/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 Carry out the following steps. ... [FREE SOLUTION] | 91Ó°ÊÓ

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Carry out the following steps. a. Use implicit differentiation to find \(\frac{d y}{d x}\) b. Find the slope of the curve at the given point. $$y^{2}+3 x=8 ;(1, \sqrt{5})$$

Short Answer

Expert verified
Answer: The slope of the curve at the point \((1, \sqrt{5})\) is \(-\frac{3}{2\sqrt{5}}\).

Step by step solution

01

Rewrite the function implicitly

The given function can be rewritten as: $$F(x, y) = y^2 + 3x - 8 = 0$$
02

Differentiate the function implicitly with respect to x

In order to obtain the derivative using implicit differentiation, differentiate both sides of the equation \(F(x, y) = 0\) with respect to x: $$\frac{d}{dx}(y^2 + 3x - 8) = \frac{d}{dx}(0)$$ Next, apply the chain rule and differentiate each term separately: $$\frac{d}{dx}(y^2) + \frac{d}{dx}(3x) - \frac{d}{dx}(8) = 0$$ As we differentiate the terms, we get: $$2y \cdot \frac{dy}{dx} + 3 - 0 = 0$$ Now, we can isolate the unknown, which is \(\frac{dy}{dx}\). Doing so, we can find the expression of the derivative. $$\frac{dy}{dx} = -\frac{3}{2y}$$
03

Evaluate the derivative at the given point to find the slope of the curve

To find the slope at the given point \((1, \sqrt{5})\), substitute the values into the derivative expression: $$\left.\frac{dy}{dx}\right|_{(1, \sqrt{5})} = -\frac{3}{2\sqrt{5}}$$ Thus, the slope of the curve at the point \((1, \sqrt{5})\) is equal to \(-\frac{3}{2\sqrt{5}}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivatives
Derivatives are a key concept in calculus that measure how a function changes as its input changes. Think of it as a way to find the "rate of change" or "slope" at any given point on a curve. In mathematical notation, the derivative of a function \( f(x) \) with respect to \( x \) is denoted as \( \frac{df}{dx} \) or \( f'(x) \).
When dealing with an equation where \( y \) is not isolated, like \( y^2 + 3x = 8 \), we use implicit differentiation to find the derivative. This allows us to differentiate equations that define \( y \) implicitly in terms of \( x \), rather than explicitly.
In the solution provided, implicit differentiation was used to determine \( \frac{dy}{dx} \) by differentiating both sides of the equation with respect to \( x \). This involves differentiating \( y^2 \) using the chain rule, resulting in \( 2y \cdot \frac{dy}{dx} \). Finally, we solved for the derivative, \( \frac{dy}{dx} = -\frac{3}{2y} \), to understand the slope behavior of the curve.
Slope of a Curve
The slope of a curve at a particular point tells us how steep the curve is at that point. It is an important aspect of geometry and calculus because it gives insights into the direction and rate of change of the curve. When we talk about slope in terms of calculus, we're often referring to the derivative.
In this exercise, once the derivative \( \frac{dy}{dx} \) was found, the slope at a specific point \((1, \sqrt{5})\) was evaluated. To do this, we substituted \( x = 1 \) and \( y = \sqrt{5} \) into the derivative expression \( \frac{dy}{dx} = -\frac{3}{2y} \).
This gives us the slope of the curve specifically at the point \((1, \sqrt{5})\) as \(-\frac{3}{2\sqrt{5}}\). Recognizing the slope means you understand the incline or decline behavior of the curve at that exact location, which is crucial for sketching graphs and solving problems involving motion or growth rates.
Chain Rule
The chain rule is a fundamental derivative rule in calculus used for finding the derivative of composite functions. Whenever you have a function within a function, the chain rule helps you differentiate it correctly. The chain rule states that if a function \( y \) is a function of \( u \), and \( u \) is a function of \( x \), then the derivative of \( y \) with respect to \( x \) is \( \frac{dy}{du} \times \frac{du}{dx} \).
In the context of implicit differentiation, especially for the given function \( y^2 + 3x = 8 \), the chain rule was used when we differentiated \( y^2 \) with respect to \( x \).
Since \( y \) is also a function of \( x \), differentiating \( y^2 \) involves applying the chain rule: differentiate \( y^2 \) to get \( 2y \), and then multiply by \( \frac{dy}{dx} \) (since \( y \) is a function of \( x \)). This technique is essential whenever you encounter nested or implicit functions, making it crucial for more advanced calculus problems.

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