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Consider the following equations of quadric surfaces. a. Find the intercepts with the three coordinate axes, when they exist. b. Find the equations of the x y-, x z^{-}, \text {and } y z-\text {traces, when they exist. c. Sketch a graph of the surface. $$x=y^{2}+z^{2}$$

Short Answer

Expert verified
Answer: The equation represents a paraboloid opening in the positive x-direction. The intercepts with the coordinate axes are all at the origin (0,0,0).

Step by step solution

01

Find intercepts with the coordinate axes

To find intercepts, we set two of the variables to zero and solve for the remaining variable. Here, we find the x, y, and z intercepts: For the x-intercept, let y = 0 and z = 0: $$x = (0)^2 + (0)^2 = 0$$ x-intercept: (0,0,0) For the y-intercept, let x = 0 and z = 0: $$0 = y^2 + (0)^2$$ $$y = \pm \sqrt{0} = 0$$ y-intercept: (0,0,0) For the z-intercept, let x = 0 and y = 0: $$0 = (0)^2 + z^2$$ $$z = \pm \sqrt{0} = 0$$ z-intercept: (0,0,0)
02

Find the equations of traces

To find the traces of the function, we set one of the variables to a constant, usually called "c", and solve for the other two variables. 1. x, y-trace (let z = c): $$x = y^2 + c^2$$ 2. x, z-trace (let y = c): $$x = c^2 + z^2$$ 3. y, z-trace (let x = c): $$c = y^2 + z^2$$
03

Sketch a graph of the surface

To sketch the graph, we can observe that the surface is a paraboloid opening in the positive x-direction since x is equal to the sum of the squares of y and z. Since the traces are all parabolas or circles and the intercepts are all at the origin, we can sketch the surface as a paraboloid opening in the positive x-direction, centered at the origin.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coordinate Axes Intercepts
When examining quadric surfaces, knowing where they intersect the axes can be crucial. These points are known as the "intercepts." To find them, we set two of the three variables to zero and solve for the remaining one. This method isolates the intercepts on each axis and gives us valuable insight into the behavior of the surface at the origin.

In the equation \(x = y^2 + z^2\), let's explore the intercepts:
  • **X-intercept:** Setting \(y = 0\) and \(z = 0\) results in \(x = 0^2 + 0^2 = 0\). Hence, the x-intercept is \((0, 0, 0)\).
  • **Y-intercept:** Setting \(x = 0\) and \(z = 0\) gives \(0 = y^2\). Solving this, \(y = 0\), so the y-intercept is \((0, 0, 0)\).
  • **Z-intercept:** Similarly, setting \(x = 0\) and \(y = 0\) results in \(0 = z^2\), or \(z = 0\). Thus, the z-intercept is also \((0, 0, 0)\).
In this case, all intercepts lie at the origin, which is typical for centered quadric surfaces.
Coordinate Traces
Coordinate traces help visualize quadric surfaces by showing the cross sections formed when slicing the surface parallel to the coordinate planes. Traces effectively "slice" the 3D graph, simplifying it to 2D shapes that can be easier to analyze.

For the function \(x = y^2 + z^2\), here are the traces:
  • **XY-trace:** By setting \(z = c\) (a constant), we get \(x = y^2 + c^2\), which represents a parabola's equation in the xy-plane.
  • **XZ-trace:** By setting \(y = c\), we find \(x = c^2 + z^2\), another parabola but in the xz-plane.
  • **YZ-trace:** Setting \(x = c\) gives us \(c = y^2 + z^2\), a circle centered at the origin with radius \(\sqrt{c}\) in the yz-plane.
Each trace reveals different aspects of the surface's shape. Parabolas illustrate the curved nature, while the circle indicates symmetry about the chosen axis.
Paraboloid Sketching
Sketching a paraboloid can offer clarity on its spatial orientation and dimensions. In the given equation \(x = y^2 + z^2\), you can see it forms a paraboloid, a 3D structure that resembles a U-shape extending infinitely.

Paraboloids can open along different axes, and in this case, the paraboloid opens in the positive x-direction because \(x\) is expressed as a function of \(y^2\) and \(z^2\). Here are a few steps to aid in sketching:
  • Identify the axis of symmetry. For our equation, it's the x-axis.
  • Note that the vertex of the paraboloid is at the origin \((0,0,0)\).
  • Since the traces are parabolas and circles, you should depict these traces when sketching.
Begin by drawing the general outline—a "bowl" shape pointing along the x-axis—with parabolic profiles when viewed from the side. Keep symmetry in mind as you reflect the shape across the yz-plane. Sketching in these elements can help you visualize the quadric surface accurately in 3D.

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Most popular questions from this chapter

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