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Show that with the change of variables \(u=\sqrt{\tan x}\) the integral \(\int \sqrt{\tan x} d x\) can be converted to an integral amenable to partial fractions. Evaluate \(\int_{0}^{\pi / 4} \sqrt{\tan x} d x\)

Short Answer

Expert verified
Question: Evaluate the definite integral of the given expression from \(0\) to \(\pi/4\): \(\int \sqrt{\tan x} dx\) Answer: \(\frac{3}{5}\)

Step by step solution

01

Perform the change of variables

Let \(u = \sqrt{\tan x}\). We need to find a substitution for \(dx\) in terms of \(du\). To do this, first express \(\tan x\) in terms of \(u\). We have, $$ \tan x = u^2 $$ Now, differentiate both sides with respect to \(x\): $$ \frac{d}{d x}(\tan x) = \frac{d}{d x}(u^2) $$ Using chain rule and remembering \(\sec^2 x = \frac{d}{d x}(\tan x)\), $$ \sec^2 x dx = 2u \, du $$
02

Replace \(dx\) in terms of \(du\) in the integral

Now let's replace \(dx\) in the integral: $$ \int \sqrt{\tan x} dx = \int u \cdot \frac{\sec^2 x dx}{2u} $$ Cancelling \(u\) and factor 2: $$ \frac{1}{2}\int \sec^2 x \, du $$
03

Express \(\sec^2 x\) in terms of \(u\)

Recall that \(\sec^2 x = 1 + \tan^2 x\). We can rewrite this in terms of \(u\) as: $$ \sec^2 x = 1 + u^4 $$ Now, substitute this into the integral: $$ \frac{1}{2} \int (1 + u^4) du $$
04

Evaluate the integral

Integrating with respect to \(u\) gives: $$ \frac{1}{2} \int (1 + u^4) du = \frac{1}{2} (u + \frac{1}{5} u^5) + C = \frac{1}{2}(u + \frac{1}{5}u^5) + C $$ Now, substitute back \(u = \sqrt{\tan x}\) to get the result in terms of \(x\): $$ \frac{1}{2}(\sqrt{\tan x} + \frac{1}{5} (\tan x)^{\frac{5}{2}}) + C $$
05

Evaluate the definite integral

Finally, evaluate the definite integral from \(0\) to \(\pi/4\): $$ \int_{0}^{\pi / 4} \sqrt{\tan x} dx = \frac{1}{2}(\sqrt{\tan x} + \frac{1}{5} (\tan x)^{\frac{5}{2}}) \Big|_0^{\pi/4} $$ $$ =\frac{1}{2} [(\sqrt{\tan {\pi/4}} + \frac{1}{5} (\tan {\pi/4})^{\frac{5}{2}}) - (\sqrt{\tan 0} + \frac{1}{5} (\tan 0)^{\frac{5}{2}})] $$ As we know, \(\tan 0 = 0\) and \(\tan (\pi/4) = 1\). Therefore, $$ \int_{0}^{\pi / 4} \sqrt{\tan x} dx = \frac{1}{2} [(\sqrt{1} + \frac{1}{5} (1)^{\frac{5}{2}}) - (\sqrt{0} + \frac{1}{5} (0)^{\frac{5}{2}})] = \frac{1}{2}(1+\frac{1}{5}) = \frac{3}{5} $$ Thus, the value of the given integral from \(0\) to \(\pi/4\) is \(\frac{3}{5}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Change of Variables
The change of variables is a technique used in calculus to simplify integrals by substituting a part of the integrand (the expression inside the integral) with a new variable. This substitution transforms the integral into a form that's easier to solve. In this exercise, we use the substitution
  • Let: \( u = \sqrt{\tan x} \)
This substitution implies that \( \tan x \) can be expressed as \( u^2 \). By differentiating both sides, we find that
  • \( \sec^2 x \, dx = 2u \, du \)
The choice of substitution is often guided by the aim of simplifying the expression considerably. The key is to find a substitution where the new integral is easier to evaluate. Here, the change in variables transforms a complex trigonometric function into a simple polynomial expression imposed on integrals. This method is instrumental when dealing with integrals involving composite functions.
Partial Fractions
Partial fractions involve decomposing a complex rational function into a sum of simpler rational expressions. This method greatly aids in integrating functions that are difficult to handle. After changing variables in the original problem to \( u = \sqrt{\tan x} \), we arrive at an integral that lends itself well to partial fraction decomposition:
  • \( \frac{1}{2} \int (1 + u^4) \, du \)
Instead of tackling the entire complex fraction, the strategy here is to first break it down. Unfortunately, here it doesn't decompose further, but this is because the polynomial is already a straightforward form for integration. Essentials of this concept lie in the ability to recognize when a polynomial fraction can be expanded into simpler, more easily integrable parts. Overall, this approach makes calculus much more approachable, particularly in dealing with more involved expressions.
Definite Integrals
Definite integrals are a key tool used to calculate the accumulation of quantities, represented as the area under a curve between two specific points. In this exercise, we explore the definite integral
  • \( \int_{0}^{\pi / 4} \sqrt{\tan x} \, dx \)
After performing the change of variables and integrating the new expression, we substitute back to the original variable and evaluate at the bounds, resulting in:
  • \( \frac{3}{5} \)
The process involves substituting \( u = \sqrt{\tan x} \) and converting our bounds accordingly. Evaluating definite integrals often involves key calculus operations: substitution, differentiation, and simplification. This integral calculation understanding is crucial because it allows us to find exact values for areas or accumulations, providing precise results which are essential in different applied sciences and engineering tasks.

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Most popular questions from this chapter

\(A\) powerful tool in solving problems in engineering and physics is the Laplace transform. Given a function \(f(t)\) the Laplace transform is a new function \(F(s)\) defined by $$F(s)=\int_{0}^{\infty} e^{-s t} f(t) d t$$ where we assume that \(s\) is a positive real number. For example, to find the Laplace transform of \(f(t)=e^{-t},\) the following improper integral is evaluated: $$F(s)=\int_{0}^{\infty} e^{-s t} e^{-t} d t=\int_{0}^{\infty} e^{-(s+1) t} d t=\frac{1}{s+1}$$ Verify the following Laplace transforms, where a is a real number. $$f(t)=e^{a t} \longrightarrow F(s)=\frac{1}{s-a}$$

Use the reduction formulas in a table of integrals to evaluate the following integrals. $$\int p^{2} e^{-3 p} d p$$

An object in free fall may be modeled by assuming that the only forces at work are the gravitational force and resistance (friction due to the medium in which the object falls). By Newton's second law (mass \(\times\) acceleration \(=\) the sum of the external forces), the velocity of the object satisfies the differential equation $$m \quad \cdot \quad v^{\prime}(t)=m g+f(v)$$, where \(f\) is a function that models the resistance and the positive direction is downward. One common assumption (often used for motion in air) is that \(f(v)=-k v^{2},\) where \(k>0\) is a drag coefficient. a. Show that the equation can be written in the form \(v^{\prime}(t)=\) \(g-a v^{2},\) where \(a=k / m\). b. For what (positive) value of \(v\) is \(v^{\prime}(t)=0 ?\) (This equilibrium solution is called the terminal velocity.) c. Find the solution of this separable equation assuming \(v(0)=0\) and \(0

\(A\) powerful tool in solving problems in engineering and physics is the Laplace transform. Given a function \(f(t)\) the Laplace transform is a new function \(F(s)\) defined by $$F(s)=\int_{0}^{\infty} e^{-s t} f(t) d t$$ where we assume that \(s\) is a positive real number. For example, to find the Laplace transform of \(f(t)=e^{-t},\) the following improper integral is evaluated: $$F(s)=\int_{0}^{\infty} e^{-s t} e^{-t} d t=\int_{0}^{\infty} e^{-(s+1) t} d t=\frac{1}{s+1}$$ Verify the following Laplace transforms, where a is a real number. $$f(t)=\cos a t \longrightarrow F(s)=\frac{s}{s^{2}+a^{2}}$$

Graph the integrands and then evaluate and compare the values of \(\int_{0}^{\infty} x e^{-x^{2}} d x\) and \(\int_{0}^{\infty} x^{2} e^{-x^{2}} d x\).

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