/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 61 Explain why or why not Determine... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample. a. \(\frac{d}{d x}\left(e^{5}\right)=5 e^{4}\) b. The Quotient Rule must be used to evaluate \(\frac{d}{d x}\left(\frac{x^{2}+3 x+2}{x}\right)\) c. \(\frac{d}{d x}\left(\frac{1}{x^{5}}\right)=\frac{1}{5 x^{4}}\) d. \(\frac{d^{n}}{d x^{n}}\left(e^{3 x}\right)=3^{n} e^{3 x},\) for any integer \(n \geq 1\)

Short Answer

Expert verified
A) \(\frac{d}{d x}\left(e^{5}\right)=5 e^{4}\) B) The Quotient Rule must be used to evaluate \(\frac{d}{d x}\left(\frac{x^{2}+3 x+2}{x}\right)\) C) \(\frac{d}{d x}\left(\frac{1}{x^{5}}\right)=\frac{1}{5 x^{4}}\) D) \(\frac{d^{n}}{d x^{n}}\left(e^{3 x}\right)=3^{n} e^{3 x}\) for any integer \(n \geq 1\) Answer: D) \(\frac{d^{n}}{d x^{n}}\left(e^{3 x}\right)=3^{n} e^{3 x}\) for any integer \(n \geq 1\)

Step by step solution

01

Statement A - Differentiating a constant

The given statement is \(\frac{d}{d x}\left(e^{5}\right)=5 e^{4}\). Note that \(e^{5}\) is a constant, since the power is a constant. To differentiate a constant, the result is 0. Hence, \(\frac{d}{d x}\left(e^{5}\right) = 0\), which is not equal to \(5 e^{4}\). Therefore, Statement A is false.
02

Statement B - The use of Quotient Rule

The given statement claims that the Quotient Rule must be used to evaluate \(\frac{d}{d x}\left(\frac{x^{2}+3 x+2}{x}\right)\). However, we can simplify this expression before differentiating, which would not require the use of the Quotient Rule: \(\frac{x^{2}+3 x+2}{x} = x + 3 + \frac{2}{x}\). Now we can simply apply the Power Rule: \(\frac{d}{d x}\left(x + 3 + \frac{2}{x}\right) = 1 - \frac{2}{x^2}\). Therefore, statement B is false.
03

Statement C - Differentiating a reciprocal power

The given statement is \(\frac{d}{d x}\left(\frac{1}{x^{5}}\right)=\frac{1}{5 x^{4}}\). We can rewrite the function as \(x^{-5}\), and then apply the Power Rule to the function: \(\frac{d}{d x}\left(x^{-5}\right) = -5x^{-6} = \frac{-5}{x^{6}}\). This is not equal to \(\frac{1}{5x^{4}}\), so Statement C is false.
04

Statement D - The nth derivative of an exponential function

The given statement is \(\frac{d^{n}}{d x^{n}}\left(e^{3 x}\right)=3^{n} e^{3 x}\) for any integer \(n \geq 1\). Let's differentiate \(e^{3x}\): 1st derivative: \(\frac{d}{d x}\left(e^{3x}\right) = 3e^{3x}\) (Using the Chain Rule) 2nd derivative: \(\frac{d^{2}}{d x^{2}}\left(e^{3x}\right) = 3 \cdot 3e^{3x} = 3^2e^{3x}\) 3rd derivative: \(\frac{d^{3}}{d x^{3}}\left(e^{3x}\right) = 3 \cdot 3^2e^{3x} = 3^3e^{3x}\) It's easy to notice the pattern: the nth derivative of \(e^{3x}\) is \(3^ne^{3x}\) for any integer \(n \geq 1\). Therefore, Statement D is true. In conclusion, Statements A, B, and C are false, and Statement D is true.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Constant Function Derivative
A constant function is a function that remains the same no matter the input value. For instance, if you have a function like \(f(x) = c\), where \(c\) is a constant, the derivative is always \(0\). This is because the function does not change as \(x\) changes.

In calculus, when differentiating constant functions, remember:
  • The slope of the tangent line to a constant function is \(0\).
  • Constant functions don't have any change in their output.
In the exercise, the expression \(e^5\) is a constant because it doesn't involve the variable \(x\). This means its derivative is \(0\), not \(5e^4\), as initially stated. Keeping this in mind will help avoid mistakes when differentiating constants.
Quotient Rule
The Quotient Rule is a method used in calculus for finding the derivative of a ratio (or quotient) of two functions. Given two functions \(u(x)\) and \(v(x)\), their quotient \(\frac{u}{v}\) has a derivative given by:

\[ \left( \frac{u}{v} \right)' = \frac{v \cdot u' - u \cdot v'}{v^2} \]

However, it is not always necessary to use the Quotient Rule. If a fraction can be simplified, you may apply simpler differentiation techniques such as the Power Rule instead. In the provided exercise, the expression \(\frac{x^2 + 3x + 2}{x}\) can be rewritten as \(x + 3 + \frac{2}{x}\). After simplifying, use basic differentiation rules without the Quotient Rule. Understanding when to simplify first can make differentiation much easier and reduce calculation errors.
Power Rule
The Power Rule is one of the simplest and most frequently used rules in differentiation. It states that for any function \(f(x) = x^n\), where \(n\) is a real number, the derivative is found by:

\[ \frac{d}{dx} x^n = nx^{n-1} \]

In the exercise, converting \(\frac{1}{x^5}\) to \(x^{-5}\) allows you to apply the Power Rule directly. By doing so, the derivative becomes \(-5x^{-6}\), which simplifies to \(\frac{-5}{x^6}\). Note that the original claim \(\frac{1}{5x^4}\) was incorrect, as it did not account for the negative power effectively.

Remembering how to manipulate exponents and apply the Power Rule will help tackle a wide range of differentiation problems efficiently.
Exponential Function Derivative
Exponential functions often take the form \(e^{ax}\), which differ slightly from other functions when differentiating. The derivative of an exponential function \(e^{ax}\) is given by:

\[ \frac{d}{dx} e^{ax} = ae^{ax} \]

In more complex cases, such as taking higher-order derivatives, a pattern emerges quickly. As the exercise demonstrated, for \(e^{3x}\), you can see:
  • 1st derivative: \(3e^{3x}\)
  • 2nd derivative: \(3^2e^{3x}\)
  • nth derivative: \(3^n e^{3x}\) for any integer \(n \geq 1\)
This pattern simplifies the process, as you only need to multiply the derivative by an additional \(a\) each time for each order. Understanding these patterns helps to streamline calculations in differential calculus, especially in higher-level applications.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

a. Determine an equation of the tangent line and normal line at the given point \(\left(x_{0}, y_{0}\right)\) on the following curves. b. Graph the tangent and normal lines on the given graph. \(\left(x^{2}+y^{2}-2 x\right)^{2}=2\left(x^{2}+y^{2}\right)\) \(\left(x_{0}, y_{0}\right)=(2,2)\) (limaçon of Pascal)

An observer stands \(20 \mathrm{m}\) from the bottom of a 10 -m-tall Ferris wheel on a line that is perpendicular to the face of the Ferris wheel. The wheel revolves at a rate of \(\pi \mathrm{rad} / \mathrm{min},\) and the observer's line of sight with a specific seat on the wheel makes an angle \(\theta\) with the ground (see figure). Forty seconds after that seat leaves the lowest point on the wheel, what is the rate of change of \(\theta ?\) Assume the observer's eyes are level with the bottom of the wheel.

Assuming that \(f\) is differentiable for all \(x,\) simplify \(\lim _{x \rightarrow 5} \frac{f\left(x^{2}\right)-f(25)}{x-5}.\)

Suppose you own a fuel-efficient hybrid automobile with a monitor on the dashboard that displays the mileage and gas consumption. The number of miles you can drive with \(g\) gallons of gas remaining in the tank on a particular stretch of highway is given by \(m(g)=50 g-25.8 g^{2}+12.5 g^{3}-1.6 g^{4},\) for \(0 \leq g \leq 4\). a. Graph and interpret the mileage function. b. Graph and interpret the gas mileage \(m(g) / \mathrm{g}\). c. Graph and interpret \(d m / d g\).

Jean and Juan run a one-lap race on a circular track. Their angular positions on the track during the race are given by the functions \(\theta(t)\) and \(\varphi(t),\) respectively, where \(0 \leq t \leq 4\) and \(t\) is measured in minutes (see figure). These angles are measured in radians, where \(\theta=\varphi=0\) represent the starting position and \(\theta=\varphi=2 \pi\) represent the finish position. The angular velocities of the runners are \(\theta^{\prime}(t)\) and \(\varphi^{\prime}(t)\). a. Compare in words the angular velocity of the two runners and the progress of the race. b. Which runner has the greater average angular velocity? c. Who wins the race? d. Jean's position is given by \(\theta(t)=\pi t^{2} / 8 .\) What is her angular velocity at \(t=2\) and at what time is her angular velocity the greatest? e. Juan's position is given by \(\varphi(t)=\pi t(8-t) / 8 .\) What is his angular velocity at \(t=2\) and at what time is his angular velocity the greatest?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.