/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 Evaluate the derivatives of the ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Evaluate the derivatives of the following functions. $$f(x)=\sin ^{-1} 2 x$$

Short Answer

Expert verified
Answer: The derivative of the function \(f(x)=\sin^{-1} 2x\) is \(f'(x) = \frac{2}{\sqrt{1-4x^2}}\).

Step by step solution

01

Identify the Functions#g_tag_content#The given function is a composite function, with the main function being the inverse sine function and the inner function being \(2x\). So, we have: - \(f(x) = \sin^{-1}x\) - \(g(x) = 2x\)

Step 2: Calculate the Derivative of Each Function#g_tag_content#Now, we need to find the derivatives of the functions \(f(x)\) and \(g(x)\): - Derivative of \(f(x)\): For inverse sine function, we know the derivative is $\frac{1}{\sqrt{1-x^']]) So, \(f'(x) = \frac{1}{\sqrt{1-x^2}}\) - Derivative of \(g(x)\): Since \(g(x) = 2x\), its derivative will be \(g'(x) = 2\)
02

Apply the Chain Rule#g_tag_content#Now, we apply the chain rule to find the derivative of the overall function: $$\frac{d}{dx}(\sin^{-1}(2x)) = f'(g(x))\cdot g'(x)$$ Substitute the values we found in Step 2: $$\frac{d}{dx}(\sin^{-1}(2x)) = \frac{1}{\sqrt{1-(2x)^2}}\cdot 2$$

Step 4: Simplify the Expression#g_tag_content#Now, we simplify the expression: $$\frac{d}{dx}(\sin^{-1}(2x)) = \frac{2}{\sqrt{1-4x^2}}$$ So the derivative of the function \(f(x)=\sin^{-1} 2x\) is: $$f'(x) = \frac{2}{\sqrt{1-4x^2}}$$

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inverse Trigonometric Functions
Inverse trigonometric functions are the inverse processes of the trigonometric functions like sine, cosine, and tangent. These functions are crucial when we want to determine the angle that corresponds to a particular trigonometric value. In this exercise, we focus on the inverse sine function, which is denoted as \( \sin^{-1}(x) \) or \( \arcsin(x) \).
This function helps us find an angle whose sine is \( x \). Its derivative is an essential tool in calculus and is given by \( \frac{1}{\sqrt{1-x^2}} \). This makes it a unique function because it handles angles and requires careful attention to the input values.
The domain of \( \sin^{-1}(x) \) is restricted to make the function invertible, typically from \([-1, 1]\). Knowing the derivative of inverse trigonometric functions allows us to solve more complex problems involving rates of change of angles.
Chain Rule
The chain rule is a fundamental theorem in calculus used for differentiating composite functions. It states that the derivative of a composite function \( f(g(x)) \) is found by computing the derivative of the outer function \( f \) at the inner function \( g(x) \), and multiplying it by the derivative of the inner function \( g(x) \).
Mathematically, it is represented as:
  • \( \frac{d}{dx} f(g(x)) = f'(g(x)) \cdot g'(x) \)
The chain rule is particularly useful when dealing with nested functions.
In our exercise, applying the chain rule allows us to manage the composite nature of \( \sin^{-1}(2x) \). Here, the outer function is the inverse sine, and the inner function is \( 2x \). By utilizing their derivatives, we can find the derivative of the overall function smoothly.
Composite Functions
Composite functions involve the combination of two or more functions, where the output of one function becomes the input of another function. This can be represented as \( (f \circ g)(x) = f(g(x)) \).
Understanding composite functions is vital as they appear frequently in calculus and real-world applications.
In this exercise, \( \sin^{-1}(2x) \) is a composite function where the main function is \( \sin^{-1}(x) \) and the inner function is \( 2x \).
Recognizing the nature of composite functions allows us to use the chain rule effectively to differentiate them. Once you identify and separate the layers of functions, calculating derivatives becomes more manageable.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use the properties of logarithms to simplify the following functions before computing \(f^{\prime}(x)\). $$f(x)=\ln \frac{(2 x-1)(x+2)^{3}}{(1-4 x)^{2}}$$

The total energy in megawatt-hr (MWh) used by a town is given by $$E(t)=400 t+\frac{2400}{\pi} \sin \frac{\pi t}{12},$$ where \(t \geq 0\) is measured in hours, with \(t=0\) corresponding to noon. a. Find the power, or rate of energy consumption, \(P(t)=E^{\prime}(t)\) in units of megawatts (MW). b. At what time of day is the rate of energy consumption a maximum? What is the power at that time of day? c. At what time of day is the rate of energy consumption a minimum? What is the power at that time of day? d. Sketch a graph of the power function reflecting the times at which energy use is a minimum or maximum.

Logistic growth Scientists often use the logistic growth function \(P(t)=\frac{P_{0} K}{P_{0}+\left(K-P_{0}\right) e^{-r_{d}}}\) to model population growth, where \(P_{0}\) is the initial population at time \(t=0, K\) is the carrying capacity, and \(r_{0}\) is the base growth rate. The carrying capacity is a theoretical upper bound on the total population that the surrounding environment can support. The figure shows the sigmoid (S-shaped) curve associated with a typical logistic model. World population (part 1 ) The population of the world reached 6 billion in \(1999(t=0)\). Assume Earth's carrying capacity is 15 billion and the base growth rate is \(r_{0}=0.025\) per year. a. Write a logistic growth function for the world's population (in billions) and graph your equation on the interval \(0 \leq t \leq 200\) using a graphing utility. b. What will the population be in the year 2020? When will it reach 12 billion?

A woman attached to a bungee cord jumps from a bridge that is \(30 \mathrm{m}\) above a river. Her height in meters above the river \(t\) seconds after the jump is \(y(t)=15\left(1+e^{-t} \cos t\right),\) for \(t \geq 0\). a. Determine her velocity at \(t=1\) and \(t=3\). b. Use a graphing utility to determine when she is moving downward and when she is moving upward during the first 10 s. c. Use a graphing utility to estimate the maximum upward velocity.

Prove the following identities and give the values of \(x\) for which they are true. $$\cos \left(\sin ^{-1} x\right)=\sqrt{1-x^{2}}$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.