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Evaluate the derivatives of the following functions. $$f(t)=\ln \left(\tan ^{-1} t\right)$$

Short Answer

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Question: Find the derivative of the function \(f(t) = \ln\left(\tan^{-1}(t)\right)\). Answer: The derivative of the given function is \(f'(t) = \frac{1}{\tan^{-1}(t)}\cdot \frac{1}{1+t^2}\).

Step by step solution

01

Identify the outer and inner functions

In order to apply the Chain Rule, we need to identify the outer and inner functions. In this case, the outer function is the natural logarithm, and the inner function is the inverse tangent function. So, we have \(g(t) = \ln(t)\) and \(h(t) = \tan^{-1}(t)\). The given function can be written as \(f(t) = g(h(t))\).
02

Compute the derivatives of outer and inner functions

Next, we need to find the derivatives of the outer and inner functions. The derivative of the natural logarithm function is \(\frac{1}{t}\) and the derivative of the inverse tangent function is \(\frac{1}{1+t^2}\). So we have: \(g'(t) = \frac{1}{t}\) and \(h'(t) = \frac{1}{1+t^2}\).
03

Apply the Chain Rule to the composite function

Now that we have the derivatives of the outer and inner functions, we can apply the Chain Rule to find the derivative of the composite function \(f(t) = g(h(t))\). The Chain Rule states that if \(f(t) = g(h(t))\), then \(f'(t) = g'(h(t)) \cdot h'(t)\). Using this rule, we have: $$f'(t) = g'\left(\tan^{-1}(t)\right) \cdot \left(\frac{1}{1+t^2}\right) = \frac{1}{\tan^{-1}(t)}\cdot \left(\frac{1}{1+t^2}\right)$$
04

Write the final answer

Putting everything together, we find that the derivative of \(f(t) = \ln\left(\tan^{-1}(t)\right)\) is: $$f'(t) = \frac{1}{\tan^{-1}(t)}\cdot \frac{1}{1+t^2}$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule
The chain rule is an essential concept in calculus, especially when dealing with composite functions. Imagine you have a function that is made up of two other functions, where one is nested inside the other, like layers of an onion. To find the derivative of such a composite function, you need the chain rule. The chain rule can be expressed as: if you have a function \( f(t) = g(h(t)) \), then the derivative \( f'(t) \) is calculated by taking the derivative of the outer function \( g \) evaluated at the inner function \( h(t) \), and multiplying it by the derivative of the inner function\( h'(t) \). In formula form, this looks like:\[ f'(t) = g'(h(t)) \cdot h'(t) \]By decomposing a complex function into layers, you can easily manage derivatives, making the chain rule a powerful tool in calculus. This principle is particularly handy when dealing with functions involving logarithms, trigonometric functions, or other non-linear transformations.
Inverse Trigonometric Functions
Inverse trigonometric functions are the flipsides of the traditional trigonometric functions like sine, cosine, and tangent. Inverse functions effectively "undo" what the original functions do. For example, the inverse tangent function, often written as \( \tan^{-1}(t) \) or \( \text{arctan}(t) \), asks,"What angle has a tangent of \( t \)?"When finding derivatives of inverse trigonometric functions, their unique properties come into play. The derivative of the inverse tangent function is:\[ \frac{d}{dt}\left(\tan^{-1}(t)\right) = \frac{1}{1 + t^2} \]This result is important as it describes how the inverse function changes with respect to \( t \). Understanding this derivative is useful when you're using the chain rule in calculus, especially when the inverse function is nested inside another function, like a logarithm. This knowledge allows you to untangle and calculate the rates of change in complicated composite functions.
Natural Logarithm Function
The natural logarithm function, written as \( \ln(t) \), is one of the core functions in calculus, representing the inverse of the exponential function \( e^t \). This logarithm is "natural" because it arises naturally in mathematical models dealing with growth, decay, and compounding processes.The derivative of the natural logarithm function is straightforward:\[ \frac{d}{dt}\left(\ln(t)\right) = \frac{1}{t} \]This expression shows how the rate of change of \( \ln(t) \) decreases as \( t \) increases, contributing to its widespread use in differential calculus. This property is particularly helpful when you use the chain rule. It helps break down complex expressions involving the logarithm of another function. Recognizing these derivatives can simplify evaluating the rate of change for compound functions, making it a fundamental skill for calculus students.

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Most popular questions from this chapter

Savings plan Beginning at age \(30,\) a self-employed plumber saves \(\$ 250\) per month in a retirement account until he reaches age \(65 .\) The account offers \(6 \%\) interest, compounded monthly. The balance in the account after \(t\) years is given by \(A(t)=50,000\left(1.005^{12 t}-1\right)\) a. Compute the balance in the account after \(5,15,25,\) and 35 years. What is the average rate of change in the value of the account over the intervals \([5,15],[15,25],\) and [25,35]\(?\) b. Suppose the plumber started saving at age 25 instead of age 30\. Find the balance at age 65 (after 40 years of investing). c. Use the derivative \(d A / d t\) to explain the surprising result in part (b) and to explain this advice: Start saving for retirement as early as possible.

Work carefully Proceed with caution when using implicit differentiation to find points at which a curve has a specified slope. For the following curves, find the points on the curve (if they exist) at which the tangent line is horizontal or vertical. Once you have found possible points, make sure they actually lie on the curve. Confirm your results with a graph. $$y^{2}-3 x y=2$$

A cylindrical tank is full at time \(t=0\) when a valve in the bottom of the tank is opened. By Torricelli's Law, the volume of water in the tank after \(t\) hours is \(V=100(200-t)^{2}\), measured in cubic meters. a. Graph the volume function. What is the volume of water in the tank before the valve is opened? b. How long does it take the tank to empty? c. Find the rate at which water flows from the tank and plot the flow rate function. d. At what time is the magnitude of the flow rate a minimum? A maximum?

Assuming the first and second derivatives of \(f\) and \(g\) exist at \(x\), find a formula for \(\frac{d^{2}}{d x^{2}}(f(x) g(x))\)

Calculating limits exactly Use the definition of the derivative to evaluate the following limits. $$\lim _{x \rightarrow e} \frac{\ln x-1}{x-e}$$

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