/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 Evaluate the following integrals... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the following integrals or state that they diverge. $$\int_{2}^{\infty} \frac{d x}{(x+2)^{2}}$$

Short Answer

Expert verified
$$\int_{2}^{\infty} \frac{d x}{(x+2)^{2}}$$ Answer: The improper integral converges, and its value is $\frac{1}{4}$.

Step by step solution

01

Identify the given integral as an improper integral

We are given the improper integral: $$\int_{2}^{\infty} \frac{d x}{(x+2)^{2}}$$ Notice that the upper limit of integration is infinity, which signals an improper integral.
02

Rewrite the integral as a limit

Since the integral has infinity as an upper limit, we must rewrite it as a limit to properly evaluate its convergence or divergence: $$\lim_{b \to \infty} \int_{2}^{b} \frac{d x}{(x+2)^{2}}$$
03

Evaluate the antiderivative

We are now going to find the antiderivative of the given integrand, which is: $$\frac{d x}{(x+2)^{2}}$$ Using substitution, let \(u = x + 2\). So, \(\frac{d u}{d x} = 1\) and \(d x = d u\). Now we have: $$\int \frac{d u}{u^2}$$ This is an elementary integral which can be evaluated as follows: $$\int \frac{d u}{u^2} = -\frac{1}{u} + C = -\frac{1}{x + 2} + C$$
04

Apply the Fundamental Theorem of Calculus and take the limit

Now we will apply the Fundamental Theorem of Calculus to evaluate the definite integral and take the limit as the upper limit approaches infinity: $$\lim_{b \to \infty} \left[-\frac{1}{b + 2} - \left(-\frac{1}{2 + 2}\right)\right]$$
05

Evaluate the limit

We will now evaluate the limit: $$\lim_{b \to \infty} \left[-\frac{1}{b + 2} + \frac{1}{4}\right]$$ Since as \(b\) approaches infinity, the first term in the expression goes to zero, we have: $$\lim_{b \to \infty} \left[-\frac{1}{b + 2} + \frac{1}{4}\right] = 0 + \frac{1}{4} = \frac{1}{4}$$ As the limit exists and is finite, the integral converges. Therefore, the value of the integral is: $$\int_{2}^{\infty} \frac{d x}{(x+2)^{2}} = \frac{1}{4}$$

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