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Find the derivative of the following functions. $$y=\frac{\tan t}{1+\sec t}$$

Short Answer

Expert verified
Answer: The derivative of the function is $$\frac{dy}{dp} = -12p^{-4}$$.

Step by step solution

01

Rewrite the function

First, let's rewrite the given function in a more suitable form for differentiation. We can rewrite the function as: $$y = 4p^{-3}$$
02

Apply the power rule to find the derivative

Now we'll apply the power rule for differentiation to find $$\frac{dy}{dp}$$. The power rule states that if $$y = p^n$$, then $$\frac{dy}{dp} = np^{n-1}$$, where n is a constant. So, applying the power rule to our function, we get: $$\frac{dy}{dp} = -3(4)p^{-3-1}$$
03

Simplify the derivative

Simplify the expression obtained in step 2: $$\frac{dy}{dp} = -3(4)p^{-4} = -12p^{-4}$$
04

Write the final answer

The derivative of the function $$y = \frac{4}{p^3}$$ with respect to p is: $$\frac{dy}{dp} = -12p^{-4}$$

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Most popular questions from this chapter

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