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Determine \(\lim _{x \rightarrow \infty} f(x)\) and \(\lim _{x \rightarrow-\infty} f(x)\) for the following rational functions. Then give the horizontal asymptote of \(f\) (if any). $$f(x)=\frac{12 x^{8}-3}{3 x^{8}-2 x^{7}}$$

Short Answer

Expert verified
Answer: The left and right limits as x approaches infinity and negative infinity are both 4. There is a horizontal asymptote at \(y = 4\).

Step by step solution

01

Determine the highest power terms

In this rational function \(f(x)=\frac{12 x^{8}-3}{3 x^{8}-2 x^{7}}\), we identify the highest power terms in both the numerator and the denominator. The highest power term in the numerator is \(12x^8\) and the highest power term in the denominator is \(3x^8\).
02

Divide both numerator and denominator by the highest power of x

To find the limits, we divide both the numerator and the denominator of the rational function by \(x^8\). This helps to simplify the function and makes it easier to evaluate the limits. $$ f(x) = \frac{\frac{12 x^{8}}{x^8} - \frac{3}{x^8}}{\frac{3 x^{8}}{x^8} - \frac{2 x^{7}}{x^8}} = \frac{12 - \frac{3}{x^8}}{3 - \frac{2}{x}} $$
03

Evaluate limits as x approaches infinity and negative infinity

Now we will find the limits as x approaches infinity and negative infinity: $$ \lim_{x \rightarrow \infty} f(x) = \frac{12 - \frac{3}{x^8}}{3 - \frac{2}{x}} \\ \lim_{x \rightarrow -\infty} f(x) = \frac{12 - \frac{3}{x^8}}{3 - \frac{2}{x}} $$ As \(x\) becomes infinitely large or infinitely small (negative), the terms \(\frac{3}{x^8}\) and \(\frac{2}{x}\) will approach 0, so both these limits simplify to: $$ \lim_{x \rightarrow \infty} f(x) = \frac{12}{3} \\ \lim_{x \rightarrow -\infty} f(x) = \frac{12}{3} $$
04

Compute the limits

Compute the limits: $$ \lim_{x \rightarrow \infty} f(x) = 4 \\ \lim_{x \rightarrow -\infty} f(x) = 4 $$
05

Determine Horizontal Asymptotes

Since the limits as x approaches both infinity and negative infinity are the same, there is a horizontal asymptote at \(y=4\). The horizontal asymptote of the given rational function is \(y = 4\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Horizontal Asymptotes
When it comes to understanding the long-term behavior of rational functions like the one given in the exercise, horizontal asymptotes are key. A horizontal asymptote is a horizontal line that the graph of the function approaches as the input, or x-value, either increases without bound (heads towards positive infinity) or decreases without bound (heads towards negative infinity).

In mathematical terms, if the limit of a function f(x) as x approaches infinity or negative infinity is a constant value L, then the line y = L is a horizontal asymptote of f(x). The existence of a horizontal asymptote helps us predict the function's behavior far from the origin. It does not, however, mean that the function necessarily touches the asymptote; it might just get closer and closer indefinitely.

In the given exercise, the horizontal asymptote of the function is y = 4. This is deduced by calculating the limits at infinity and negative infinity and finding they both yield the same constant value.
Limit at Infinity
Exploring the concept of limits at infinity provides insight into the end-behavior of a function like the one in the exercise. In simple terms, the limit at infinity asks: as we let x grow larger and larger without bound, what value does f(x) approach? Similarly, the limit at negative infinity would consider the value that f(x) approaches as x becomes more and more negative.

In our exercise, we determined that as x approaches both positive and negative infinity, the function f(x) approaches 4. It's crucial to note that when x is large enough, the terms with lower powers of x within the function become insignificant compared to the highest power terms, which dominate the behavior of the function. Thus, by approximating the function at extremes (very large or very negative x), we can often find a simple, constant limit.
Highest Power Terms
Identifying the highest power terms in the numerator and denominator of a rational function is a critical step in determining its limits at infinity. The rationale behind this is that the highest power terms dictate the behavior of the function as x grows very large or very large in the negative sense.

By focusing on the highest power of x present in both the numerator and the denominator—an approach used in our step-by-step solution—we can often simplify the analysis. After dividing through by the highest power of x, the remaining terms with x in the denominator become negligible as x approaches infinity, since values like \(\frac{1}{x}\) or \(\frac{1}{x^2}\) approach zero. In our example, this meant simplifying \(\frac{12 x^8}{x^8}\) to 12 and \(\frac{3 x^8}{x^8}\) to 3. This simplification is key to easily identifying the limits at infinity and, consequently, any horizontal asymptotes.
Simplifying Rational Expressions
Simplifying rational expressions, much like we did with the example exercise, is an essential algebraic skill when dealing with limits of functions. Simplification can involve factoring, canceling common factors, or, as in this case, dividing by the highest power of x. The beauty of simplification is that it often reveals the function's core components that significantly impact its behavior, especially towards the extremes of its domain.

By simplifying the function, we make it more manageable and easier to analyze. In the context of limits, this often means clarity around what happens as x approaches infinity or negative infinity. As seen in our exercise, after simplification, the limits became much easier to evaluate, leading us directly to the horizontal asymptote without complication. This is why simplifying is not just a mathematical step; it's a conceptual tool that helps us peer into the heart of the function's behavior.

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Most popular questions from this chapter

Use the following definitions. Assume fexists for all \(x\) near a with \(x>\) a. We say the limit of \(f(x)\) as \(x\) approaches a from the right of a is \(L\) and write \(\lim _{x \rightarrow a^{+}} f(x)=L,\) if for any \(\varepsilon>0\) there exists \(\delta>0\) such that $$|f(x)-L|<\varepsilon \quad \text { whenever } \quad 0< x-a<\delta$$ Assume fexists for all \(x\) near a with \(x < \) a. We say the limit of \(f(x)\) as \(x\) approaches a from the left of a is \(L\) and write \(\lim _{x \rightarrow a^{-}} f(x)=L,\) if for any \(\varepsilon > 0 \) there exists \(\delta > 0\) such that $$|f(x)-L| < \varepsilon \quad \text { whenever } \quad 0< a-x <\delta$$ Prove that \(\lim _{x \rightarrow 0^{+}} \sqrt{x}=0\).

Use analytical methods and/or a graphing utility en identify the vertical asymptotes (if any) of the following functions. $$g(\theta)=\tan \frac{\pi \theta}{10}$$

A monk set out from a monastery in the valley at dawn. He walked all day up a winding path, stopping for lunch and taking a nap along the way. At dusk, he arrived at a temple on the mountaintop. The next day the monk made the return walk to the valley, leaving the temple at dawn, walking the same path for the entire day, and arriving at the monastery in the evening. Must there be one point along the path that the monk occupied at the same time of day on both the ascent and descent? (Hint: The question can be answered without the Intermediate Value Theorem.) (Source: Arthur Koestler, The Act of Creation.)

Calculate the following limits using the factorization formula \(x^{n}-a^{n}=(x-a)\left(x^{n-1}+x^{n-2} a+x^{n-3} a^{2}+\cdots+x a^{n-2}+a^{n-1}\right)\) where \(n\) is a positive integer and a is a real number. \(\lim _{x \rightarrow 1} \frac{x^{6}-1}{x-1}\)

Find the limit of the following sequences or state that the limit does not exist. $$\begin{aligned} &\left\\{4,2, \frac{4}{3}, 1, \frac{4}{5}, \frac{2}{3}, \ldots\right\\}, \text { which is defined by } f(n)=\frac{4}{n}, \text { for }\\\ &n=1,2,3, \ldots \end{aligned}$$

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