/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 Use a table of integrals to dete... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use a table of integrals to determine the following indefinite integrals. $$\int \frac{d x}{1-\cos 4 x}$$

Short Answer

Expert verified
Question: Find the indefinite integral of the given function: $$\int \frac{dx}{1-\cos 4x}$$ Answer: $$\int \frac{dx}{1-\cos 4x} = -\cot(2x) + C$$

Step by step solution

01

Write down integral using a trigonometric identity

For a start, let's rewrite the given integral using the trigonometric identity mentioned in the analysis. By doing so, we obtain: $$\int \frac{dx}{1-\cos 4x} = 2 \int\frac{dx}{2\sin^2 2x}$$
02

Substitute and use the integration table

Now we will substitute \(u = 2x\), and we get: $$2 \int\frac{dx}{2\sin^2 2x} = \int\frac{du}{\sin^2 u}$$ Using the integration table, we find that the integral of \(\csc^2 x\) with respect to \(x\) is equal to \(- \cot x + C\).
03

Substitute back and find the indefinite integral

Now that we have found the integral with respect to \(u\), we can substitute back and find the original indefinite integral. $$\int\frac{du}{\sin^2 u} = -\cot u + C = -\cot(2x) + C$$ So, the indefinite integral is given by: $$\int \frac{dx}{1-\cos 4x} = -\cot(2x) + C$$

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometric Identities
Trigonometric identities are mathematical equations that express one trigonometric function in terms of others. They are pivotal in simplifying and solving integrals involving trigonometric functions. In this exercise, we used the identity involving sine and cosine, specifically:
  • The double angle identity for sine: \[1 - \cos 4x = 2\sin^2 2x\]
This identity allows us to convert the expression \(1 - \cos 4x\) into a term involving \(\sin\), which is much simpler to integrate.
By rewriting the integral in this way, we break down a complex expression into a more manageable form. Understanding and applying these identities are essential skills for manipulating trigonometric integrals effectively. Integrals that seem complex at first sight often have simpler forms with the right identity.
Substitution Method
The substitution method is a technique used to simplify integrals. It involves changing variables to transform a difficult integral into one that is easier to solve. In our exercise, we used the substitution method as follows:
  • We substituted \(u = 2x\), thus \(du = 2dx\). Solving for \(dx = \frac{du}{2}\) then allows us to substitute in the integral.
The substitution transforms the integral into a new form: \[2 \int \frac{dx}{2\sin^2 2x} = \int \frac{du}{\sin^2 u}\]
By breaking it down, the substitution method helps reduce the complexity. This step is crucial because it often turns an integral into a standard form that we can then solve using known integral tables or rules.
It’s a powerful tool for situations where direct integration is complex or impossible, converting variable expressions into more manageable equivalents.
Integration Table
An integration table is a collection of formulas used to find the antiderivatives of various functions. It empowers you to quickly solve integrals without re-deriving integral formulas. In the given problem, after substitution, the resulting integral was:
  • \(\int \frac{du}{\sin^2 u}\)
By referring to an integration table, we identify this integral as the derivative of the cosecant function, specifically:\[\int \csc^2 u \, du = -\cot u + C\]
Integration tables are essential for calculus students because they save time and effort. Instead of working out every integral from scratch, you can apply these pre-established results to solve problems more efficiently. It's important to become familiar with the functions in an integration table and understand how and when to use them correctly.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use the window \([-2,2] \times[-2,2]\) to sketch a direction field for the following equations. Then sketch the solution curve that corresponds to the given initial condition. $$y^{\prime}(t)=\sin y, y(-2)=\frac{1}{2}$$

A differential equation of the form \(y^{\prime}(t)=F(y)\) is said to be autonomous (the function \(F\) depends only on \(y\) ). The constant function \(y=y_{0}\) is an equilibrium solution of the equation provided \(F\left(y_{0}\right)=0\) (because then \(y^{\prime}(t)=0,\) and the solution remains constant for all \(t\) ). Note that equilibrium solutions correspond to horizontal line segments in the direction field. Note also that for autonomous equations, the direction field is independent of \(t\). Consider the following equations. a. Find all equilibrium solutions. b. Sketch the direction field on either side of the equilibrium solutions for \(t \geq 0\). c. Sketch the solution curve that corresponds to the initial condition \(y(0)=1\). $$y^{\prime}(t)=y(y-3)$$

Suppose that the rate at which a company extracts oil is given by \(r(t)=r_{0} e^{-k t},\) where \(r_{0}=10^{7}\) barrels \(/ \mathrm{yr}\) and \(k=0.005 \mathrm{yr}^{-1} .\) Suppose also the estimate of the total oil reserve is \(2 \times 10^{9}\) barrels. If the extraction continues indefinitely, will the reserve be exhausted?

Another Simpson's Rule formula is \(S(2 n)=\frac{2 M(n)+T(n)}{3},\) for \(n \geq 1 .\) Use this rule to estimate \(\int_{1}^{e} 1 / x d x\) using \(n=10\) subintervals.

Imagine that today you deposit \(\$ B\) in a savings account that earns interest at a rate of \(p \%\) per year compounded continuously (Section 6.9). The goal is to draw an income of \(\$ I\) per year from the account forever. The amount of money that must be deposited is \(B=I \int_{0}^{\infty} e^{-n} d t,\) where \(r=p / 100 .\) Suppose you find an account that earns \(12 \%\) interest annually and you wish to have an income from the account of \(\$ 5000\) per year. How much must you deposit today?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.