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Use the given identity to verify the related identity. Use the identity \(\cosh (x+y)=\cosh x \cosh y+\sinh x \sinh y\) to verify the identity \(\cosh 2 x=\cosh ^{2} x+\sinh ^{2} x.\)

Short Answer

Expert verified
Question: Verify the identity \(\cosh 2x = \cosh^2 x + \sinh^2 x\). Answer: Using the identity \(\cosh(x+y) = \cosh x\cosh y + \sinh x\sinh y\), we substituted \(x\) with \(2x\), and found that \(\cosh(2x) = \cosh^2 x + \sinh^2 x\), which verifies the given identity.

Step by step solution

01

Substitute \(x\) with \(2x\)

First, we need to substitute \(x\) with \(2x\) in the given identity to get the result we want. We have, \(\cosh(x+y) = \cosh x\cosh y + \sinh x\sinh y\) Now, let us substitute \(y = x\): \(\cosh(2x) = \cosh x\cosh x + \sinh x\sinh x\)
02

Simplify the equation

Now, we have: \(\cosh(2x) = \cosh^2 x + \sinh^2 x\) This means that we have verified the identity \(\cosh 2x = \cosh^2 x + \sinh^2 x\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Cosh Function
The hyperbolic cosine function, often written as \( \cosh(x) \), is a fundamental component in hyperbolic trigonometry. It is analogous to the cosine function in circular trigonometry, but adapted for the hyperbola.
The definition of the \( \cosh \) function is quite analytical. It can be expressed using the exponential function: \[ \cosh(x) = \frac{e^x + e^{-x}}{2} \] This definition highlights its key property: \( \cosh(x) \) always produces a value greater than or equal to 1 for all real numbers \( x \).
Here are a few crucial facts about \( \cosh \):
  • \( \cosh(0) = 1 \)
  • It is even, meaning \( \cosh(-x) = \cosh(x) \)
  • Increases exponentially as \( x \) moves away from zero in both directions
Moreover, the \( \cosh \) function is often applied in physical contexts, such as calculating the shape of a hanging cable or chain, known as the catenary. Understanding \( \cosh \) is essential for anyone diving into hyperbolic identities.
Exploring the Sinh Function
The hyperbolic sine function, denoted \( \sinh(x) \), is the counterpart to the hyperbolic cosine function. While \( \cosh(x) \) relates to the average of exponentials, \( \sinh(x) \) can be expressed as the difference between two exponentials: \[ \sinh(x) = \frac{e^x - e^{-x}}{2} \] This definition demonstrates that the hyperbolic sine generates a wide range of real numbers, including both positive and negative values.
Some important properties of \( \sinh \) include:
  • \( \sinh(0) = 0 \)
  • It is an odd function, meaning \( \sinh(-x) = -\sinh(x) \)
  • Shows exponential growth in magnitude as \( x \) moves away from zero
Unlike trigonometric sine, which cycles between -1 and 1, \( \sinh \) exhibits unbounded behavior.
Understanding \( \sinh \) helps with analyzing hyperbolic identities, as it often pairs with \( \cosh \) to form important identities used in calculus and engineering applications.
Identity Verification
Identity verification in mathematics involves proving that two expressions are equivalent, using established identities or transformation techniques. This process ensures the reliability and consistency of the mathematical statements we use.
In the context of hyperbolic functions, verifying identities like \[ \cosh(2x) = \cosh^2(x) + \sinh^2(x) \] involves substituting values and simplifying expressions to check their equivalence using known identities.
The identity provided here utilizes the formula: \[ \cosh(x+y) = \cosh x \cosh y + \sinh x \sinh y \] In this scenario, substituting \( y = x \) immediately confirms the target identity. Practicing identity verification strengthens understanding by reinforcing connections between different mathematical concepts.
Through this approach, students can develop a deeper insight into why these identities work and how they interconnect with larger mathematical frameworks. It's more than just proving equations—it's about understanding the inherent properties of the functions involved.

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Most popular questions from this chapter

Kelly started at noon \((t=0)\) riding a bike from Niwot to Berthoud, a distance of \(20 \mathrm{km},\) with velocity \(v(t)=15 /(t+1)^{2}\) (decreasing because of fatigue). Sandy started at noon \((t=0)\) riding a bike in the opposite direction from Berthoud to Niwot with velocity \(u(t)=20 /(t+1)^{2}\) (also decreasing because of fatigue). Assume distance is measured in kilometers and time is measured in hours. a. Make a graph of Kelly's distance from Niwot as a function of time. b. Make a graph of Sandy's distance from Berthoud as a function of time. c. When do they meet? How far has each person traveled when they meet? d. More generally, if the riders' speeds are \(v(t)=A /(t+1)^{2}\) and \(u(t)=B /(t+1)^{2}\) and the distance between the towns is \(\vec{D},\) what conditions on \(A, B,\) and \(D\) must be met to ensure that the riders will pass each other? e. Looking ahead: With the velocity functions given in part (d), make a conjecture about the maximum distance each person can ride (given unlimited time).

A simple model (with different parameters for different people) for the flow of air in and out of the lungs is $$V^{\prime}(t)=-\frac{\pi}{2} \sin \frac{\pi t}{2}$$ where \(V(t)\) (measured in liters) is the volume of air in the lungs at time \(t \geq 0, t\) is measured in seconds, and \(t=0\) corresponds to a time at which the lungs are full and exhalation begins. Only a fraction of the air in the lungs in exchanged with each breath. The amount that is exchanged is called the tidal volume. a. Find and graph the volume function \(V\) assuming that $$ V(0)=6 \mathrm{L} $$ b. What is the breathing rate in breaths/min? c. What is the tidal volume and what is the total capacity of the lungs?

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Determine whether the following statements are true and give an explanation or counterexample. a. A pyramid is a solid of revolution. b. The volume of a hemisphere can be computed using the disk method. c. Let \(R_{1}\) be the region bounded by \(y=\cos x\) and the \(x\) -axis on \([-\pi / 2, \pi / 2] .\) Let \(R_{2}\) be the region bounded by \(y=\sin x\) and the \(x\) -axis on \([0, \pi] .\) The volumes of the solids generated when \(R_{1}\) and \(R_{2}\) are revolved about the \(x\) -axis are equal.

Theo and Sasha start at the same place on a straight road, riding bikes with the following velocities (measured in \(\mathrm{mi} / \mathrm{hr}\) ). Assume \(t\) is measured in hours. Theo: \(v_{T}(t)=10,\) for \(t \geq 0\) Sasha: \(v_{S}(t)=15 t,\) for \(0 \leq t \leq 1\) and \(v_{S}(t)=15,\) for \(t>1\) a. Graph the velocity functions for both riders. b. If the riders ride for 1 hr, who rides farther? Interpret your answer geometrically using the graphs of part (a). c. If the riders ride for 2 hr, who rides farther? Interpret your answer geometrically using the graphs of part (a). d. Which rider arrives first at the \(10-, 15-\), and 20 -mile markers of the race? Interpret your answer geometrically using the graphs of part (a). e. Suppose Sasha gives Theo a head start of \(0.2 \mathrm{mi}\) and the riders ride for 20 mi. Who wins the race? f. Suppose Sasha gives Theo a head start of \(0.2 \mathrm{hr}\) and the riders ride for 20 mi. Who wins the race?

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