Chapter 6: Problem 6
Why is integration used to find the total force on the face of a dam?
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Chapter 6: Problem 6
Why is integration used to find the total force on the face of a dam?
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a. The definition of the inverse hyperbolic cosine is \(y=\cosh ^{-1} x \Leftrightarrow x=\cosh y,\) for \(x \geq 1,0 \leq y<\infty.\) Use implicit differentiation to show that \(\frac{d}{d x}\left(\cosh ^{-1} x\right)=\) \(1 / \sqrt{x^{2}-1}.\) b. Differentiate \(\sinh ^{-1} x=\ln (x+\sqrt{x^{2}+1})\) to show that \(\frac{d}{d x}\left(\sinh ^{-1} x\right)=1 / \sqrt{x^{2}+1}.\)
Find the volume of the solid generated in the following situations. The region \(R\) is bounded by the graph of \(f(x)=2 x(2-x)\) and the \(x\) -axis. Which is greater, the volume of the solid generated when \(R\) is revolved about the line \(y=2\) or the volume of the solid generated when \(R\) is revolved about the line \(y=0 ?\) Use integration to justify your answer.
A large tank has a plastic window on one wall that is designed to withstand a force of 90,000 N. The square window is \(2 \mathrm{m}\) on a side, and its lower edge is \(1 \mathrm{m}\) from the bottom of the tank. a. If the tank is filled to a depth of \(4 \mathrm{m},\) will the window withstand the resulting force? b. What is the maximum depth to which the tank can be filled without the window failing?
Miscellaneous integrals Evaluate the following integrals. \(\int_{0}^{1} \frac{16^{x}}{4^{2 x}} d x\)
Find the volume of the solid generated in the following situations. The region \(R\) bounded by the graphs of \(y=\sin x\) and \(y=1-\sin x\) on \(\left[\frac{\pi}{6}, \frac{5 \pi}{6}\right]\) is revolved about the line \(y=-1\).
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