/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 54 Evaluate the following limits or... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the following limits or state that they do not exist. $$\lim _{x \rightarrow \infty} \frac{\cos x}{x}$$

Short Answer

Expert verified
Solution: Based on the analysis and solution described above, we found that the limit of the function is 0. So, the limit of the function as x approaches infinity is: $$\lim _{x \rightarrow \infty} \frac{\cos x}{x} = 0$$

Step by step solution

01

Identify the properties of the function

We know that the cosine function has values ranging from -1 to 1 for any value of x. Therefore, we can write: $$-1 \leq \cos x \leq 1$$ This means that for any value of x, the cosine function will be between -1 and 1.
02

Divide the inequality by x

Now, we will divide the entire inequality by x. $$-\frac{1}{x} \leq \frac{\cos x}{x} \leq \frac{1}{x}$$
03

Apply the limit

We want to find the limit of the function as x approaches infinity. Therefore, we will apply the limit to each part of the inequality. Note that we can apply limits to each part of an inequality as long as the direction of the inequality remains the same. So we have: $$\lim_{x \rightarrow \infty} -\frac{1}{x} \leq \lim_{x \rightarrow \infty} \frac{\cos x}{x} \leq \lim_{x \rightarrow \infty} \frac{1}{x}$$
04

Find the limits of the bounding functions

Now, we need to find the limit of -1/x and 1/x as x approaches infinity. These limits are straightforward to calculate: $$\lim_{x \rightarrow \infty} -\frac{1}{x} = 0$$ and $$\lim_{x \rightarrow \infty} \frac{1}{x} = 0$$
05

Apply the Squeeze theorem

Since we have found the limits of the bounding functions, we can now apply the Squeeze theorem. The Squeeze theorem states that if a function is always between two functions that have the same limit at a point, then the function will also have that limit at that point. Therefore, the limit of the function, as x approaches infinity, is: $$\lim _{x \rightarrow \infty} \frac{\cos x}{x} = 0$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Squeeze Theorem
The Squeeze Theorem, also known as the Sandwich Theorem or the Pinching Theorem, is a fundamental concept in calculus that asserts if a function is squeezed or sandwiched between two other functions at a certain point and if these two functions converge to the same limit, then the 'squeezed' function must also converge to that same limit.

For example, given three functions, if we have \( f(x) \leq g(x) \leq h(x) \) and the limits of \( f(x) \) and \( h(x) \) are equal as \( x \) approaches \( a \), that is, if \( \lim_{{x \rightarrow a}} f(x) = \lim_{{x \rightarrow a}} h(x) = L \), then \( \lim_{{x \rightarrow a}} g(x) = L \) as well. This powerful tool is particularly useful for evaluating limits where direct substitution or algebraic manipulation isn't possible.
Limits at Infinity
The concept of limits at infinity pertains to the behavior of functions as the variable \( x \) grows without bounds, either positively or negatively. Mathematically, we express this as \( x \) approaches infinity (\( \infty \) or \( -\infty \)).

The main focus here is to understand what value the function converges to, if any, as the input grows larger and larger. When \( \lim_{{x \rightarrow \infty}} f(x) = L \) or \( \lim_{{x \rightarrow -\infty}} f(x) = L \) for some real number \( L \), it means that the values of \( f(x) \) get arbitrarily close to \( L \) as \( x \) becomes very large or very small in the negative direction. This concept is particularly relevant when discussing horizontal asymptotes of functions.
Trigonometric Functions
Trigonometric functions, such as sine \( (\sin) \), cosine \( (\cos) \), and tangent \( (\tan) \) are fundamental in calculus, especially when dealing with periodic behaviors and harmonics. Each trigonometric function has specific properties and values that range over certain intervals.

For instance, the cosine function ranges between -1 and 1 for all real numbers, meaning \( -1 \leq \cos(x) \leq 1 \). This boundedness property is enormously beneficial when applying the Squeeze Theorem because it allows functions involving trigonometric components to be estimated and their limits easily found, as demonstrated in the original exercise where the cosine function set the bounds for squeezing.
Inequalities in Calculus
Inequalities play a significant role in calculus by providing a framework for comparing the relative sizes of functions and determining their behavior. When solving inequalities, it's crucial to remember that the standard rules for inequalities apply, just as they do in algebra.

However, when encountering limits in the context of inequalities, it is important to maintain the direction of the inequality while evaluating the limits separately. If \( f(x) \leq g(x) \) for all \( x \) in some interval, and we take the limit as \( x \) approaches a point within that interval, the result must preserve the inequality, like \( \lim_{{x \rightarrow a}} f(x) \leq \lim_{{x \rightarrow a}} g(x) \) assuming the limits exist. This allows calculus students to solve problems involving limits of functions where direct computation is not possible, as in the case of the textbook exercise involving trigonometric functions and limits at infinity.

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Most popular questions from this chapter

Jean and Juan run a one-lap race on a circular track. Their angular positions on the track during the race are given by the functions \(\theta(t)\) and \(\varphi(t),\) respectively, where \(0 \leq t \leq 4\) and \(t\) is measured in minutes (see figure). These angles are measured in radians, where \(\theta=\varphi=0\) represent the starting position and \(\theta=\varphi=2 \pi\) represent the finish position. The angular velocities of the runners are \(\theta^{\prime}(t)\) and \(\varphi^{\prime}(t)\). a. Compare in words the angular velocity of the two runners and the progress of the race. b. Which runner has the greater average angular velocity? c. Who wins the race? d. Jean's position is given by \(\theta(t)=\pi t^{2} / 8 .\) What is her angular velocity at \(t=2\) and at what time is her angular velocity the greatest? e. Juan's position is given by \(\varphi(t)=\pi t(8-t) / 8 .\) What is his angular velocity at \(t=2\) and at what time is his angular velocity the greatest?

Tangency question It is easily verified that the graphs of \(y=x^{2}\) and \(y=e^{x}\) have no points of intersection (for \(x>0\) ), and the graphs of \(y=x^{3}\) and \(y=e^{x}\) have two points of intersection. It follows that for some real number \(2 0 \) ). Using analytical and/or graphical methods, determine \(p\) and the coordinates of the single point of intersection.

Work carefully Proceed with caution when using implicit differentiation to find points at which a curve has a specified slope. For the following curves, find the points on the curve (if they exist) at which the tangent line is horizontal or vertical. Once you have found possible points, make sure they actually lie on the curve. Confirm your results with a graph. $$x^{2}\left(3 y^{2}-2 y^{3}\right)=4$$

Find the following higher-order derivatives. $$\frac{d^{2}}{d x^{2}}\left(\log _{10} x\right)$$

Identifying functions from an equation. The following equations implicitly define one or more functions. a. Find \(\frac{d y}{d x}\) using implicit differentiation. b. Solve the given equation for \(y\) to identify the implicitly defined functions \(y=f_{1}(x), y=f_{2}(x), \ldots\) c. Use the functions found in part (b) to graph the given equation. $$y^{2}(x+2)=x^{2}(6-x) \text { (trisectrix) }$$

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