/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 Evaluate the following integrals... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Evaluate the following integrals. $$\int x \sin x \cos x d x$$

Short Answer

Expert verified
Question: Evaluate the integral of the product of x, sin(x), and cos(x). Answer: The integral is given by: ∫x sin(x) cos(x) dx = (1/2)x sin^2(x) - (1/4)x + (1/8)sin(2x) + C.

Step by step solution

01

Identify u and dv

In integration by parts, we need to identify the two functions, u and dv: Let u = x, then du = dx Let dv = sin(x) cos(x) dx Step 2: Integrate dv to find v
02

Integrate dv

To find v, integrate sin(x) cos(x) dx. We will use a substitution method: Let y = sin(x), then dy = cos(x) dx So, the integral becomes ∫y dy, which equals (1/2)y^2 + C. Now, substitute back sin(x) for y: v = (1/2)sin^2(x) Step 3: Apply integration by parts formula
03

Integration by Parts

Using the integration by parts formula, ∫u dv = u v - ∫v du In our case, it will look like this: ∫x sin(x) cos(x) dx = x (1/2)sin^2(x) - ∫(1/2)sin^2(x) dx Step 4: Simplify and use a trigonometric identity
04

Simplify the integral

Now, let's simplify the integral and use the identity sin^2(x) = (1 - cos(2x))/2: ∫x sin(x) cos(x) dx = (1/2)x sin^2(x) - (1/4)∫(1 - cos(2x)) dx Step 5: Integrate the remaining integral
05

Integration of remaining terms

Now, let's integrate ∫(1 - cos(2x)) dx term by term: ∫(1 - cos(2x)) dx = x - (1/2)∫cos(2x) dx To find the integral of cos(2x) dx, use substitution: Let t = 2x, then (1/2)dt = dx So, the integral becomes (1/2)∫cos(t) dt, which equals (1/2)sin(t) + C. Now, substitute back 2x for t: (1/2)sin(2x) + C Now, substitute this back to the main equation: ∫x sin(x) cos(x) dx = (1/2)x sin^2(x) - (1/4)(x - (1/2)sin(2x)) + C Step 6: Simplify the final result
06

Simplify the final result

Now, combine all terms and simplify to get the final result: ∫x sin(x) cos(x) dx = (1/2)x sin^2(x) - (1/4)x + (1/8)sin(2x) + C

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometric Integration
Trigonometric integration is all about finding the integral of functions that involve trigonometric components like sine, cosine, tangent, and their multiples or powers. These integrals can vary from straightforward to quite complex. For the integral \( \int x \sin x \cos x \, dx \), trigonometric identities simplify the process.

When dealing with trigonometric integrals, recognize if a substitution or identity can aid in simplification. For example, using the identity \( \sin^2(x) = \frac{1 - \cos(2x)}{2} \) can transform expressions and make integration more manageable. Additionally, breaking down complex products into simpler trigonometric components can be crucial for evaluating the integral effectively.

Understanding these identities and how to apply them is a key component of mastering trigonometric integration problems.
Substitution Method
The substitution method is highly valuable in integration, especially when dealing with composite functions. This method changes the variables to simplify the integral.

In the problem \( \int x \sin x \cos x \, dx \), substitution simplifies parts of the expression that seem complex at first glance. For example, filling in \( y = \sin(x) \) turns the product \( \cos(x) \, dx \) into a differential form \( dy \), which is much easier to integrate.

The substitution method is often paired with recognizing derivatives within the integral that matches part of the integral to aid simplification. This technique reduces the complexity of solving integrals, making them more straightforward to evaluate.
  • Identify what function to substitute, commonly aiming for simpler integration.
  • Ensure all parts of the integral align thanks to the substitution.
  • Simultaneously solve for the new differential.
These steps can effectively transform and simplify complex integrals.
Definite Integral Evaluation
Definite integrals calculate the area under the curve of a function within a specified interval. Although not directly applied in the initial step-by-step solution of \( \int x \sin x \cos x \, dx \), understanding definite integrals is essential for complete mastery of the topic.

To evaluate a definite integral, such as \( \int_{a}^{b} f(x) \, dx \):
  • Find the antiderivative \( F(x) \) of the function \( f(x) \).
  • Compute \( F(b) - F(a) \), where \( a \) and \( b \) are the bounds.
  • This result gives the exact area under \( f(x) \) between x \( a \) and x \( b \).
If you have functions involving trigonometric identities and substitutions, it often involves simplifying the expression before taking the antiderivative. These integral properties make them a powerful tool for calculating exact areas and understanding the behavior of functions over intervals.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Determine whether the following statements are true and give an explanation or counterexample. a. The Trapezoid Rule is exact when used to approximate the definite integral of a linear function. b. If the number of subintervals used in the Midpoint Rule is increased by a factor of \(3,\) the error is expected to decrease by a factor of 8. c. If the number of subintervals used in the Trapezoid Rule is increased by a factor of \(4,\) the error is expected to decrease by a factor of 16.

Hourly temperature data for Boulder, Colorado, San Francisco, California, Nantucket, Massachusetts, and Duluth, Minnesota, over a 12 hr period on the same day of January are shown in the figure. Assume that these data are taken from a continuous temperature function \(T(t) .\) The average temperature over the 12 -hr period is \(\bar{T}=\frac{1}{12} \int_{0}^{12} T(t) d t\). Find an accurate approximation to the average temperature over the 12 -hr period for San Francisco. State your method.

Skydiving A skydiver in free fall subject to gravitational acceleration and air resistance has a velocity given by \(v(t)=v_{T}\left(\frac{e^{a t}-1}{e^{a t}+1}\right),\) where \(v_{T}\) is the terminal velocity and \(a>0\) is a physical constant. Find the distance that the skydiver falls after \(t\) seconds, which is \(d(t)=\int_{0}^{t} v(y) d y.\)

Compare the errors in the Midpoint and Trapezoid Rules with \(n=4,8,16,\) and 32 subintervals when they are applied to the following integrals (with their exact values given). \(\int_{0}^{\pi} \ln (5+3 \cos x) d x=\pi \ln \frac{9}{2}\)

The work required to launch an object from the surface of Earth to outer space is given by \(W=\int_{R}^{\infty} F(x) d x,\) where \(R=6370 \mathrm{km}\) is the approximate radius of Earth, \(F(x)=G M m / x^{2}\) is the gravitational force between Earth and the object, \(G\) is the gravitational constant, \(M\) is the mass of Earth, \(m\) is the mass of the object, and \(G M=4 \times 10^{14} \mathrm{m}^{3} / \mathrm{s}^{2}\) a. Find the work required to launch an object in terms of \(m\) b. What escape velocity \(v_{e}\) is required to give the object a kinetic energy \(\frac{1}{2} m v_{e}^{2}\) equal to \(W ?\) c. The French scientist Laplace anticipated the existence of black holes in the 18 th century with the following argument: If a body has an escape velocity that equals or exceeds the speed of light, \(c=300,000 \mathrm{km} / \mathrm{s},\) then light cannot escape the body and it cannot be seen. Show that such a body has a radius \(R \leq 2 G M / c^{2}\). For Earth to be a black hole, what would its radius need to be?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.