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State the three Pythagorean identities.

Short Answer

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Answer: The three Pythagorean identities are: 1. \((\sin{\theta})^2 + (\cos{\theta})^2 = 1\), derived from the Pythagorean theorem applied to a right triangle with a hypotenuse of length 1. 2. \((\tan{\theta})^2 + 1 = (\sec{\theta})^2\), derived by dividing both sides of the first identity by \((\cos{\theta})^2\). 3. \(1 + (\cot{\theta})^2 = (\csc{\theta})^2\), derived by dividing both sides of the first identity by \((\sin{\theta})^2\). These identities are trigonometric relationships based on the Pythagorean theorem and are true for any angle in a right triangle.

Step by step solution

01

Pythagorean Identity 1 (Sine & Cosine)

The first Pythagorean identity is derived from the Pythagorean theorem applied to a right triangle with a hypotenuse of length 1. In this case, the theorem states that the sum of the squares of the lengths of the legs is equal to the square of the length of the hypotenuse, i.e., \((\sin{\theta})^2 + (\cos{\theta})^2 = 1\). This identity is true for any angle \(\theta\).
02

Pythagorean Identity 2 (Tangent & Secant)

The second Pythagorean identity is derived from the first identity. By dividing both sides of the first identity by \((\cos{\theta})^2\), we get the following identity: \[\frac{(\sin{\theta})^2}{(\cos{\theta})^2} + \frac{(\cos{\theta})^2}{(\cos{\theta})^2} = \frac{1}{(\cos{\theta})^2}.\] Since \(\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}\) and \(\sec{\theta} = \frac{1}{\cos{\theta}}\), we can rewrite the above equation as \((\tan{\theta})^2 + 1 = (\sec{\theta})^2\). This identity is also true for any angle \(\theta\).
03

Pythagorean Identity 3 (Cotangent & Cosecant)

The third Pythagorean identity is derived by dividing both sides of the first identity by \((\sin{\theta})^2\). In this case, we get the following identity: \[\frac{(\sin{\theta})^2}{(\sin{\theta})^2} + \frac{(\cos{\theta})^2}{(\sin{\theta})^2} = \frac{1}{(\sin{\theta})^2}.\] Since \(\cot{\theta} = \frac{\cos{\theta}}{\sin{\theta}}\) and \(\csc{\theta} = \frac{1}{\sin{\theta}}\), we can rewrite the above equation, obtaining \(1 + (\cot{\theta})^2 = (\csc{\theta})^2\). This identity is true for any angle \(\theta\). So the three Pythagorean identities are: 1. \((\sin{\theta})^2 + (\cos{\theta})^2 = 1\) 2. \((\tan{\theta})^2 + 1 = (\sec{\theta})^2\) 3. \(1 + (\cot{\theta})^2 = (\csc{\theta})^2\)

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