/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 Sketch the graph of \(f^{\prime}... [FREE SOLUTION] | 91Ó°ÊÓ

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Sketch the graph of \(f^{\prime}(x)=2 .\) Then sketch three possible graphs of \(f\).

Short Answer

Expert verified
Answer: Based on the given derivative \(f^{\prime}(x) = 2\), the function \(f(x)\) is a linear function with a constant slope of 2. Some possible graphs for \(f(x)\) include: 1. Linear function with slope 2 and y-intercept 0: \(f(x) = 2x\) 2. Linear function with slope 2 and y-intercept 1: \(f(x) = 2x + 1\) 3. Linear function with slope 2 and y-intercept -1: \(f(x) = 2x - 1\) These are just examples, and there are infinitely many possible graphs for \(f(x)\) with different y-intercepts.

Step by step solution

01

Analyzing the derivative \(f^{\prime}(x) = 2\)

First, we need to understand what the given derivative tells us about the function \(f(x)\). The derivative \(f^{\prime}(x)\) represents the slope of the tangent line to the function \(f(x)\) at any point \(x\). Given that \(f^{\prime}(x) = 2\), we know that the slope of the tangent line of \(f(x)\) is constant and equal to 2 for all values of \(x\). This means that the function \(f(x)\) must have a uniformly increasing slope, and is therefore a linear function.
02

Sketch the graph of \(f^{\prime}(x) = 2\)

Since we know that the derivative is constant, it means that the graph of the derivative will be a horizontal line. To sketch the graph of \(f^{\prime}(x) = 2\), we simply draw a horizontal line at \(y = 2\).
03

Sketch three possible graphs of \(f(x)\)

As we have determined that \(f(x)\) should be a linear function with a constant slope of 2, we can now sketch three possible graphs for \(f(x)\). To obtain different graphs of the function, we can change the y-intercept value. Some possible graphs are: 1. Linear function with slope 2 and y-intercept 0: \(f(x) = 2x\). The graph goes through the origin and has an upward inclination. 2. Linear function with slope 2 and y-intercept 1: \(f(x) = 2x + 1\). The graph goes through the point \((0,1)\) and has an upward inclination. 3. Linear function with slope 2 and y-intercept -1: \(f(x) = 2x - 1\). The graph goes through the point \((0,-1)\) and has an upward inclination. Keep in mind that, although we have provided three examples of possible graphs of \(f(x)\), there are infinitely many possible graphs for \(f(x)\) since we can have different y-intercepts.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Constant Slope
When discussing the notion of a 'constant slope,' we're talking about a situation where a line on a graph has the same steepness throughout its entire length. Essentially, no matter where you measure it, the slope (rise over run) will remain the same. In the context of calculus and derivatives, a constant slope means that the rate of change of the function is the same at any point along the function. In our example where the derivative of a function, given by \(f^{\textprime}(x)=2\), is a constant, it indicates that the function itself is increasing at a constant rate. For every unit that \(x\) increases, the value of \(f(x)\) goes up by 2 units.

This concept is fundamental in understanding linear functions and their graph representation. If a student struggles to visualize this concept, a useful exercise is to draw a number of lines with different slopes on grid paper and note how the angles and steepnesses compare. The one with constant slope will always create equal-sized right triangles when points along the line are connected vertically and horizontally to form a triangle.
Linear Function Graph
A 'linear function graph' depicts a straight line that can be represented by the linear equation y=mx+b, where 'm' is the slope and 'b' is the y-intercept—the point at which the line crosses the y-axis. Our textbook problem involves sketching the graph of a linear function with a slope of 2. This means that for each step rightward (increase in \(x\)) the line will move two steps upward (increase in \(y\)).

To help students further grasp this concept, demonstrate how altering the slope and y-intercept values changes the line's orientation and position on the graph. For instance, increasing the slope makes the line steeper, while changing the y-intercept moves the line up or down without affecting its steepness.
Horizontal Line Derivative
The 'horizontal line derivative' is conceptually straightforward—whenever the graph of a function is a perfectly horizontal line, its derivative is zero. This is because a horizontal line has a slope of zero, and a derivative at a point gives us the slope of the tangent line at that point. When we look at our function's derivative, \(f^{\textprime}(x)=2\), and its graph—which is a horizontal line at \(y=2\)—we must remember that this represents the slope of the original function, not the function itself. In other words, while our derivative graph is horizontal, the actual function it corresponds to is not; it’s a line with a slope of 2. If a student is confused, remind them that the derivative function is a separate function entirely that provides information on the original function’s rate of change, not its position.
Tangent Line Slope
The 'tangent line slope' is a measurement of how steep the tangent is at a certain point on a curve. It's the value of the derivative at that point. Since in our example we have a constant derivative, \(f^{\textprime}(x)=2\), every tangent line on the function \(f(x)\) has the same slope, which is 2. This implies that if you were to draw tiny lines touching the curve of \(f(x)\) at any and every point, each of these tiny lines would have the same slope—parallel to each other—inclining upwards from left to right. The concept of the tangent line slope is paramount in understanding the movement of a point along a curve. To make this notion clear to students, demonstrate it by drawing tangent lines at numerous points on a curved function and highlighting how the slopes vary, except for the case in our current scenario where the derivative is constant.

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Most popular questions from this chapter

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Suppose a large company makes 25,000 gadgets per year in batches of \(x\) items at a time. After analyzing setup costs to produce each batch and taking into account storage costs, it has been determined that the total cost \(C(x)\) of producing 25,000 gadgets in batches of \(x\) items at a time is given by $$C(x)=1,250,000+\frac{125,000,000}{x}+1.5 x.$$ a. Determine the marginal cost and average cost functions. Graph and interpret these functions. b. Determine the average cost and marginal cost when \(x=5000\). c. The meaning of average cost and marginal cost here is different from earlier examples and exercises. Interpret the meaning of your answer in part (b).

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