/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 Implicit differentiation with ra... [FREE SOLUTION] | 91Ó°ÊÓ

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Implicit differentiation with rational exponents Determine the slope of the following curves at the given point. $$x^{2 / 3}+y^{2 / 3}=2 ;(1,1)$$

Short Answer

Expert verified
Answer: The slope of the curve at the point (1,1) is -1.

Step by step solution

01

Analyze the equation

- The given curve is $$x^{2/3}+y^{2/3}=2$$. - The given point is (1,1). - We need to find the slope of the curve at the given point
02

Apply the implicit differentiation

Differentiate both sides of the curve equation with respect to x, and remember to apply the chain rule when differentiating y. - Differentiate the x-term: $$(\frac{2}{3})x^{\frac{2}{3}-1} = \frac{2}{3}x^{-1/3}$$ - Differentiate the y-term: $$(\frac{2}{3})(y^{2/3-1})\cdot \frac{dy}{dx} = \frac{2}{3}y^{-1/3}\cdot \frac{dy}{dx}$$ - Differentiate the constant term: $$\frac{d(2)}{dx} = 0$$ - So we get: $$\frac{2}{3}x^{-1/3} + \frac{2}{3}y^{-1/3}\cdot\frac{dy}{dx} = 0$$
03

Solve for the derivative dy/dx

Now isolate dy/dx in the equation: $$\frac{2}{3}y^{-1/3}\cdot\frac{dy}{dx} = -\frac{2}{3}x^{-1/3}$$ Divide both sides by \(\frac{2}{3}y^{-1/3}\): $$\frac{dy}{dx} = \frac{-\frac{2}{3}x^{-1/3}}{\frac{2}{3}y^{-1/3}}$$ Simplify the expression: $$\frac{dy}{dx} = -\frac{x^{-1/3}}{y^{-1/3}} = -\frac{1}{x^{1/3}}\cdot y^{1/3}$$
04

Evaluate dy/dx at the given point

- Substitute the given point (1,1) into the expression for dy/dx: $$\frac{dy}{dx}(1,1) = -\frac{1}{1^{1/3}}\cdot 1^{1/3}$$ - Simplify: $$\frac{dy}{dx}(1,1) = -1$$ The slope of the curve $$x^{2/3}+y^{2/3}=2$$ at the point (1,1) is -1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Slope of a Curve
The slope of a curve at a point is a measure of how steep the curve is at that point. It's a fundamental concept in calculus that describes the rate of change of the function at a given point. When we talk about slope, we're generally referring to the derivative of the function at that point. For a curve described by an equation in two variables, like our example equation, \(x^{2/3} + y^{2/3} = 2\), finding the slope at a point requires a method called implicit differentiation since the equation isn't solved for \(y\) explicitly.

In this context, the slope at a point (1,1) provides us with an understanding of how the curve behaves in the immediate vicinity of this point. In our exercise, by determining the slope, we ascertain that the curve is descending at a 45-degree angle at the point (1,1), since the slope found is -1. This piece of information is invaluable for various applications, such as physics (for determining velocity or acceleration) or economics (to find out how one variable affects another).
Rational Exponents and Their Differentiation
Rational exponents are a way of expressing powers and roots in a unified manner. For instance, \(x^{2/3}\) denotes the cube root of \(x^2\), which can also be written as \(\sqrt[3]{x^2}\). Differentiating terms with rational exponents involves applying the standard power rule of differentiation. However, we must be careful with the negative exponents that arise after applying the rule.

In our exercise, differentiating \(x^{2/3}\) generates \(x^{-1/3}\), a negative exponent indicating the reciprocal of a cube root. The differentiation of rational exponents requires attention to ensure accurate simplification. Particularly, when we find the derivative at a point like (1,1), we capitalize on the property that the cube root of 1 is 1, simplifying our calculations considerably. This concept is not only essential for finding slopes of curves but is pervasive in all fields that utilize calculus.
Applying the Chain Rule in Implicit Differentiation
The chain rule is a cornerstone of calculus, enabling us to differentiate compositions of functions. In implicit differentiation, it allows us to differentiate expressions where one variable is a function of another, such as the \(y\) term in our equation, \(y^{2/3}\). The chain rule dictates that we take the derivative of the outer function, in this case \(y^{2/3}\), as if \(y\) were just \(x\), and then multiply by the derivative of the inner function, which is \(dy/dx\).

In the step-by-step solution provided, we applied the chain rule by multiplying \((2/3)y^{-1/3}\) by \(dy/dx\). The result ties the rate of change of \(y\) to that of \(x\), a relationship that is crucial when the variables are interdependent. Mastering the chain rule is indispensable, as it finds application in various complex differentiation problems, such as those involving trigonometric functions, exponentials, or logarithms, not to mention its pivotal role in all forms of implicit differentiation.

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