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Determine whether the following vector fields are conservative on \(\mathbb{R}^{2}\). $$\mathbf{F}=\langle-y,-x\rangle$$

Short Answer

Expert verified
Based on the given vector field \(\mathbf{F}=\langle-y,-x\rangle\), we calculated its curl and found it to be zero. Therefore, the vector field is conservative on \(\mathbb{R}^2\).

Step by step solution

01

Find the partial derivatives of the components

To calculate the curl of a vector field in \(\mathbb{R}^2\), we need to find the partial derivatives of the components with respect to both x and y. The components of the given vector field are \(F_{1}=-y\) and \(F_{2}=-x\). So we need to find: $$\frac{\partial F_{1}}{\partial x}, \frac{\partial F_{1}}{\partial y}, \frac{\partial F_{2}}{\partial x}, \frac{\partial F_{2}}{\partial y}$$ Let's calculate the partial derivatives one by one: $$\frac{\partial F_{1}}{\partial x} = \frac{\partial (-y)}{\partial x} = 0$$ $$\frac{\partial F_{1}}{\partial y} = \frac{\partial (-y)}{\partial y} = -1$$ $$\frac{\partial F_{2}}{\partial x} = \frac{\partial (-x)}{\partial x} = -1$$ $$\frac{\partial F_{2}}{\partial y} = \frac{\partial (-x)}{\partial y} = 0$$
02

Calculate the curl of the vector field

Now, we will calculate the curl of the vector field \(\mathbf{F}\). For a vector field in \(\mathbb{R}^2\), it is defined as: $$ curl(\mathbf{F}) = \frac{\partial F_{2}}{\partial x} - \frac{\partial F_{1}}{\partial y}$$ Substituting the computed partial derivatives, we get: $$curl(\mathbf{F})= (-1) - (-1) = 0$$
03

Determine whether the vector field is conservative

Since the curl of the vector field is zero, we can conclude that the given vector field is conservative on \(\mathbb{R}^2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Derivatives
Partial derivatives are a fundamental concept in multivariable calculus. They represent how a function changes as one of its variables is varied, holding the others constant. In essence, partial derivatives give us the rate of change of functions with respect to each variable independently.

For example, if we have a function of two variables, say, \(z=f(x,y)\), the partial derivative of \(z\) with respect to \(x\), denoted by \(\frac{\partial z}{\partial x}\), tells us how much \(z\) changes when \(x\) is increased by an infinitesimally small amount, while keeping \(y\) constant. Similarly, \(\frac{\partial z}{\partial y}\) measures change with respect to \(y\).

Understanding partial derivatives is crucial because they are used in various applications such as calculating the gradient of a function or finding where a function has a maximum or minimum value. In the context of the exercise, they are the building blocks to determine the curl of a vector field in two dimensions.
Curl of a Vector Field
The curl of a vector field is a measure of the rotation of the field at a point. In three dimensions, curl is itself a vector that describes the axis of rotation and the magnitude of the rotation. However, in two dimensions, things are a bit simpler - the curl is a single scalar value.

In \(\mathbb{R}^2\), the curl of a vector field \(\mathbf{F} = \langle F_{1}, F_{2} \rangle\) is defined as \(\frac{\partial F_{2}}{\partial x} - \frac{\partial F_{1}}{\partial y}\). It is essentially the difference between the partial derivative of the second component with respect to \(x\) and the first component with respect to \(y\). When this value is zero, it implies that there is no net 'twisting' effect at any point in the field, and therefore, the vector field is potentially conservative.

A conservative vector field has the important property that its line integral is path-independent, which means that the work done in moving along different paths between the same points is the same. This concept is integral in physics, particularly in the study of fields like electromagnetism and fluid dynamics.
Vector Field in \(\mathbb{R}^2\)
A vector field in \(\mathbb{R}^2\) is a function that assigns a two-dimensional vector to every point in a plane. The vectors can represent many different things, like velocity in fluid flow or force in a physical system. Physically, you can think of a vector field as a way to represent various forces acting at different points in space.

For the given exercise, we are analyzing the vector field \(\mathbf{F}=\langle -y, -x \rangle\). Visualizing this field, you might imagine a series of arrows pointing in various directions with their magnitude and orientation varying across the plane. This specific vector field \(\mathbf{F}\) is particularly interesting because it provides us with a classic example of a field that has rotational symmetry about the origin.

Understanding the nature of vector fields in \(\mathbb{R}^2\) is essential for several branches of science and engineering. The concept we used to determine whether the field is conservative, involving partial derivatives and the curl, provides a gateway to more advanced studies in vector calculus and its numerous applications.

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Most popular questions from this chapter

The goal is to evaluate \(A=\iint_{S}(\nabla \times \mathbf{F}) \cdot \mathbf{n} d S,\) where \(\mathbf{F}=\langle y z,-x z, x y\rangle\) and \(S\) is the surface of the upper half of the ellipsoid \(x^{2}+y^{2}+8 z^{2}=1(z \geq 0)\) a. Evaluate a surface integral over a more convenient surface to find the value of \(A\) b. Evaluate \(A\) using a line integral.

The heat flow vector field for conducting objects is \(\mathbf{F}=-k \nabla T,\) where \(T(x, y, z)\) is the temperature in the object and \(k>0\) is a constant that depends on the material. Compute the outward flux of \(\mathbf{F}\) across the following surfaces S for the given temperature distributions. Assume \(k=1\). \(T(x, y, z)=-\ln \left(x^{2}+y^{2}+z^{2}\right) ; S\) is the sphere \(x^{2}+y^{2}+z^{2}=a^{2}\).

a. Let \(\mathbf{a}=\langle 0,1,0\rangle, \mathbf{r}=\langle x, y, z\rangle,\) and consider the rotation field \(\mathbf{F}=\mathbf{a} \times \mathbf{r} .\) Use the right-hand rule for cross products to find the direction of \(\mathbf{F}\) at the points (0,1,1),(1,1,0),(0,1,-1), and (-1,1,0). b. With \(\mathbf{a}=\langle 0,1,0\rangle,\) explain why the rotation field \(\mathbf{F}=\mathbf{a} \times \mathbf{r}\) circles the \(y\) -axis in the counterclockwise direction looking along a from head to tail (that is, in the negative \(y\) -direction).

Use Stokes' Theorem to find the circulation of the following vector fields around any simple closed smooth curve \(C\). $$\mathbf{F}=\langle 2 x,-2 y, 2 z\rangle$$

Let \(R\) be a region in a plane that has a unit normal vector \(\mathbf{n}=\langle a, b, c\rangle\) and boundary \(C .\) Let \(\mathbf{F}=\langle b z, c x, a y\rangle\) a. Show that \(\nabla \times \mathbf{F}=\mathbf{n}\) b. Use Stokes' Theorem to show that $$\operatorname{area} \text { of } R=\oint_{C} \mathbf{F} \cdot d \mathbf{r}$$ c. Consider the curve \(C\) given by \(\mathbf{r}=\langle 5 \sin t, 13 \cos t, 12 \sin t\rangle\) for \(0 \leq t \leq 2 \pi .\) Prove that \(C\) lies in a plane by showing that \(\mathbf{r} \times \mathbf{r}^{\prime}\) is constant for all \(t\) d. Use part (b) to find the area of the region enclosed by \(C\) in part (c). (Hint: Find the unit normal vector that is consistent with the orientation of \(C\).)

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