/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 Evaluate each geometric series o... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate each geometric series or state that it diverges. $$\sum_{k=4}^{\infty} \frac{1}{5^{k}}$$

Short Answer

Expert verified
Answer: The sum of the given infinite geometric series is \(\frac{1}{500}\).

Step by step solution

01

Identify the first term and common ratio

As we can see from the series, each term can be written as \(\frac{1}{5^{k}}\). The common ratio, r, by which each term is multiplied is \(\frac{1}{5}\). The first term, a, can be found by substituting k=4 in the formula \(\frac{1}{5^{k}}\): $$a = \frac{1}{5^{4}}$$
02

Check for Convergence

To determine if the series converges, we examine the common ratio, \(r=\frac{1}{5}\). Since the absolute value of the ratio, \(|r|=|\frac{1}{5}|=\frac{1}{5}<1\), the given series converges.
03

Calculate the sum of the infinite series

Since the series converges, we can calculate the sum using the formula for the sum of an infinite geometric series: $$S_\infty = \frac{a}{1 - r}$$ Now, we will substitute the values of \(a\) and \(r\) in the formula: $$S_\infty = \frac{\frac{1}{5^{4}}}{1 - \frac{1}{5}}$$
04

Simplify the expression

Now, we will simplify the expression to get the sum of the infinite series: $$S_\infty = \frac{\frac{1}{625}}{\frac{4}{5}}$$ To proceed, multiply both numerator and denominator by 625 to eliminate the fraction in the numerator: $$S_\infty = \frac{1}{\frac{2500}{5}}$$ Finally, divide the denominator by 5 to get the sum: $$S_\infty = \frac{1}{500}$$ So, the sum of the given geometric series is \(\frac{1}{500}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Infinite Series
An infinite series is a sum that continues indefinitely, often represented as the sum of an infinite number of terms. A classic example is the geometric series, where each term is a constant multiple of the previous one. Unlike finite sums, which add up a set number of terms, infinite series continue without bound. However, this does not always mean they add up to an infinite value. Even without a last term, many infinite series can have well-defined sums. This is where the idea of convergence comes into play, determining whether the sum of the series can reach a specific finite number.
  • Each term in the series contributes a portion to the overall sum.
  • The series examined in our context is vast, starting from a specific term and extending to infinity.
For example, in our given series from the exercise, the terms are of the form \( \frac{1}{5^{k}} \) which starts at \( k=4 \) and stretches out to infinity.
Convergence
Convergence is a vital concept when dealing with an infinite series. The notion of convergence answers the question of whether an infinite series settles at a particular value as more terms are considered. A series is said to be convergent if, as you add more and more terms, the series approaches a finite limit. The key determinant of convergence in a geometric series is the common ratio \( r \).
  • If the absolute value of \( r \) is less than 1, the series converges.
  • If \( |r| \geq 1 \), the series diverges, meaning it doesn't settle at a finite value.
In the example given, the common ratio \( r = \frac{1}{5} \) is indeed less than 1, ensuring that the series converges. Hence, this means that the sum of the series does not stretch to infinity but resolves to a specific number, which helps in making the series manageable and calculable.
Sum of a Series
Once the convergence of a geometric series is established, we can compute its sum using a straightforward formula. For a convergent geometric series with a first term \( a \) and common ratio \( r \), the sum \( S_\infty \) can be calculated as:\[ S_\infty = \frac{a}{1 - r} \]This formula provides the means to find the total sum regardless of the infinite number of terms, as long as the series converges. Calculating the actual sum involves substituting the known values of \( a \) and \( r \) into the formula. In our exercise:
  • The first term \( a \) is \( \frac{1}{625} \) (found by setting \( k=4\) in the formula \( \frac{1}{5^{k}} \)).
  • The common ratio \( r \) is \( \frac{1}{5} \).
These values plugged into the sum formula yield \( S_\infty = \frac{1}{500} \), demonstrating how the series, despite being infinite, equates to a simple finite number.

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Most popular questions from this chapter

The expression $$1+\frac{1}{1+\frac{1}{1+\frac{1}{1+\frac{1}{1+}}}}.$$ where the process continues indefinitely, is called a continued fraction. a. Show that this expression can be built in steps using the recurrence relation \(a_{0}=1, a_{n+1}=1+1 / a_{n},\) for \(n=0,1,2,3, \ldots . .\) Explain why the value of the expression can be interpreted as \(\lim _{n \rightarrow \infty} a_{n},\) provided the limit exists. b. Evaluate the first five terms of the sequence \(\left\\{a_{n}\right\\}\). c. Using computation and/or graphing, estimate the limit of the sequence. d. Assuming the limit exists, use the method of Example 5 to determine the limit exactly. Compare your estimate with \((1+\sqrt{5}) / 2,\) a number known as the golden mean. e. Assuming the limit exists, use the same ideas to determine the value of $$a+\frac{b}{a+\frac{b}{a+\frac{b}{a+\frac{b}{a+}}}}$$ where \(a\) and \(b\) are positive real numbers.

Consider series \(S=\sum_{k=0}^{n} r^{k},\) where \(|r|<1\) and its sequence of partial sums \(S_{n}=\sum_{k=0}^{n} r^{k}\) a. Complete the following table showing the smallest value of \(n,\) calling it \(N(r),\) such that \(\left|S-S_{n}\right|<10^{-4},\) for various values of \(r .\) For example, with \(r=0.5\) and \(S=2,\) we find that \(\left|S-S_{13}\right|=1.2 \times 10^{-4}\) and \(\left|S-S_{14}\right|=6.1 \times 10^{-5}\) Therefore, \(N(0.5)=14\) $$\begin{array}{|c|c|c|c|c|c|c|c|c|c|} \hline r & -0.9 & -0.7 & -0.5 & -0.2 & 0 & 0.2 & 0.5 & 0.7 & 0.9 \\ \hline N(r) & & & & & & & 14 & & \\ \hline \end{array}$$ b. Make a graph of \(N(r)\) for the values of \(r\) in part (a). c. How does the rate of convergence of the geometric series depend on \(r ?\)

Consider the following situations that generate a sequence. a. Write out the first five terms of the sequence. b. Find an explicit formula for the terms of the sequence. c. Find a recurrence relation that generates the sequence. d. Using a calculator or a graphing utility, estimate the limit of the sequence or state that it does not exist. Radioactive decay A material transmutes \(50 \%\) of its mass to another element every 10 years due to radioactive decay. Let \(M_{n}\) be the mass of the radioactive material at the end of the \(n\) th decade, where the initial mass of the material is \(M_{0}=20 \mathrm{g}\)

Use Theorem 8.6 to find the limit of the following sequences or state that they diverge. $$\left\\{\frac{n^{10}}{\ln ^{20} n}\right\\}$$

In the following exercises, two sequences are given, one of which initially has smaller values, but eventually "overtakes" the other sequence. Find the sequence with the larger growth rate and the value of \(n\) at which it overtakes the other sequence. $$a_{n}=n^{10} \text { and } b_{n}=n^{9} \ln ^{3} n, n \geq 7$$

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