/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 Explain why \(f^{\prime}(x)\) co... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Explain why \(f^{\prime}(x)\) could be positive or negative at a point where \(f(x) > 0\).

Short Answer

Expert verified
Explain. Answer: Yes, the derivative of a function can be either positive or negative at a point where the function itself is greater than 0. This is because the derivative, \(f^{\prime}(x)\), represents the rate of change of the function, not the function value itself. If the derivative is positive at a point, it means the function is increasing at that point. If the derivative is negative, it means the function is decreasing. Therefore, it is possible for a function with a positive value to have a positive or negative derivative depending on whether it is increasing or decreasing at that particular point.

Step by step solution

01

Understand the meaning of the derivative

The derivative of a function, \(f^{\prime}(x)\), gives us information about the rate of change of the function, or how fast the function is increasing or decreasing at a given point. If the derivative is positive, it means the function is increasing at that point; if the derivative is negative, it means the function is decreasing at that point.
02

Consider the case when the function is increasing

Suppose at some point \(x=a\), the function value \(f(a)>0\). Imagine that the function is increasing at \(x=a\), which means that the slope of the tangent line to the graph at this point is positive. In this case, we can conclude that \(f^{\prime}(a)>0\).
03

Consider the case when the function is decreasing

Now, let's still assume that at \(x=a\), the function value \(f(a)>0\). However, this time imagine that the function is decreasing at \(x=a\), which means that the slope of the tangent line to the graph at this point is negative. In this case, we can conclude that \(f^{\prime}(a)<0\).
04

Explain the result

As demonstrated in steps 2 and 3, it is possible for the derivative of a function, \(f^{\prime}(x)\), to be either positive or negative at a point where the function itself, \(f(x)\), is greater than 0. The key is to remember that the derivative represents the rate of change of the function and not the function value itself. Just because the function value is positive, it doesn't mean that the function is necessarily increasing or that the derivative must be positive.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate of Change
The concept of rate of change is fundamental in calculus and represents how one quantity changes in relation to another. When we look at the derivative of a function, denoted as f'(x), we're investigating the rate at which the function's value is changing at a certain point along its graph. To understand rate of change, consider a car's speedometer: It shows how rapidly the car's position changes over time. Similarly, a function's derivative tells us how quickly the function's value is changing at a particular x-value.

Mathematically, if you have a function f(x), the rate of change at a point x is given by the derivative f'(x). If f'(x) is positive, the function's value is increasing as x increases; if it's negative, the function's value is decreasing. This behavior holds true regardless of whether the original function's value, f(x), is positive or negative at that point.
Tangent Line Slope
The tangent line to a curve at a particular point is a straight line that just 'touches' the curve at that point without cutting through it. It essentially represents the curve's direction at that point. The slope of this tangent line is of particular interest because it provides a numerical value for the steepness or incline of the curve at exactly one point, which is the derivative of the function at that point, f'(x).

In practical terms, imagine tracing your finger along a hill's contour. As you move along a slope, the angle of the hill under your finger represents the slope of the tangent to the hill's profile at each point. In calculus, the slope of the tangent line to a function's graph at any point describes how steep the graph is at that exact location. This slope is crucial for understanding many physical phenomena, such as acceleration (the rate of velocity change) in physics.
Function Increasing or Decreasing
When analyzing functions, it's essential to determine where they are increasing or decreasing. An increasing function is one where, as you move along the graph from left to right, the function's value rises. Conversely, a decreasing function's value falls as you move from left to right. This behavior is intimately related to the function's derivative: a positive derivative, f'(x) > 0, indicates the function is ascending, whereas a negative derivative, f'(x) < 0, signals that it's descending.

Whether a function is increasing or decreasing at particular points can have significant implications in various fields, such as economics, where an increasing function might represent a growing market. It's critical to recall that a function can increase in one interval and decrease in another, and these changes are depicted by the sign of its derivative within those intervals.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A lighthouse stands 500 m off a straight shore and the focused beam of its light revolves four times each minute. As shown in the figure, \(P\) is the point on shore closest to the lighthouse and \(Q\) is a point on the shore 200 m from \(P\). What is the speed of the beam along the shore when it strikes the point \(Q ?\) Describe how the speed of the beam along the shore varies with the distance between \(P\) and \(Q\). Neglect the height of the lighthouse.

Logistic growth Scientists often use the logistic growth function \(P(t)=\frac{P_{0} K}{P_{0}+\left(K-P_{0}\right) e^{-r_{d}}}\) to model population growth, where \(P_{0}\) is the initial population at time \(t=0, K\) is the carrying capacity, and \(r_{0}\) is the base growth rate. The carrying capacity is a theoretical upper bound on the total population that the surrounding environment can support. The figure shows the sigmoid (S-shaped) curve associated with a typical logistic model. World population (part 1 ) The population of the world reached 6 billion in \(1999(t=0)\). Assume Earth's carrying capacity is 15 billion and the base growth rate is \(r_{0}=0.025\) per year. a. Write a logistic growth function for the world's population (in billions) and graph your equation on the interval \(0 \leq t \leq 200\) using a graphing utility. b. What will the population be in the year 2020? When will it reach 12 billion?

Calculating limits exactly Use the definition of the derivative to evaluate the following limits. $$\lim _{x \rightarrow e} \frac{\ln x-1}{x-e}$$

General logarithmic and exponential derivatives Compute the following derivatives. Use logarithmic differentiation where appropriate. $$\frac{d}{d x}\left(1+\frac{1}{x}\right)^{x}$$

\(F=f / g\) be the quotient of two functions that are differentiable at \(x\) a. Use the definition of \(F^{\prime}\) to show that $$ \frac{d}{d x}\left(\frac{f(x)}{g(x)}\right)=\lim _{h \rightarrow 0} \frac{f(x+h) g(x)-f(x) g(x+h)}{h g(x+h) g(x)} $$ b. Now add \(-f(x) g(x)+f(x) g(x)\) (which equals 0 ) to the numerator in the preceding limit to obtain $$\lim _{h \rightarrow 0} \frac{f(x+h) g(x)-f(x) g(x)+f(x) g(x)-f(x) g(x+h)}{h g(x+h) g(x)}$$ Use this limit to obtain the Quotient Rule. c. Explain why \(F^{\prime}=(f / g)^{\prime}\) exists, whenever \(g(x) \neq 0\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.