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Evaluate the line integral \(\oint_{C} \mathbf{F} \cdot d \mathbf{r}\) by evaluating the surface integral in Stokes Theorem with an appropriate choice of \(S\). Assume that Chas a counterclockwise orientation. \(\mathbf{F}=\langle y, x z,-y\rangle ; C\) is the ellipse \(x^{2}+y^{2} / 4=1\) in the plane \(z=1\)

Short Answer

Expert verified
Based on the solution above, we applied the Stokes' Theorem to evaluate the line integral of the given vector field and found that the line integral of the vector field around the closed curve C is equal to 0.

Step by step solution

01

Calculate the curl of the vector field

First, we will calculate the curl of the vector field \(\mathbf{F}\): $$\nabla \times \mathbf{F} = \left(\frac{\partial(-y)}{\partial y} - \frac{\partial(xz)}{\partial z}, \frac{\partial(y)}{\partial z} - \frac{\partial x}{\partial x}, \frac{\partial(xz)}{\partial x} - \frac{\partial y}{\partial y}\right) = \langle0, 0, z-1\rangle$$
02

Parameterize the surface S

Now, we need to parameterize the surface S bounded by the given ellipse. Since the ellipse lies in the plane \(z = 1\), a suitable parameterization would be: $$\mathbf{r}(u, v) = \langle u\cos{v}, 2u\sin{v}, 1\rangle, \quad (u, v): (0 \leq u \leq 1, 0 \leq v \leq 2\pi)$$ The partial derivatives of \(\mathbf{r}(u, v)\) with respect to \(u\) and \(v\) are: $$\frac{\partial \mathbf{r}}{\partial u} = \langle \cos{v}, 2\sin{v}, 0\rangle \quad \text{and} \quad \frac{\partial \mathbf{r}}{\partial v} = \langle -u\sin{v}, 2u\cos{v}, 0\rangle$$
03

Calculate the surface integral

Now we will calculate the surface integral of the curl of \(\mathbf{F}\): $$\begin{aligned} \iint_{S} (\nabla \times \mathbf{F}) \cdot d\mathbf{S} &= \iint_{S} \langle0, 0, z-1\rangle \cdot \left(\frac{\partial \mathbf{r}}{\partial u} \times \frac{\partial \mathbf{r}}{\partial v}\right) dudv \\ &= \iint_{(u, v): (0 \leq u \leq 1, 0 \leq v \leq 2\pi)} \langle0, 0, 1-1\rangle \cdot \left(\langle \cos{v}, 2\sin{v}, 0\rangle \times \langle -u\sin{v}, 2u\cos{v}, 0\rangle\right) dudv \\ &= \iint_{0 \leq u \leq 1, 0 \leq v \leq 2\pi} \langle0, 0, 0\rangle \cdot \langle 0, 0, 4u^2\cos^2{v} + 2u\sin^2{v}\rangle dudv \end{aligned}$$ Since we are taking the dot product of two vectors where one has components exclusively in the z-direction and the other has components exclusively in the x- and y-directions, the dot product is zero, and so the surface integral is equal to 0: $$\iint_{S} (\nabla \times \mathbf{F}) \cdot d\mathbf{S} = 0$$ Thus, the line integral is also equal to 0 by applying the Stokes' Theorem: $$\oint_{C} \mathbf{F} \cdot d \mathbf{r} = 0$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Line integral
In calculus, the line integral is a fundamental concept that involves integrating a vector field along a curve or path. It's represented by the notation \(\oint_{C} \mathbf{F} \. d \mathbf{r}\), where \(\mathbf{F}\) is a vector field and \(C\) is the path or curve along which the integral is taken. The line integral essentially sums up the work done by the force \(\mathbf{F}\) while moving along \(C\).

Imagine walking along a hilly path with varying wind directions and strengths; the line integral would help calculate the total effort you must exert to walk this path under the influence of the wind. In mathematics, it captures the cumulative effect of a vector field along a curve, which is pivotal in fields like electromagnetism and fluid dynamics.

In the context of the textbook exercise, the line integral \(\oint_{C} \mathbf{F} \. d \mathbf{r}\) is being evaluated using Stokes' Theorem, which provides a relation between the line integral around a closed curve \(C\) and a surface integral over the surface \(S\) bounded by \(C\).
Curl of a vector field
The curl is a vector operator that describes the infinitesimal rotation of a 3-dimensional vector field. In physical terms, if you visualize the vector field as the flow of a fluid, the curl measures the tendency of the fluid to rotate or swirl around a point.

Mathematically, the curl of a vector field \(\mathbf{F}\) is notated as \(abla \times \mathbf{F}\) and is a vector that points in the direction of the axis of rotation, with a magnitude that reflects the rate of rotation at a point. For example, if we think of \(\mathbf{F}\) as representing wind speeds, the curl would give us the local rotation of air (like a small tornado) at any given point.

In our given problem, the curl of \(\mathbf{F}\) is found to be \(\langle0, 0, z-1\rangle\), indicating that as \(z\) changes from the plane value, the rate of rotation changes, but there is no rotation in the \(x\) or \(y\) components.
Surface integral
A surface integral is the higher-dimensional analog of a line integral. It involves integrating over a surface in three dimensions rather than a curve. This integration is particularly helpful in physics and engineering when dealing with fields spreading out over an area, such as the flux of a magnetic or electric field through a surface.

Mathematically, the surface integral of a vector field \(\mathbf{F}\) over a surface \(S\) is expressed as \(\iint_{S} \mathbf{F} \. d\mathbf{S}\), where \(d\mathbf{S}\) represents a vector area element on the surface. Think of it as breaking down the surface into infinitesimally small patches, calculating the vector field's effect across each patch, and then summing up all these tiny effects to get the total.

In the exercise, we use the surface integral of the curl of \(\mathbf{F}\) over the surface \(S\) to evaluate the line integral through the application of Stokes' Theorem. The computed surface integral equals zero, reflecting that there is no net 'twisting' effect when accounting for the entire surface within the curve \(C\).
Vector field parameterization
Parameterization involves representing a vector field or a surface in terms of independent variables, often to simplify calculations such as integrals. In the case of vector field parameterization, each point of a surface is described by parameters—typically two for a surface in three-dimensional space.

For example, parametric equations for a sphere might use latitude and longitude as parameters. Each point on the sphere's surface is uniquely determined by these two values. Similarly, in the ellipse example from our exercise, the surface \(S\) in the plane \(z = 1\) is parameterized using \(u\) and \(v\), producing a family of vectors that describe every point on the ellipse as \(u\) and \(v\) range over their domains.

The parameterization \(\mathbf{r}(u, v) = \langle u\cos{v}, 2u\sin{v}, 1\rangle\) allows us to express the area element \(d\mathbf{S}\) needed for the surface integral in terms of \(du\) and \(dv\), making the integration process feasible. Ultimately, this calculated area under the vector field gives us insight into how \(\mathbf{F}\) behaves over the entire surface \(S\).

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Most popular questions from this chapter

Show that \(\left|\mathbf{t}_{u} \times \mathbf{t}_{v}\right|=a^{2} \sin u\) for a sphere of radius \(a\) defined parametrically by \(\mathbf{r}(u, v)=\langle a \sin u \cos v, a \sin u \sin v, a \cos u\rangle,\) where \(0 \leq u \leq \pi\) and \(0 \leq v \leq 2 \pi\).

One of Maxwell's equations for electromagnetic waves is \(\nabla \times \mathbf{B}=C \frac{\partial \mathbf{E}}{\partial t},\) where \(\mathbf{E}\) is the electric field, \(\mathbf{B}\) is the magnetic field, and \(C\) is a constant. a. Show that the fields $$\mathbf{E}(z, t)=A \sin (k z-\omega t) \mathbf{i} \quad \mathbf{B}(z, t)=A \sin (k z-\omega t) \mathbf{j}$$ satisfy the equation for constants \(A, k,\) and \(\omega,\) provided \(\omega=k / C\). b. Make a rough sketch showing the directions of \(\mathbf{E}\) and \(\mathbf{B}\).

Suppose that a surface \(S\) is defined as \(z=g(x, y)\) on a region \(R\). Show that \(\mathbf{t}_{x} \times \mathbf{t}_{y}=\left\langle-z_{x},-z_{y}, 1\right\rangle\) and that \(\iint_{S} f(x, y, z) d S=\iint_{R} f(x, y, z) \sqrt{z_{x}^{2}+z_{y}^{2}+1} d A\).

Prove the following identities. a. \(\iiint_{D} \nabla \times \mathbf{F} d V=\iint_{S}(\mathbf{n} \times \mathbf{F}) d S\) (Hint: Apply the Divergence Theorem to each component of the identity.) b. \(\iint_{S}(\mathbf{n} \times \nabla \varphi) d S=\oint_{C} \varphi d \mathbf{r}\) (Hint: Apply Stokes' Theorem to each component of the identity.)

The Navier-Stokes equation is the fundamental equation of fluid dynamics that models the flow in everything from bathtubs to oceans. In one of its many forms (incompressible, viscous flow), the equation is $$\rho\left(\frac{\partial \mathbf{V}}{\partial t}+(\mathbf{V} \cdot \nabla) \mathbf{V}\right)=-\nabla p+\mu(\nabla \cdot \nabla) \mathbf{V}.$$ In this notation, \(\mathbf{V}=\langle u, v, w\rangle\) is the three-dimensional velocity field, \(p\) is the (scalar) pressure, \(\rho\) is the constant density of the fluid, and \(\mu\) is the constant viscosity. Write out the three component equations of this vector equation. (See Exercise 40 for an interpretation of the operations.)

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