next. With our given sequence, \( 64, 32, 16, 8, 4, \ldots \), we repeatedly divide by 2, which is an arithmetic operation.

Arithmetic operations in sequences are not only limited to finding subsequent terms but also play a role in the computation of series, where addition is commonly used. Understanding how to apply these operations correctly is crucial for working with sequences and series. They allow us to summarize and analyze patterns within sequences, which can lead to deeper insights and applications in mathematics and science.

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Most popular questions from this chapter

Consider the following situations that generate a sequence. a. Write out the first five terms of the sequence. b. Find an explicit formula for the terms of the sequence. c. Find a recurrence relation that generates the sequence. d. Using a calculator or a graphing utility, estimate the limit of the sequence or state that it does not exist. The Consumer Price Index (the CPI is a measure of the U.S. cost of living) is given a base value of 100 in the year \(1984 .\) Assume the CPI has increased by an average of \(3 \%\) per year since \(1984 .\) Let \(c_{n}\) be the CPI \(n\) years after \(1984,\) where \(c_{0}=100\)

The fractal called the snowflake island (or Koch island ) is constructed as follows: Let \(I_{0}\) be an equilateral triangle with sides of length \(1 .\) The figure \(I_{1}\) is obtained by replacing the middle third of each side of \(I_{0}\) with a new outward equilateral triangle with sides of length \(1 / 3\) (see figure). The process is repeated where \(I_{n+1}\) is obtained by replacing the middle third of each side of \(I_{n}\) with a new outward equilateral triangle with sides of length \(1 / 3^{n+1}\). The limiting figure as \(n \rightarrow \infty\) is called the snowflake island. a. Let \(L_{n}\) be the perimeter of \(I_{n} .\) Show that \(\lim _{n \rightarrow \infty} L_{n}=\infty\) b. Let \(A_{n}\) be the area of \(I_{n} .\) Find \(\lim _{n \rightarrow \infty} A_{n} .\) It exists!

In \(1978,\) in an effort to reduce population growth, China instituted a policy that allows only one child per family. One unintended consequence has been that, because of a cultural bias toward sons, China now has many more young boys than girls. To solve this problem, some people have suggested replacing the one-child policy with a one-son policy: A family may have children until a boy is born. Suppose that the one-son policy were implemented and that natural birth rates remained the same (half boys and half girls). Using geometric series, compare the total number of children under the two policies.

Evaluate the limit of the following sequences or state that the limit does not exist. $$a_{n}=\cos \left(0.99^{n}\right)+\frac{7^{n}+9^{n}}{63^{n}}$$

Express each sequence \(\left\\{a_{n}\right\\}_{n=1}^{\infty}\) as an equivalent sequence of the form \(\left\\{b_{n}\right\\}_{n=3}^{\infty}\). $$\\{2 n+1\\}_{n=1}^{\infty}$$

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