/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 Derive the following derivative ... [FREE SOLUTION] | 91Ó°ÊÓ

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Derive the following derivative formulas given that \(d / d x(\cosh x)=\sinh x\) and \(d / d x(\sinh x)=\cosh x.\) $$d / d x(\operatorname{coth} x)=-\operatorname{csch}^{2} x$$

Short Answer

Expert verified
Answer: The derivative formula for coth(x) is: d(coth(x))/dx = -csch^2(x)

Step by step solution

01

Express coth(x) in terms of other hyperbolic functions

The function \(\operatorname{coth}(x)\) can be expressed as the quotient of \(\cosh(x)\) and \(\sinh(x)\): $$ \operatorname{coth}(x) = \frac{\cosh(x)}{\sinh(x)} $$
02

Apply the quotient rule

Now, we can use the quotient rule to find the derivative of \(\operatorname{coth}(x)\). The quotient rule states that if we have a function \(f(x)=\frac{u(x)}{v(x)}\), then the derivative is given by: $$ f'(x) = \frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^{2}} $$ In our case, \(u(x)=\cosh(x)\) and \(v(x)=\sinh(x)\). We are given that \(u'(x)=\sinh(x)\) and \(v'(x)=\cosh(x)\). Plugging these values into the quotient rule, we get: $$ \frac{d}{dx}(\operatorname{coth}(x)) = \frac{\sinh(x)\sinh(x) - \cosh(x)\cosh(x)}{[\sinh(x)]^{2}} $$
03

Simplify the expression

To simplify the expression, we can combine terms in the numerator using the identity \(\cosh^2(x) - \sinh^2(x) = 1\). This leads to: $$ \frac{d}{dx}(\operatorname{coth}(x)) = \frac{-1}{\sinh^2(x)} $$ Now, we can rewrite the expression using the definition of the hyperbolic cosecant (csch) function as \(\operatorname{csch}(x) = \frac{1}{\sinh(x)}\): $$ \frac{d}{dx}(\operatorname{coth}(x)) = -\operatorname{csch}^2(x) $$ So, we have derived the given derivative formula for \(\operatorname{coth}(x)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hyperbolic Functions
Hyperbolic functions are analogs of the trigonometric functions but for a hyperbola rather than a circle. They have similar names and properties, such as hyperbolic sine \( \sinh(x) \) and hyperbolic cosine \( \cosh(x) \):
  • Hyperbolic sine (sinh): \( \sinh(x) = \frac{e^x - e^{-x}}{2} \)
  • Hyperbolic cosine (cosh): \( \cosh(x) = \frac{e^x + e^{-x}}{2} \)
These functions are deeply connected to exponential functions.
The hyperbolic tangent \( \tanh(x) \) and cotangent \( \coth(x) \) are defined similarly to their trigonometric counterparts:
  • Hyperbolic tangent (tanh): \( \tanh(x) = \frac{\sinh(x)}{\cosh(x)} \)
  • Hyperbolic cotangent (coth): \( \coth(x) = \frac{\cosh(x)}{\sinh(x)} \)
Another important hyperbolic function is the hyperbolic cosecant \( \csch(x) \), which is the reciprocal of \( \sinh(x) \):
  • Hyperbolic cosecant (csch): \( \csch(x) = \frac{1}{\sinh(x)} \)
Hyperbolic functions have unique derivatives:
  • \( \frac{d}{dx}(\cosh(x)) = \sinh(x) \)
  • \( \frac{d}{dx}(\sinh(x)) = \cosh(x) \)
These distinctiveness helps in solving calculus problems involving hyperbolic functions.
Derivative
The derivative is a tool in calculus that measures how a function changes as its input changes. It is often described as the "rate of change" or "slope" of the function. For example, the derivative of a function \( f(x) \) is denoted as \( f'(x) \) or \( \frac{df}{dx} \).
For hyperbolic functions, knowing the derivatives is crucial for differentiating more complex expressions. For example:
  • The derivative of the hyperbolic sine \( \sinh(x) \) is \( \cosh(x) \).
  • Conversely, the derivative of the hyperbolic cosine \( \cosh(x) \) is \( \sinh(x) \).
Calculating a derivative involves applying differentiation rules such as the power rule, product rule, chain rule, or quotient rule, depending on the expression's structure.
Mastering derivatives is fundamental for understanding more sophisticated applications of calculus, like solving equations or modeling real-world scenarios.
Quotient Rule
The quotient rule is a method for finding the derivative of a quotient of two differentiable functions. Suppose we have a function \( f(x) = \frac{u(x)}{v(x)} \), where both \( u(x) \) and \( v(x) \) are differentiable.
The quotient rule states:\[\frac{d}{dx}\left(\frac{u(x)}{v(x)}\right) = \frac{u'(x)v(x) - u(x)v'(x)}{(v(x))^2} \\]This tells us how to calculate the derivative by using the derivatives of the numerator \( u(x) \) and the denominator \( v(x) \).
Here's a breakdown of the steps:
  • Step 1: Differentiate the numerator to get \( u'(x) \).
  • Step 2: Differentiate the denominator to get \( v'(x) \).
  • Step 3: Apply the formula by plugging in \( u'(x) \), \( v(x) \), and \( v'(x) \).
The quotient rule is essential when dealing with functions presented as ratios, particularly in calculus problems involving trigonometric and hyperbolic functions, with the latter like \( \coth(x) = \frac{\cosh(x)}{\sinh(x)} \). It also helps simplify and find derivatives accurately in a structured way.

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