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Evaluate the following integrals. $$\int x \sin x \cos x d x$$

Short Answer

Expert verified
Question: Evaluate the integral of the product of x, sin(x), and cos(x). Answer: The integral is given by: ∫x sin(x) cos(x) dx = (1/2)x sin^2(x) - (1/4)x + (1/8)sin(2x) + C.

Step by step solution

01

Identify u and dv

In integration by parts, we need to identify the two functions, u and dv: Let u = x, then du = dx Let dv = sin(x) cos(x) dx Step 2: Integrate dv to find v
02

Integrate dv

To find v, integrate sin(x) cos(x) dx. We will use a substitution method: Let y = sin(x), then dy = cos(x) dx So, the integral becomes ∫y dy, which equals (1/2)y^2 + C. Now, substitute back sin(x) for y: v = (1/2)sin^2(x) Step 3: Apply integration by parts formula
03

Integration by Parts

Using the integration by parts formula, ∫u dv = u v - ∫v du In our case, it will look like this: ∫x sin(x) cos(x) dx = x (1/2)sin^2(x) - ∫(1/2)sin^2(x) dx Step 4: Simplify and use a trigonometric identity
04

Simplify the integral

Now, let's simplify the integral and use the identity sin^2(x) = (1 - cos(2x))/2: ∫x sin(x) cos(x) dx = (1/2)x sin^2(x) - (1/4)∫(1 - cos(2x)) dx Step 5: Integrate the remaining integral
05

Integration of remaining terms

Now, let's integrate ∫(1 - cos(2x)) dx term by term: ∫(1 - cos(2x)) dx = x - (1/2)∫cos(2x) dx To find the integral of cos(2x) dx, use substitution: Let t = 2x, then (1/2)dt = dx So, the integral becomes (1/2)∫cos(t) dt, which equals (1/2)sin(t) + C. Now, substitute back 2x for t: (1/2)sin(2x) + C Now, substitute this back to the main equation: ∫x sin(x) cos(x) dx = (1/2)x sin^2(x) - (1/4)(x - (1/2)sin(2x)) + C Step 6: Simplify the final result
06

Simplify the final result

Now, combine all terms and simplify to get the final result: ∫x sin(x) cos(x) dx = (1/2)x sin^2(x) - (1/4)x + (1/8)sin(2x) + C

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometric Integration
Trigonometric integration is all about finding the integral of functions that involve trigonometric components like sine, cosine, tangent, and their multiples or powers. These integrals can vary from straightforward to quite complex. For the integral \( \int x \sin x \cos x \, dx \), trigonometric identities simplify the process.

When dealing with trigonometric integrals, recognize if a substitution or identity can aid in simplification. For example, using the identity \( \sin^2(x) = \frac{1 - \cos(2x)}{2} \) can transform expressions and make integration more manageable. Additionally, breaking down complex products into simpler trigonometric components can be crucial for evaluating the integral effectively.

Understanding these identities and how to apply them is a key component of mastering trigonometric integration problems.
Substitution Method
The substitution method is highly valuable in integration, especially when dealing with composite functions. This method changes the variables to simplify the integral.

In the problem \( \int x \sin x \cos x \, dx \), substitution simplifies parts of the expression that seem complex at first glance. For example, filling in \( y = \sin(x) \) turns the product \( \cos(x) \, dx \) into a differential form \( dy \), which is much easier to integrate.

The substitution method is often paired with recognizing derivatives within the integral that matches part of the integral to aid simplification. This technique reduces the complexity of solving integrals, making them more straightforward to evaluate.
  • Identify what function to substitute, commonly aiming for simpler integration.
  • Ensure all parts of the integral align thanks to the substitution.
  • Simultaneously solve for the new differential.
These steps can effectively transform and simplify complex integrals.
Definite Integral Evaluation
Definite integrals calculate the area under the curve of a function within a specified interval. Although not directly applied in the initial step-by-step solution of \( \int x \sin x \cos x \, dx \), understanding definite integrals is essential for complete mastery of the topic.

To evaluate a definite integral, such as \( \int_{a}^{b} f(x) \, dx \):
  • Find the antiderivative \( F(x) \) of the function \( f(x) \).
  • Compute \( F(b) - F(a) \), where \( a \) and \( b \) are the bounds.
  • This result gives the exact area under \( f(x) \) between x \( a \) and x \( b \).
If you have functions involving trigonometric identities and substitutions, it often involves simplifying the expression before taking the antiderivative. These integral properties make them a powerful tool for calculating exact areas and understanding the behavior of functions over intervals.

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Most popular questions from this chapter

Another Simpson's Rule formula is \(S(2 n)=\frac{2 M(n)+T(n)}{3},\) for \(n \geq 1 .\) Use this rule to estimate \(\int_{1}^{e} 1 / x d x\) using \(n=10\) subintervals.

The nucleus of an atom is positively charged because it consists of positively charged protons and uncharged neutrons. To bring a free proton toward a nucleus, a repulsive force \(F(r)=k q Q / r^{2}\) must be overcome, where \(q=1.6 \times 10^{-19} \mathrm{C}\) (coulombs) is the charge on the proton, \(k=9 \times 10^{9} \mathrm{N}-\mathrm{m}^{2} / \mathrm{C}^{2}, Q\) is the charge on the nucleus, and \(r\) is the distance between the center of the nucleus and the proton. Find the work required to bring a free proton (assumed to be a point mass) from a large distance \((r \rightarrow \infty)\) to the edge of a nucleus that has a charge \(Q=50 q\) and a radius of \(6 \times 10^{-11} \mathrm{m}\)

Consider the logistic equation $$P^{\prime}(t)=0.1 P\left(1-\frac{P}{300}\right), \text { for } t \geq 0$$, with \(P(0)>0 .\) Show that the solution curve is concave down for \(150300\).

Use numerical methods or a calculator to approximate the following integrals as closely as possible. The exact value of each integral is given. $$\int_{0}^{\pi / 2} \ln (\sin x) d x=\int_{0}^{\pi / 2} \ln (\cos x) d x=-\frac{\pi \ln 2}{2}$$

Compare the errors in the Midpoint and Trapezoid Rules with \(n=4,8,16,\) and 32 subintervals when they are applied to the following integrals (with their exact values given). \(\int_{0}^{\pi / 2} \cos ^{9} x d x=\frac{128}{315}\)

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