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What is the name of the surface defined by the equation \(y=\frac{x^{2}}{4}+\frac{z^{2}}{8} ?\)

Short Answer

Expert verified
Answer: The surface represented by the equation is an elliptical paraboloid.

Step by step solution

01

Identify the type of equation

The given equation is \(y=\frac{x^{2}}{4}+\frac{z^{2}}{8}\). It is expressed in terms of \(x, y\), and \(z\). We notice that the \(x\) and \(z\) terms are squared, which means the surface will have a parabolic shape in these dimensions.
02

Analyze the coefficients of the squared terms

The coefficients of the squared terms will affect the "width" of the parabolic shape in the corresponding dimensions. In this case, we have coefficients \(4\) for \(x^{2}\) and \(8\) for \(z^{2}\). Higher coefficients will result in a narrower parabolic shape, while lower coefficients will result in a wider parabolic shape.
03

Identify the type of surface

Based on the analysis of the equation and the coefficients of the squared terms, we can conclude that the given surface is a paraboloid. Specifically, the surface is an elliptical paraboloid, because the coefficients of the squared terms are different in each dimension. If the coefficients were equal, it would be a circular paraboloid.
04

Final Answer

The surface defined by the equation \(y=\frac{x^{2}}{4}+\frac{z^{2}}{8}\) is an elliptical paraboloid.

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Most popular questions from this chapter

Let \(R\) be a closed bounded region in \(\mathbb{R}^{2}\) and let \(f(x, y)=a x+b y+c,\) where \(a, b\) and \(c\) are real numbers, with \(a\) and \(b\) not both zero. Give a geometrical argument explaining why the absolute maximum and minimum values of \(f\) over \(R\) occur on the boundaries of \(R\).

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