/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 Compute \(dy/dx\) for the follow... [FREE SOLUTION] | 91Ó°ÊÓ

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Compute \(dy/dx\) for the following functions. $$y=\sinh 4 x$$

Short Answer

Expert verified
Answer: The derivative of the function $$y = \sinh{(4x)}$$ is $$\frac{dy}{dx} = 2e^{4x} + 2e^{-4x}$$.

Step by step solution

01

Recall the definition of the hyperbolic sine function

The hyperbolic sine function, written as \(\sinh{(x)}\), is defined as: $$\sinh{(x)} = \frac{e^x - e^{-x}}{2}$$
02

Differentiate the function

Now, we'll differentiate the given function $$y = \sinh{(4x)}$$ with respect to \(x\). Using the chain rule, we get: $$\frac{dy}{dx} = \frac{d}{dx}\left(\sinh{(4x)}\right) = \frac{d}{dx}\left(\frac{e^{4x} - e^{-4x}}{2}\right)$$ We will now differentiate the function inside the parentheses and multiply by the derivative of the function inside the hyperbolic sine. $$\frac{dy}{dx} = \frac{1}{2}\frac{d}{dx}\left(e^{4x} - e^{-4x}\right)$$ Apply the chain rule to differentiate both terms inside the parentheses: $$\frac{dy}{dx} = \frac{1}{2}(4e^{4x} - (-4)e^{-4x})$$
03

Simplify the expression

Finally, we'll simplify the expression for the derivative: $$\frac{dy}{dx} = 2e^{4x} + 2e^{-4x}$$ So the derivative of the function $$y = \sinh{(4x)}$$ is: $$\frac{dy}{dx} = 2e^{4x} + 2e^{-4x}$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule
The chain rule is a fundamental technique in calculus for finding the derivative of composite functions. When a function can be considered as a 'function of a function', like when we have a hyperbolic function involving an expression like '4x', this is where chain rule shines. For example, if we have to differentiate the function \( f(g(x)) \) with respect to \( x \), the chain rule tells us to differentiate \( f \) with respect to \( g \) first, and then multiply by the derivative of \( g \) with respect to \( x \).

In the case of differentiating \( \sinh(4x) \), we consider \( \sinh \) as \( f \) and \( 4x \) as \( g(x) \) and apply the rule accordingly to compute the derivative. The chain rule allows us to break down more complex differentiation problems into simpler parts that we can manage easily, making the differentiation of composite functions like \( \sinh(4x) \) accessible and straightforward.
Hyperbolic Sine Function
The hyperbolic sine function, denoted as \( \sinh \) and pronounced 'sinch', is not as commonly known as its trigonometric counterpart, but it's equally important in mathematics, especially when it comes to hyperbolic geometry and complex analysis.

The function is defined using the exponential function: \[ \sinh(x) = \frac{e^x - e^{-x}}{2} \] This equation shows that \( \sinh \) is actually a result of a particular combination of the exponential function and its inverse. The hyperbolic sine function behaves somewhat like a smoother, unbounded oscillation. This behavior makes \( \sinh \) extremely useful in physics and engineering for modeling scenarios where growth occurs in two opposite directions, like in the case of a hanging cable or the distribution of electric potential in a hyperbolic space.
Exponential Functions Differentiation
The exponential functions, typically of the form \( e^x \) where \( e \) is Euler's number (approximately 2.71828), play a crucial role in various scientific applications due to their unique properties. Differentiating an exponential function is unique because the derivative of \( e^x \) with respect to \( x \) is simply \( e^x \) itself.

When the exponent includes an expression, such as \( e^{4x} \) or \( e^{-4x} \) instead of a single variable, we can still apply the simple rule with the only addition being the inclusion of the derivative of the exponent following the chain rule. Therefore, the derivative of \( e^{4x} \) would be \( 4e^{4x} \) and similarly, the derivative of \( e^{-4x} \) would be \( -4e^{-4x} \) because we differentiate the exponent \( 4x \) as 4 and \( -4x \) as -4 respectively before applying the constant exponential rule.
Derivative of Hyperbolic Functions
Hyperbolic functions like \( \sinh \) involve exponential expressions, and their derivatives can be elegantly found using the properties of exponential differentiation. As shown in the original solution, the derivative of \( \sinh(x) \) is calculated by differentiating the exponential components: \( \frac{d}{dx}(\frac{e^x - e^{-x}}{2}) \), which results in \( \frac{e^x + e^{-x}}{2} \) — surprisingly, this is the hyperbolic cosine function, denoted \( \cosh(x) \).

This relationship between the derivatives of hyperbolic sine and cosine mirrors the relationship between the derivatives of their trigonometric counterparts, sine and cosine. Understanding the relationship between these hyperbolic functions and their derivatives not only helps with finding the slope of hyperbolic functions at any point but also with solving a wide array of mathematical problems involving hyperbolic functions in calculus.

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