Chapter 7: Problem 98
Show that with the change of variables \(u=\sqrt{\tan x}\) the integral \(\int \sqrt{\tan x} d x\) can be converted to an integral amenable to partial fractions. Evaluate \(\int_{0}^{\pi / 4} \sqrt{\tan x} d x\)
Short Answer
Expert verified
Question: Evaluate the definite integral of the given expression from \(0\) to \(\pi/4\): \(\int \sqrt{\tan x} dx\)
Answer: \(\frac{3}{5}\)
Step by step solution
01
Perform the change of variables
Let \(u = \sqrt{\tan x}\). We need to find a substitution for \(dx\) in terms of \(du\). To do this, first express \(\tan x\) in terms of \(u\). We have,
$$
\tan x = u^2
$$
Now, differentiate both sides with respect to \(x\):
$$
\frac{d}{d x}(\tan x) = \frac{d}{d x}(u^2)
$$
Using chain rule and remembering \(\sec^2 x = \frac{d}{d x}(\tan x)\),
$$
\sec^2 x dx = 2u \, du
$$
02
Replace \(dx\) in terms of \(du\) in the integral
Now let's replace \(dx\) in the integral:
$$
\int \sqrt{\tan x} dx = \int u \cdot \frac{\sec^2 x dx}{2u}
$$
Cancelling \(u\) and factor 2:
$$
\frac{1}{2}\int \sec^2 x \, du
$$
03
Express \(\sec^2 x\) in terms of \(u\)
Recall that \(\sec^2 x = 1 + \tan^2 x\). We can rewrite this in terms of \(u\) as:
$$
\sec^2 x = 1 + u^4
$$
Now, substitute this into the integral:
$$
\frac{1}{2} \int (1 + u^4) du
$$
04
Evaluate the integral
Integrating with respect to \(u\) gives:
$$
\frac{1}{2} \int (1 + u^4) du = \frac{1}{2} (u + \frac{1}{5} u^5) + C = \frac{1}{2}(u + \frac{1}{5}u^5) + C
$$
Now, substitute back \(u = \sqrt{\tan x}\) to get the result in terms of \(x\):
$$
\frac{1}{2}(\sqrt{\tan x} + \frac{1}{5} (\tan x)^{\frac{5}{2}}) + C
$$
05
Evaluate the definite integral
Finally, evaluate the definite integral from \(0\) to \(\pi/4\):
$$
\int_{0}^{\pi / 4} \sqrt{\tan x} dx = \frac{1}{2}(\sqrt{\tan x} + \frac{1}{5} (\tan x)^{\frac{5}{2}}) \Big|_0^{\pi/4}
$$
$$
=\frac{1}{2} [(\sqrt{\tan {\pi/4}} + \frac{1}{5} (\tan {\pi/4})^{\frac{5}{2}}) - (\sqrt{\tan 0} + \frac{1}{5} (\tan 0)^{\frac{5}{2}})]
$$
As we know, \(\tan 0 = 0\) and \(\tan (\pi/4) = 1\). Therefore,
$$
\int_{0}^{\pi / 4} \sqrt{\tan x} dx = \frac{1}{2} [(\sqrt{1} + \frac{1}{5} (1)^{\frac{5}{2}}) - (\sqrt{0} + \frac{1}{5} (0)^{\frac{5}{2}})] = \frac{1}{2}(1+\frac{1}{5}) = \frac{3}{5}
$$
Thus, the value of the given integral from \(0\) to \(\pi/4\) is \(\frac{3}{5}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Change of Variables
The change of variables is a technique used in calculus to simplify integrals by substituting a part of the integrand (the expression inside the integral) with a new variable. This substitution transforms the integral into a form that's easier to solve. In this exercise, we use the substitution
- Let: \( u = \sqrt{\tan x} \)
- \( \sec^2 x \, dx = 2u \, du \)
Partial Fractions
Partial fractions involve decomposing a complex rational function into a sum of simpler rational expressions. This method greatly aids in integrating functions that are difficult to handle. After changing variables in the original problem to \( u = \sqrt{\tan x} \), we arrive at an integral that lends itself well to partial fraction decomposition:
- \( \frac{1}{2} \int (1 + u^4) \, du \)
Definite Integrals
Definite integrals are a key tool used to calculate the accumulation of quantities, represented as the area under a curve between two specific points. In this exercise, we explore the definite integral
- \( \int_{0}^{\pi / 4} \sqrt{\tan x} \, dx \)
- \( \frac{3}{5} \)