/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 43 Consider the following functions... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Consider the following functions and express the relationship between a small change in \(x\) and the corresponding change in \(y\) in the form \(d y=f^{\prime}(x) d x\). \(f(x)=1 / x^{3}\)

Short Answer

Expert verified
Question: Find the relationship between the changes in x and y, given the function \(f(x) = \frac{1}{x^3}\) in the form of \(dy = f'(x) dx\). Answer: \(dy = -3x^{-4} dx\)

Step by step solution

01

Apply the power rule for differentiation

Recall that the power rule for derivative states that if \(f(x) = x^n\), then \(f'(x) = n x^{n-1}\). Now, rewrite the given function as \(f(x) = x^{-3}\). Then, apply the power rule to find the derivative: \(f'(x) = -3x^{-4}\)
02

Express the relationship between \(dy\) and \(dx\)

We now have the derivative of the function, which is \(f'(x) = -3x^{-4}\). It now remains to establish the relationship between \(dy\) and \(dx\) in the form of a differential equation. The derivative \(f'(x)\) represents the change in \(y\) with respect to the change in \(x\). Therefore, we can write the relationship as \(dy = f'(x) dx\).
03

Write the final equation

Substitute \(f'(x) = -3x^{-4}\) to obtain the final equation: \(dy = -3x^{-4} dx\). This equation represents the relationship between the change in \(y\) and the change in \(x\) for the given function \(f(x) = \frac{1}{x^3}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Rule
The power rule is a fundamental tool in calculus for finding the derivative of a function. It's particularly useful when dealing with polynomial expressions. The rule states that if you have a function of the form \(f(x) = x^n\), the derivative \(f'(x)\) is given by \(n \cdot x^{n-1}\). This means you take the exponent \(n\), multiply it by \(x\), and reduce the exponent by one.

To apply the power rule, it’s important first to rewrite the function in an appropriate form, which often means expressing the function with positive or negative exponents. For instance, the exercise involves \(f(x) = \frac{1}{x^3}\). By rewriting this as \(f(x) = x^{-3}\), it’s easier to apply the power rule.

  • Identify the exponent \(n\).
  • Multiply \(x\) by \(n\).
  • Reduce the exponent by one.
For this function, applying the power rule results in the derivative \(-3x^{-4}\). The simplicity of the power rule makes it a preferred choice for differentiating monomial terms.
Derivative
The derivative of a function measures how the function's output changes as its input changes, essentially capturing the rate of change or the "slope" at any given point. In the exercise, by finding the derivative \(-3x^{-4}\), we are calculating how \(y\) changes relative to \(x\) for the function \(f(x) = \frac{1}{x^3}\).

Derivatives have widespread applications:
  • Determining slopes of tangents to curves.
  • Finding extreme values (maximums and minimums) of functions.
  • Modeling real-world phenomena where change is occurring.
To find a derivative, it is crucial to understand derivative rules like the power rule, product rule, and chain rule. For simple functions, the power rule often suffices. As the derivative \(-3x^{-4}\) shows, when \(x\) is small (close to zero), \(f(x)\) changes quickly, since the derived function's value becomes large. Understanding derivatives helps in interpreting the behavior of functions.
Differential Equation
A differential equation expresses a relationship involving cycles of derivatives. In simpler terms, it relates functions with their derivatives, often used to capture how a particular quantity changes over time or space.

The exercise results in a direct relationship between the differentials \(dy\) and \(dx\). By reaching \(dy = -3x^{-4} dx\), we establish that a small change in \(x\) leads to a change in \(y\) scaled by the factor \(-3x^{-4}\). These equations are important in many fields
  • Engineering: predicting system behavior.
  • Physics: modeling motion and forces.
  • Biology: describing population dynamics.
Solving a differential equation often means finding a function that satisfies the relationship. In this case, the differential equation tells you how to express \(dy\) when \(dx\) is known, helping in integrations and providing solutions to problems featuring rates of change.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Tangent lines and concavity Give an argument to support the claim that if a function is concave up at a point, then the tangent line at that point lies below the curve near that point.

Approximating square roots Let \(a>0\) be given and suppose we want to approximate \(\sqrt{a}\) using Newton's method. a. Explain why the square root problem is equivalent to finding the positive root of \(f(x)=x^{2}-a\) b. Show that Newton's method applied to this function takes the form (sometimes called the Babylonian method) $$x_{n+1}=\frac{1}{2}\left(x_{n}+\frac{a}{x_{n}}\right), \text { for } n=0,1,2, \ldots$$ c. How would you choose initial approximations to approximate \(\sqrt{13}\) and \(\sqrt{73} ?\) d. Approximate \(\sqrt{13}\) and \(\sqrt{73}\) with at least 10 significant digits.

Properties of cubics Consider the general cubic polynomial \(f(x)=x^{3}+a x^{2}+b x+c,\) where \(a, b,\) and \(c\) are real numbers. a. Prove that \(f\) has exactly one local maximum and one local minimum provided that \(a^{2}>3 b\) b. Prove that \(f\) has no extreme values if \(a^{2}<3 b\)

Given the following acceleration functions of an object moving along a line, find the position function with the given initial velocity and position. $$a(t)=2 e^{-t / 6} ; v(0)=1, s(0)=0$$

A family of single-humped functions Consider the functions \(f(x)=\frac{1}{x^{2 n}+1},\) where \(n\) is a positive integer. a. Show that these functions are even. b. Show that the graphs of these functions intersect at the points \(\left(\pm 1, \frac{1}{2}\right),\) for all positive values of \(n\) c. Show that the inflection points of these functions occur at \(x=\pm \sqrt[2 n]{\frac{2 n-1}{2 n+1}},\) for all positive values of \(n\) d. Use a graphing utility to verify your conclusions. e. Describe how the inflection points and the shape of the graphs change as \(n\) increases.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.