/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 80 Evaluate the following limits. ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Evaluate the following limits. $$\lim _{(x, y) \rightarrow(0, \pi / 2)} \frac{1-\cos x y}{4 x^{2} y^{3}}$$

Short Answer

Expert verified
Question: Evaluate the limit of the following function as (x, y) approaches (0, π/2): \(\frac{1 - \cos{(xy)}}{4x^2y^3}\). Answer: The limit does not exist.

Step by step solution

01

Identify the indeterminate form

When (x, y) approach (0, π/2), the given function becomes: \(\frac{1 - \cos{(0 \cdot \pi / 2)}}{4 \cdot 0^2 \cdot (\pi / 2)^3} = \frac{1 - \cos{0}}{4 \cdot 0^2 \cdot (\pi / 2)^3} = \frac{1 - 1}{0} = \frac{0}{0}\). This is indeed an indeterminate form.
02

Use trigonometric identity

We can use the trigonometric identity \(1 - \cos{x} = 2 \sin^2{\frac{x}{2}}\). Applying this, the given function becomes: \(\frac{2\sin^2{\frac{xy}{2}}}{4x^2y^3}\).
03

Simplify the function

We can simplify the function by dividing the numerator and denominator \(\frac{2\sin^2{\frac{xy}{2}}}{4x^2y^3} = \frac{\sin^2{\frac{xy}{2}}}{2x^2y^3}\)
04

Rewrite the function

We rewrite the function as \(\frac{\sin{\frac{xy}{2}}}{\frac{xy}{2}}\cdot\frac{\left(\frac{xy}{2}\right)^2}{2x^2y^3}\). Now we can recognize two key expressions.
05

Apply limit properties

Due to limit properties, we can evaluate the limit of the product of the functions as the product of the limits of the functions, by applying the limit to each of them. $$\lim _{(x, y) \rightarrow(0, \pi / 2)} \frac{\sin{\frac{xy}{2}}}{\frac{xy}{2}}\cdot\frac{\left(\frac{xy}{2}\right)^2}{2x^2y^3}$$
06

Evaluate the first limit

Using the standard limit \(\lim_{t \to 0} \frac{\sin{t}}{t} = 1\), we can evaluate the first part of the expression. $$\lim _{(x, y) \rightarrow(0, \pi / 2)} \frac{\sin{\frac{xy}{2}}}{\frac{xy}{2}} = 1$$
07

Evaluate the second limit

The second part is a simple limit with substitution. $$\lim _{(x, y) \rightarrow(0, \pi / 2)} \frac{\left(\frac{xy}{2}\right)^2}{2x^2y^3} = \frac{\left(\frac{0 \cdot \pi / 2}{2}\right)^2}{2 \cdot 0^2 \cdot (\pi / 2)^3} = \frac{0}{0}$$
08

Conclude the final answer

Since the limit of the second part is indeterminate, we cannot evaluate the final result. The limit does not exist.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Indeterminate Forms
Indeterminate forms occur when evaluating limits and the resulting expression takes on an undefined or ambiguous form. The most common indeterminate forms are \( \frac{0}{0} \) and \( \frac{\infty}{\infty} \). These forms suggest that if you directly substitute into the function, you get a division by zero or a misleading infinity operation.
To resolve indeterminate forms, you need additional algebraic manipulation or known mathematical techniques, like L'Hôpital's rule, factoring, or other limit properties, which can help you interpret these expressions.
In our exercise example, as \((x, y)\) approaches \((0, \frac{\pi}{2})\), the function simplifies to the indeterminate form \( \frac{0}{0} \). This signals the necessity to further analyze and manipulate the expression to find any potential limits that might exist.
Trigonometric Limits
Working with trigonometric limits can be especially tricky because trigonometric functions often don't behave intuitively at certain limits. However, trigonometric identities and limits are powerful tools here.
One important identity is \(1 - \cos x = 2 \sin^2{\frac{x}{2}}\). For tackling trigonometric limits, using such identities can simplify complex expressions considerably. In this exercise, transforming \(1 - \cos xy\) into \(2 \sin^2\frac{xy}{2}\) facilitates the breakdown of the limit problem into more manageable parts.
Moreover, a particularly useful standard trigonometric limit is \(\lim_{t \to 0} \frac{\sin t}{t} = 1\). This limit helps in handling fractions involving sine terms, as seen when \( \sin{\frac{xy}{2}} \) is involved. It helps evaluate the behavior of sine at small values, streamlining the computation of such limits in multivariable contexts.
Limit Laws
Limit laws are fundamental rules that allow us to evaluate limits for more complex functions through simpler, well-understood components. These laws provide a way to decompose a complex limit into parts that can be individually analyzed.
Key properties include the sum law, difference law, product law, and quotient law. For our problem, the product law is particularly relevant: it states that the limit of a product of functions is the product of their limits, provided the limits exist.
In our solution, this principle lets us separate the challenging problem into easier pieces. First, we evaluate the trigonometric component \( \frac{\sin{\frac{xy}{2}}}{\frac{xy}{2}} \), which becomes 1 as \((x, y) \to (0, \frac{\pi}{2})\), and then we assess the simpler remaining part. Unfortunately, the second part results in another indeterminate form \(\frac{0}{0}\), indicating that, after analysis, the initial limit evaluation leads to the conclusion that the limit does not exist.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use the definition of differentiability to prove that the following functions are differentiable at \((0,0) .\) You must produce functions \(\varepsilon_{1}\) and \(\varepsilon_{2}\) with the required properties. $$f(x, y)=x+y$$

Extending Exercise \(62,\) when three electrical resistors with resistance \(R_{1}>0, R_{2}>0,\) and \(R_{3}>0\) are wired in parallel in a circuit (see figure), the combined resistance \(R,\) measured in ohms \((\Omega),\) is given by \(\frac{1}{R}=\frac{1}{R_{1}}+\frac{1}{R_{2}}+\frac{1}{R_{3}}\) Estimate the change in \(R\) if \(R_{1}\) increases from \(2 \Omega\) to \(2.05 \Omega, R_{2}\) decreases from \(3 \Omega\) to \(2.95 \Omega,\) and \(R_{3}\) increases from \(1.5 \Omega\) to \(1.55 \Omega.\)

Identify and briefly describe the surfaces defined by the following equations. $$y=x^{2} / 6+z^{2} / 16$$

A function of one variable has the property that a local maximum (or minimum) occurring at the only critical point is also the absolute maximum (or minimum) (for example, \(f(x)=x^{2}\) ). Does the same result hold for a function of two variables? Show that the following functions have the property that they have a single local maximum (or minimum), occurring at the only critical point, but that the local maximum (or minimum) is not an absolute maximum (or minimum) on \(\mathbb{R}^{2}\). a. \(f(x, y)=3 x e^{y}-x^{3}-e^{3 y}\) b. \(f(x, y)=\left(2 y^{2}-y^{4}\right)\left(e^{x}+\frac{1}{1+x^{2}}\right)-\frac{1}{1+x^{2}}\) This property has the following interpretation. Suppose that a surface has a single local minimum that is not the absolute minimum. Then water can be poured into the basin around the local minimum and the surface never overflows, even though there are points on the surface below the local minimum. (Source: Mathematics Magazine, May 1985, and Calculus and Analytical Geometry, 2nd ed., Philip Gillett, 1984)

The density of a thin circular plate of radius 2 is given by \(\rho(x, y)=4+x y .\) The edge of the plate is described by the parametric equations \(x=2 \cos t, y=2 \sin t,\) for \(0 \leq t \leq 2 \pi\) a. Find the rate of change of the density with respect to \(t\) on the edge of the plate. b. At what point(s) on the edge of the plate is the density a maximum?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.