/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 58 Mass from density Find the mass ... [FREE SOLUTION] | 91Ó°ÊÓ

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Mass from density Find the mass of the following solids with the given density functions. Note that density is described by the function \(f\) to avoid confusion with the radial spherical coordinate \(\rho\). The solid cone \(\\{(r, \theta, z): 0 \leq z \leq 4,0 \leq r \leq \sqrt{3} z\) \(0 \leq \theta \leq 2 \pi\\}\) with a density \(f(r, \theta, z)=5-z\)

Short Answer

Expert verified
Answer: The mass of the solid cone is \(48\pi\).

Step by step solution

01

Convert the Density Function to Cylindrical Coordinates

Given the density function \(f(r, \theta, z) = 5 - z\), we don't need to change anything as it is already in cylindrical coordinates.
02

Set Up the Triple Integral

We'll set up the triple integral with respect to volume in cylindrical coordinates: $$ \text{Mass} = \int\int\int f(r, \theta, z)\, dV = \int_{0}^{4}\int_{0}^{\sqrt{3} z}\int_{0}^{2 \pi}(5 - z) r\, d\theta\, dr\, dz $$
03

Compute the \(\theta\) Integral

First, we will compute the \(\theta\) integral: $$ \int_{0}^{2\pi}(5 - z)r\, d\theta = (5 - z)r\theta\bigg|_{0}^{2\pi} = 2\pi r(5 - z) $$
04

Compute the \(r\) Integral

Now, we will compute the \(r\) integral: $$ \int_{0}^{\sqrt{3} z} 2\pi r(5 - z)\, dr = \pi (5z - z^2)r^2\bigg|_{0}^{\sqrt{3} z} = 3\pi z^3 $$
05

Compute the \(z\) Integral

Lastly, we will compute the \(z\) integral: $$ \int_{0}^{4}3\pi z^3\, dz = \frac{3}{4}\pi z^4\bigg|_{0}^{4} = 48\pi $$
06

Write the Final Answer

The mass of the solid cone is: $$ \text{Mass} = 48\pi $$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Triple Integrals
A triple integral is an extension of single and double integrals, and it allows us to calculate quantities over three-dimensional regions. This is particularly useful when dealing with volumes and other three-dimensional properties. The concept can be thought of as stacking many tiny volume elements, each with a value determined by a function, over a particular region.

When computing a triple integral, we integrate a function over a volume. These integrals are often represented in the form:\[\int\int\int f(x, y, z) \, dV\]where \(dV\) represents a differential volume element.
  • This volume element can vary depending on the coordinate system used, such as Cartesian, cylindrical, or spherical coordinates.
  • In our case with cylindrical coordinates, the volume element \(dV\) becomes \(r \, dz \, dr \, d\theta\).
  • We take the definite bounds of integration for each variable to define the limits of the region of integration.
  • Different order of integration variables can be chosen based on the geometry of the region and the simplicity it offers during calculation.
Triple integrals can help compute not only mass but also center of mass, moments of inertia, and other quantities over a three-dimensional region. In the problem above, the mass of a solid cone was determined using triple integration of the given density function over the specified region.
Cylindrical Coordinates
Cylindrical coordinates provide a useful alternative to Cartesian coordinates, especially when dealing with figures such as cylinders, cones, and other shapes where symmetry about a central axis is apparent. This system is essentially a blend between polar coordinates in a two-dimensional plane and Cartesian coordinates along the third dimension.

The cylindrical coordinates \((r, \theta, z)\) are expressed as:
  • \(r\) is the radial distance from the \(z\)-axis.
  • \(\theta\) is the angular coordinate around the \(z\)-axis, equivalent to the angle formed with respect to the positive \(x\)-axis in the \((x, y)\) plane.
  • \(z\) represents the height typically measured along the vertical \(z\)-axis.
This coordinate system can be extremely practical for solving integrals due to its simplification in symmetry, as is evident in the provided problem.

In the example of the cone:
  • The angular variable \(\theta\) ranged from 0 to \(2\pi\), covering the full circle around the \(z\)-axis.
  • The radial variable \(r\) was constrained by the relationship \(0 \leq r \leq \sqrt{3}z\), which describes the slant of the cone.
  • The vertical \(z\) variable extended from 0 to 4, standing for the cone's height.
Utilizing cylindrical coordinates made setting up and solving the triple integral more straightforward, given the cone's symmetrical shape about its central axis.
Density Function
Density functions play a crucial role in various fields, such as physics and engineering, where they define how a particular quantity (like mass, charge, etc.) is distributed within a body. In this case, the density function describes how mass is spread over the volume of a solid object.

For the exercise provided, the density function \(f(r, \theta, z) = 5 - z\) indicates how the density varies with the height (\(z\)) of the cone.
  • As \(z\) increases, the density decreases linearly from 5 to 1, indicating less mass towards the top of the cone.
  • Because the function is already provided in cylindrical coordinates, no conversion is necessary, simplifying the integration process.
To find the total mass of a solid, one expresses the mass as the integral of its density function over the region the solid occupies:\[\text{Mass} = \int\int\int f(r, \theta, z) \, dV\]This involves computing the triple integral by recognizing and using the limits and variables specific to the chosen coordinate system. Using this integral, we can analyze various structural and mechanical properties of materials and objects, as demonstrated in the given cone problem where mass is calculated via triple integration.

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Most popular questions from this chapter

An important integral in statistics associated with the normal distribution is \(I=\int_{-\infty}^{\infty} e^{-x^{2}} d x .\) It is evaluated in the following steps. a. Assume that $$\begin{aligned} I^{2} &=\left(\int_{-\infty}^{\infty} e^{-x^{2}} d x\right)\left(\int_{-\infty}^{\infty} e^{-y^{2}} d y\right) \\ &=\int_{-\infty}^{\infty} \int_{-\infty}^{\infty} e^{-x^{2}-y^{2}} d x d y \end{aligned}$$ where we have chosen the variables of integration to be \(x\) and \(y\) and then written the product as an iterated integral. Evaluate this integral in polar coordinates and show that \(I=\sqrt{\pi} .\) Why is the solution \(I=-\sqrt{\pi}\) rejected? b. Evaluate \(\int_{0}^{\infty} e^{-x^{2}} d x, \int_{0}^{\infty} x e^{-x^{2}} d x,\) and \(\int_{0}^{\infty} x^{2} e^{-x^{2}} d x\) (using part (a) if needed).

Use polar coordinates to find the centroid of the following constant-density plane regions. The region bounded by the cardioid \(r=1+\cos \theta\)

Intersecting spheres One sphere is centered at the origin and has a radius of \(R\). Another sphere is centered at \((0,0, r)\) and has a radius of \(r,\) where \(r>R / 2 .\) What is the volume of the region common to the two spheres?

Consider the following two-and three-dimensional regions. Specify the surfaces and curves that bound the region, choose a convenient coordinate system, and compute the center of mass assuming constant density. All parameters are positive real numbers. A solid is enclosed by a hemisphere of radius \(a\). How far from the base is the center of mass?

Determine whether the following statements are true and give an explanation or counterexample. a. Any point on the \(z\) -axis has more than one representation in both cylindrical and spherical coordinates. b. The sets \(\\{(r, \theta, z): r=z\\}\) and \(\\{(\rho, \varphi, \theta): \varphi=\pi / 4\\}\) are the same.

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