Chapter 6: Problem 5
Why is integration used to find the work required to pump water out of a tank?
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Chapter 6: Problem 5
Why is integration used to find the work required to pump water out of a tank?
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Find the critical points of the function \(f(x)=\sinh ^{2} x \cosh x.\)
Find the volume of the solid generated in the following situations. The region \(R\) bounded by the graphs of \(y=\sin x\) and \(y=1-\sin x\) on \(\left[\frac{\pi}{6}, \frac{5 \pi}{6}\right]\) is revolved about the line \(y=-1\).
Archimedes' principle says that the buoyant force exerted on an object that is
(partially or totally) submerged in water is equal to the weight of the water
displaced by the object (see figure). Let \(\rho_{w}=1 \mathrm{g} /
\mathrm{cm}^{3}=1000 \mathrm{kg} / \mathrm{m}^{3}\) be the density of water and
let \(\rho\) be the density of an object in water. Let \(f=\rho / \rho_{w}\). If
\(0
Determine whether the following statements are true and give an explanation or counterexample. a. \(\frac{d}{d x}(\sinh \ln 3)=\frac{\cosh \ln 3}{3}.\) b. \(\frac{d}{d x}(\sinh x)=\cosh x\) and \(\frac{d}{d x}(\cosh x)=-\sinh x.\) c. Differentiating the velocity equation for an ocean wave \(v=\sqrt{\frac{g \lambda}{2 \pi} \tanh \left(\frac{2 \pi d}{\lambda}\right)}\) results in the acceleration of the wave. d. \(\ln (1+\sqrt{2})=-\ln (-1+\sqrt{2}).\) e. \(\int_{0}^{1} \frac{d x}{4-x^{2}}=\frac{1}{2}\left(\operatorname{coth}^{-1} \frac{1}{2}-\cot ^{-1} 0\right).\)
Use a calculator to evaluate each expression or state that the value does not exist. Report answers accurate to four decimal places. a. \(\coth 4\) b. \(\tanh ^{-1} 2\) c. \(\operatorname{csch}^{-1} 5\) d. \(\left.\operatorname{csch} x\right|_{1 / 2} ^{2}\) e. \(\left.\ln \left|\tanh \left(\frac{x}{2}\right)\right|\right|_{1} ^{10}\) f. \(\left.\tan ^{-1}(\sinh x)\right|_{-3} ^{3}\) g. \(\left.\frac{1}{4} \operatorname{coth}^{-1} \frac{x}{4}\right|_{20} ^{36}\)
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