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Limits at (0,0) may be easier to evaluate by converting to polar coordinates. Remember that the same limit must be obtained as \(r \rightarrow 0\) along all paths in the domain to (0, 0). Evaluate the following limits or state that they do not exist. $$\lim _{(x, y) \rightarrow(0,0)} \frac{x^{2}+y^{2}+x^{2} y^{2}}{x^{2}+y^{2}}$$

Short Answer

Expert verified
$$\lim _{(x, y) \rightarrow(0,0)} \frac{x^{2}+y^{2}+x^{2}y^{2}}{x^{2}+y^{2}}$$ Answer: The limit of the given function as (x, y) approaches (0, 0) is 1.

Step by step solution

01

Convert to polar coordinates

To convert to polar coordinates, substitute \(x = r\cos(\theta)\) and \(y = r\sin(\theta)\), where \(r \geq 0\) and \(\theta\) is the angle in the plane with \(-\pi \leq \theta \leq \pi\). The given expression can be written as: $$f(x,y) = \frac{r^2(\cos^2(\theta) + \sin^2(\theta)) + r^4\cos^2(\theta)\sin^2(\theta)}{r^2(\cos^2(\theta)+\sin^2(\theta))}$$
02

Simplify the expression in polar coordinates

We know that \(\cos^2(\theta) + \sin^2(\theta) = 1\). Therefore, the given expression simplifies to: $$f(r,\theta) = \frac{r^2 + r^4\cos^2(\theta)\sin^2(\theta)}{r^2}$$ Now, divide the numerator and the denominator by \(r^2\) (since \(r\neq 0\)): $$f(r,\theta) = 1 + r^2\cos^2(\theta)\sin^2(\theta)$$
03

Evaluate limit as r approaches 0

We'll now evaluate the limit as r approaches 0 for the simplified expression: $$\lim _{r \rightarrow 0} \left(1 + r^2\cos^2(\theta)\sin^2(\theta)\right)$$ Since \(r^2 \geq 0\), and \(\cos^2(\theta)\sin^2(\theta) \geq 0\), their product is non-negative. As \(r\) approaches 0, \(r^2\) approaches 0. Hence, the limit is: $$\lim _{r \rightarrow 0} \left(1 + r^2\cos^2(\theta)\sin^2(\theta)\right) = 1$$ This limit is the same along all paths; thus, the given limit exists and is equal to 1. So, $$\lim _{(x, y) \rightarrow(0,0)} \frac{x^{2}+y^{2}+x^{2} y^{2}}{x^{2}+y^{2}}= 1$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polar Coordinates
Polar coordinates provide an alternative to Cartesian (rectangular) coordinates for representing points on a plane. While Cartesian coordinates utilize a grid of horizontal and vertical lines to describe the location of a point, polar coordinates do so with a combination of an angle and distance from a central point known as the origin.

For any point on the plane, its polar coordinates \( (r, \theta) \) consist of the radius \( r \)—the distance from the origin—and the angle \( \theta \)—which is measured from the positive x-axis. The conversions between Cartesian and polar coordinates are given by the equations \( x = r\cos(\theta) \) and \( y = r\sin(\theta) \) for polar to Cartesian, and \( r = \sqrt{x^2 + y^2} \) and \( \theta = \tan^{-1}(\frac{y}{x}) \) for Cartesian to polar.

This system is particularly useful when dealing with equations or problems that are naturally circular or have radial symmetry, as it often simplifies the computations.
Limit Evaluation
In calculus, the concept of a limit is essential for understanding the behavior of functions as they approach a certain point or as their input approaches a particular value. Limit evaluation in multivariable calculus, such as when dealing with polar coordinates, often examines the behavior of a function as it approaches a central point, like the origin.

The limit of a function \( f(x, y) \) as \( (x, y) \) approaches a point \( (a, b) \) is the value that \( f(x, y) \) gets closer to as the variables \( x \) and \( y \) get arbitrarily close to \( a \) and \( b \) respectively. The existence of the limit depends on the function returning the same value regardless of the path taken towards the point \( (a, b) \)—a particularly important consideration in multivariable calculus. If the limit exists and is the same along all paths, the function is said to be continuous at that point.
Multivariable Calculus
Multivariable calculus extends the principles of calculus to functions of multiple variables. Unlike in single-variable calculus, where functions take a number and produce another number, functions in multivariable calculus take a vector of numbers and produce a number.

One of the core topics in multivariable calculus is the concept of limits, which can be more complex than in the single-variable case due to the possibility of approaching a point from infinitely many paths in the domain of the function. Polar coordinates are often used in this branch of calculus to handle problems involving curves and areas that are circular or radial in nature. By using polar coordinates, certain types of multivariable limits become easier to evaluate, as the symmetries of the functions often become more apparent.
Simplifying Expressions
In mathematics, simplifying expressions is a process used to rewrite expressions in a more concise, useful, or standard form without changing the value they represent. The goal of simplification is to make complex equations easier to understand and solve.

In the process of simplifying expressions, one applies a variety of algebraic rules, such as distributive, associative, and commutative properties. For functions in polar coordinates, trigonometric identities like \( \cos^2(\theta) + \sin^2(\theta) = 1 \) are particularly useful. This identity, for instance, helps reduce the complexity of multivariable functions involving trigonometric terms, and is utilized to evaluate limits more straightforwardly. By expressing the function in simpler terms, the behavior as it approaches a particular point can be more easily deduced.

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Most popular questions from this chapter

Generalize Exercise 75 by considering a wave described by the function \(z=A+\sin (a x-b y)\) where \(a, b,\) and \(A\) are real numbers. a. Find the direction in which the crests and troughs of the wave are aligned. Express your answer as a unit vector in terms of \(a\) and \(b\) b. Find the surfer's direction - that is, the direction of steepest descent from a crest to a trough. Express your answer as a unit vector in terms of \(a\) and \(b\)

Imagine a string that is fixed at both ends (for example, a guitar string). When plucked, the string forms a standing wave. The displacement \(u\) of the string varies with position \(x\) and with time \(t .\) Suppose it is given by \(u=f(x, t)=2 \sin (\pi x) \sin (\pi t / 2),\) for \(0 \leq x \leq 1\) and \(t \geq 0\) (see figure). At a fixed point in time, the string forms a wave on [0, 1]. Alternatively, if you focus on a point on the string (fix a value of \(x\) ), that point oscillates up and down in time. a. What is the period of the motion in time? b. Find the rate of change of the displacement with respect to time at a constant position (which is the vertical velocity of a point on the string). c. At a fixed time, what point on the string is moving fastest? d. At a fixed position on the string, when is the string moving fastest? e. Find the rate of change of the displacement with respect to position at a constant time (which is the slope of the string). f. At a fixed time, where is the slope of the string greatest?

Find the maximum value of \(x_{1}+x_{2}+x_{3}+x_{4}\) subject to the condition that \(x_{1}^{2}+x_{2}^{2}+x_{3}^{2}+x_{4}^{2}=16\).

Given positive numbers \(x_{1}, \ldots, x_{n},\) prove that the geometric mean \(\left(x_{1} x_{2} \cdots x_{n}\right)^{1 / n}\) is no greater than the arithmetic mean \(\left(x_{1}+\cdots+x_{n}\right) / n\) in the following cases. a. Find the maximum value of \(x y z,\) subject to \(x+y+z=k\) where \(k\) is a real number and \(x>0, y>0\), and \(z>0 .\) Use the result to prove that $$(x y z)^{1 / 3} \leq \frac{x+y+z}{3}.$$ b. Generalize part (a) and show that $$\left(x_{1} x_{2} \cdots x_{n}\right)^{1 / n} \leq \frac{x_{1}+\cdots+x_{n}}{n}.$$

Identify and briefly describe the surfaces defined by the following equations. $$z^{2}+4 y^{2}-x^{2}=1$$

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