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Express the vector field \(\mathbf{F}=\langle x y, 0,0\rangle\) in the form \(\mathbf{V}+\mathbf{W},\) where \(\nabla \cdot \mathbf{V}=0\) and \(\nabla \times \mathbf{W}=\mathbf{0}\).

Short Answer

Expert verified
To express the vector field \(\mathbf{F}\) as the sum of two vector fields \(\mathbf{V}\) and \(\mathbf{W}\) with zero divergence and zero curl respectively, we first find \(\mathbf{V}=\langle 0, -x^2, 0\rangle\) which has zero divergence, and \(\mathbf{W}=\langle x y, 0, 0 \rangle\) which has zero curl. Then, we add these two vector fields together to obtain \(\mathbf{F} = \mathbf{V}+\mathbf{W} = \langle 0, -x^2, 0\rangle + \langle x y, 0, 0\rangle = \langle xy, -x^2, 0 \rangle\).

Step by step solution

01

Recall the Divergence

The divergence of a vector field \(\mathbf{V}=\langle P,Q,R\rangle\) in Cartesian coordinates is given by: $$\nabla \cdot \mathbf{V} = \frac{\partial P}{\partial x}+\frac{\partial Q}{\partial y}+\frac{\partial R}{\partial z}$$
02

Finding \(\mathbf{V}\) with Zero Divergence

Let \(\mathbf{V}=\langle P,Q,0\rangle\). Given that \(\nabla \cdot \mathbf{V}=0\), we have: $$\frac{\partial P}{\partial x}+\frac{\partial Q}{\partial y} = 0$$ We can choose \(P = 0\) and \(Q = -x^2\) to satisfy this equation. Hence, \(\mathbf{V}=\langle 0, -x^2, 0\rangle\). Step 2: Find a vector field with zero curl
03

Recall the Curl

The curl of a vector field \(\mathbf{W}=\langle A,B,C \rangle\) in Cartesian coordinates is given by: $$\nabla \times \mathbf{W} = \langle \frac{\partial C}{\partial y} - \frac{\partial B}{\partial z}, \frac{\partial A}{\partial z} - \frac{\partial C}{\partial x},\frac{\partial B}{\partial x} - \frac{\partial A}{\partial y}\rangle$$
04

Finding \(\mathbf{W}\) with Zero Curl

Let \(\mathbf{W}=\langle A,B,0 \rangle\). Given that \(\nabla \times \mathbf{W}=\mathbf{0}\), we need to have \(\frac{\partial B}{\partial x} - \frac{\partial A}{\partial y} = 0\). We can choose \(A = xy\) and \(B = 0\) to satisfy this equation. Hence, \(\mathbf{W}=\langle x y, 0, 0 \rangle\). Step 3: Express the vector field \(\mathbf{F}\) as the sum of \(\mathbf{V}\) and \(\mathbf{W}\)
05

Adding the Vector Fields

We have found the vector fields \(\mathbf{V}\) and \(\mathbf{W}\), now we simply need to add them together to express \(\mathbf{F}\) as the sum of these two fields: $$\mathbf{F} = \mathbf{V}+\mathbf{W} = \langle 0, -x^2, 0\rangle + \langle x y, 0, 0\rangle = \langle xy, -x^2, 0 \rangle$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Divergence
Divergence is a fundamental concept in vector calculus, which measures how much a vector field spreads out from a given point. If you picture a vector field as arrows in space, divergence at a point tells you how much these arrows are diverging or converging.
The divergence of a vector field \(\mathbf{V} = \langle P, Q, R \rangle\) in three-dimensional space is calculated using the formula:
  • \(abla \cdot \mathbf{V} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} + \frac{\partial R}{\partial z}\)
To find a vector field with zero divergence, we need the sum above to equal zero. This indicates that whatever enters a region also leaves it, leading to conservation inside the region. This property is essential in fields like fluid dynamics and electromagnetism because it represents incompressible flow or steady sources and sinks.
Curl
Curl is another key concept in vector calculus. It describes the rotation or the "twisting" force field and is denoted by \(abla \times \mathbf{W}\). Imagine a field of wind vectors, where the discrepancy in wind direction can create a rotational effect. That's what's being measured by the curl.
Mathematically, for a vector field \(\mathbf{W} = \langle A, B, C \rangle\), the curl is defined as:
  • \(abla \times \mathbf{W} = \langle \frac{\partial C}{\partial y} - \frac{\partial B}{\partial z}, \frac{\partial A}{\partial z} - \frac{\partial C}{\partial x}, \frac{\partial B}{\partial x} - \frac{\partial A}{\partial y} \rangle\)
When the curl equals zero, it means there's no net rotation at that point, indicating a conservative field. This is an important trait in forces like gravitational or electrostatic forces, where the potential energy depends only on the position and not the path taken.
Zero Curl
A vector field with zero curl is known as irrotational. In such fields, there is no rotational component; the circulation of the field around any closed loop is zero. An important implication of zero curl is that the field can be expressed as the gradient of some scalar potential.
In our exercise, to find a vector field with zero curl, \(\mathbf{W} = \langle xy, 0, 0 \rangle\), where the formula for curl gives us zero:
  • Check if \(\frac{\partial B}{\partial x} - \frac{\partial A}{\partial y} = 0\)
Since the condition satisfies, \(\mathbf{W}\) is indeed a vector field with zero curl. Understanding this concept helps delineate the kinds of vector fields encountered in physics, some of which have properties that make them uniquely important for mathematical analysis.
In applications, knowing whether a field is irrotational helps in simplifying and solving field-related problems, as it allows the use of potential functions to greatly ease calculations.

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Most popular questions from this chapter

The French physicist André-Marie Ampère \((1775-1836)\) discovered that an electrical current \(I\) in a wire produces a magnetic field \(\mathbf{B} .\) A special case of Ampère's Law relates the current to the magnetic field through the equation \(\oint_{C} \mathbf{B} \cdot d \mathbf{r}=\mu I,\) where \(C\) is any closed curve through which the wire passes and \(\mu\) is a physical constant. Assume that the current \(I\) is given in terms of the current density \(\mathbf{J}\) as \(I=\iint_{S} \mathbf{J} \cdot \mathbf{n} d S\) where \(S\) is an oriented surface with \(C\) as a boundary. Use Stokes' Theorem to show that an equivalent form of Ampère's Law is \(\nabla \times \mathbf{B}=\mu \mathbf{J}\)

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Prove Green's Second Identity for scalar-valued functions \(u\) and \(v\) defined on a region \(D\) : $$\iiint_{D}\left(u \nabla^{2} v-v \nabla^{2} u\right) d V=\iint_{S}(u \nabla v-v \nabla u) \cdot \mathbf{n} d S$$ (Hint: Reverse the roles of \(u\) and \(v\) in Green's First Identity.)

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