/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 74 Derivatives from a table \(U\) s... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Derivatives from a table \(U\) se the following table to find the given derivatives. $$\begin{array}{lllll} x & 1 & 2 & 3 & 4 \\ \hline f(x) & 5 & 4 & 3 & 2 \\ f^{\prime}(x) & 3 & 5 & 2 & 1 \\ g(x) & 4 & 2 & 5 & 3 \\ g^{\prime}(x) & 2 & 4 & 3 & 1 \end{array}$$ $$\left.\frac{d}{d x}(f(x) g(x))\right|_{x=1}$$

Short Answer

Expert verified
Answer: The derivative of the product \(f(x)g(x)\) at \(x = 1\) is \(22\).

Step by step solution

01

Identify the necessary values

From the table, we can find values for \(f(1)\), \(f'(1)\), \(g(1)\), and \(g'(1)\), which are necessary to apply the product rule. These values are: - \(f(1) = 5\) - \(f'(1) = 3\) - \(g(1) = 4\) - \(g'(1) = 2\)
02

Apply the product rule

Now that we have the necessary values, let's apply the product rule: $$\left.\frac{d}{dx}(f(x)g(x))\right|_{x=1} = f'(1)g(1) + f(1)g'(1);$$
03

Plug in the values and simplify the expression

Using the values from the table, plug them into the expression we derived in step 2: $$\left.\frac{d}{dx}(f(x)g(x))\right|_{x=1} = (3)(4) + (5)(2) = 12 + 10 = 22.$$ Thus, the derivative of \(f(x)g(x)\) at \(x = 1\) is \(22\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Product Rule
The Product Rule is a fundamental tool in calculus used for differentiating products of two functions. When finding the derivative of the product of two functions, say \( f(x) \) and \( g(x) \), the rule states that the derivative is equal to the derivative of the first function times the second function plus the first function times the derivative of the second function. Mathematically, this can be expressed as:
  • \( (f(x)g(x))' = f'(x)g(x) + f(x)g'(x) \)
The Product Rule allows one to deconstruct the problem of differentiating complex products into two simpler tasks. For example, in the exercise given, to find the derivative of \( f(x)g(x) \) at \( x = 1 \), values are taken from the provided table and plugged into the product rule formula. This shows how the rule enables an effective and straightforward computation of derivatives for combinations of functions.
Function Tables
Function Tables are a method for organizing values and their corresponding derivatives to aid in computations, such as those required in finding derivatives using differentiation rules. In the exercise, the table provided values of \( f(x) \), \( f'(x) \), \( g(x) \), and \( g'(x) \) at specific points \( x = 1, 2, 3, 4 \). This setup makes it easier for someone who is solving the exercise to quickly locate and use the necessary values to apply differentiation rules like the Product Rule.
  • In this instance, the table immediately highlights \( f(1) = 5 \), \( f'(1) = 3 \), \( g(1) = 4 \), and \( g'(1) = 2 \).
These tables are highly useful for quick reference and ensuring accurate computations, especially in exercises that require multiple values at specific points.
Mathematical Notation
Mathematical Notation is crucial to clearly communicate mathematical ideas or principles, such as describing derivatives and the application of rules like the Product Rule. Notation like \( f'(x) \) is used to denote the derivative of a function \( f(x) \), which can shelter from confusion when analyzing or solving problems. In the context of the exercise, Mathematical Notation represents functions and their derivatives, aiding in straightforward identification and utilization in calculations:
  • \( f'(1) \): Represents the derivative of \( f(x) \) evaluated at \( x = 1 \).
  • \( \frac{d}{dx}(f(x)g(x))|_{x=1} \): Clearly denotes the derivative of the product of \( f(x) \) and \( g(x) \) at \( x = 1 \).
Such concise notations are essential for conveying complex procedures in a manageable form, making it easier for anyone to follow along with the mathematical process involved.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Orthogonal trajectories Two curves are orthogonal to each other if their tangent lines are perpendicular at each point of intersection (recall that two lines are perpendicular to each other if their slopes are negative reciprocals). A family of curves forms orthogonal trajectories with another family of curves if each curve in one family is orthogonal to each curve in the other family. For example, the parabolas \(y=c x^{2}\) form orthogonal trajectories with the family of ellipses \(x^{2}+2 y^{2}=k,\) where \(c\) and \(k\) are constants (see figure). Find \(d y / d x\) for each equation of the following pairs. Use the derivatives to explain why the families of curves form orthogonal trajectories. \(y=c x^{2} ; x^{2}+2 y^{2}=k,\) where \(c\) and \(k\) are constants

Product Rule for three functions Assume that \(f, g,\) and \(h\) are differentiable at \(x\) a. Use the Product Rule (twice) to find a formula for \(\frac{d}{d x}(f(x) g(x) h(x))\) b. Use the formula in (a) to find \(\frac{d}{d x}\left(e^{2 x}(x-1)(x+3)\right)\)

Find the following higher-order derivatives. $$\frac{d^{n}}{d x^{n}}\left(2^{x}\right)$$

In general, the derivative of a product is not the product of the derivatives. Find nonconstant functions \(f\) and \(g\) such that the derivative of \(f g\) equals \(f^{\prime} g^{\prime}\)

Let \(f(x)=\cos ^{2} x+\sin ^{2} x\). a. Use the Chain Rule to show that \(f^{\prime}(x)=0\). b. Assume that if \(f^{\prime}=0,\) then \(f\) is a constant function. Calculate \(f(0)\) and use it with part (a) to explain why \(\cos ^{2} x+\sin ^{2} x=1\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.