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Evaluate \(\int \cos \sqrt{x} d x\) using a substitution followed by integration by parts.

Short Answer

Expert verified
The indefinite integral of cos(√x) with respect to x is 2√x sin(√x) + 2cos(√x) + C, where C is the constant of integration.

Step by step solution

01

Apply a substitution

To simplify the function, let us perform the following substitution: \(u = \sqrt{x}\). Now, differentiate both sides with respect to \(x\) to obtain the derivative of \(u\) with respect to \(x\): \(du/dx = \frac{1}{2\sqrt{x}}\) Now, solve for \(dx\): \(dx = 2\sqrt{x}du = 2u du\) Now, replace \(\sqrt{x}\) with \(u\) and \(dx\) with \(2u du\) in the integral: \(\int \cos(\sqrt{x})dx = \int \cos(u) (2u du)\)
02

Apply integration by parts

To evaluate this, we now apply integration by parts. Recall that integration by parts is given by the formula: \(\int u dv = uv - \int v du\) Choose \(u = 2u\) and \(dv = \cos(u) du\). Differentiate \(u\) with respect to \(u\) to obtain \(du\): \(du = 2 du\) Now, integrate \(dv\) with respect to \(u\) to obtain \(v\): \(v = \int \cos(u) du = \sin(u)\) Using these functions, we can now apply integration by parts: \(\int \cos(u)(2u du) = 2u\sin(u) - \int \sin(u)(2du)\)
03

Evaluate the remaining integral

Integrate the remaining integral: \(\int \sin(u)(2du) = 2\int \sin(u) du\) \(= -2\cos(u) + C\) Now we have: \(\int \cos(u)(2u du) = 2u\sin(u) - (-2\cos(u) + C)\)
04

Reverse the substitution

Finally, reverse the substitution by replacing \(u\) with \(\sqrt{x}\): \(\int \cos(\sqrt{x}) dx = 2\sqrt{x}\sin(\sqrt{x}) + 2\cos(\sqrt{x}) + C\) This is the final result of the integral: \(\int \cos(\sqrt{x}) dx = 2\sqrt{x}\sin(\sqrt{x}) + 2\cos(\sqrt{x}) + C\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Substitution Method
The substitution method is a powerful tool for solving integrals that may not be straightforward at first glance. By changing difficult expressions into more manageable forms, this method simplifies the integration process. Consider the function you're integrating as a complex machine. To understand it, you might want to break it into smaller, easier-to-understand parts. That's what substitution does; it acts as a translator, turning a complex expression into something familiar.

For instance, in the example given, we are faced with integrating \( \cos \sqrt{x} \). Direct integration looks challenging, but with substitution, it becomes manageable. We let \( u = \sqrt{x} \) and translate every piece of our integral in terms of \( u \) and \( du \), streamlining the integral into a friendlier form. This step is crucial because it sets the stage for applying other integration techniques, like integration by parts. Remember, choosing the right substitution can make or break your integral solution, so this step requires careful thinking and practice.
Integration by Parts
Once you simplify an integral using the substitution method, you might still encounter a product of functions that's tricky to integrate. This is where integration by parts comes into play. Imagine you are trying to untangle a knot; integration by parts helps you to carefully separate the pieces to make the problem easier to handle.

The technique is based on the product rule for differentiation and is encapsulated in the formula \( \int u dv = uv - \int v du \). By selecting \( u \) and \( dv \) wisely, we can transform our integral into a simpler form, or sometimes, into a form we recognize and can integrate directly. In our example, we let \( u = 2u \) (with \( du = 2 du \)) and \( dv = \cos(u) du \) (with \( v = \sin(u) \) upon integrating \( dv \) ). Applying the formula, we can break down the complex integral into smaller, more manageable parts. Integration by parts often requires iteration and may produce integrals that are solved using other methods, including the substitution method itself.
Indefinite Integrals
Indefinite integrals represent families of functions with an added constant \( C \), known as the constant of integration. Think of indefinite integrals as the quest to find the original function, given its rate of change. They are like archaeologists piecing together fragments to reveal a complete pot. These integrals do not have limits of integration, hence the name 'indefinite'.

For the integral \( \int \cos(\sqrt{x}) dx \), after using substitution and integration by parts, we are left with \( 2\sqrt{x}\sin(\sqrt{x}) + 2\cos(\sqrt{x}) + C \). This result represents a family of functions. The \( + C \) indicates that there are potentially infinitely many functions that, once differentiated, would result in \( \cos(\sqrt{x}) \). Including \( C \) is important because it accounts for the unknown initial value of the function we're integrating. When working with indefinite integrals, always remember to add the \( + C \), as it acknowledges all possible antiderivatives of the given function.

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Most popular questions from this chapter

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