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Assume that \(F(x, y, z(x, y))=0\) implicitly defines \(z\) as a differentiable function of \(x\) and \(y .\) Extend Theorem 12.9 to show that $$\frac{\partial z}{\partial x}=-\frac{F_{x}}{F_{z}} \text { and } \frac{\partial z}{\partial y}=-\frac{F_{y}}{F_{z}}$$

Short Answer

Expert verified
Based on the information provided and the application of the implicit function theorem, we have found that the partial derivatives of the implicitly defined differentiable function \(z(x, y)\) with respect to \(x\) and \(y\) are: $$\frac{\partial z}{\partial x}=-\frac{F_{x}}{F_{z}} \text { and } \frac{\partial z}{\partial y}=-\frac{F_{y}}{F_{z}}$$

Step by step solution

01

1. Applying the implicit function theorem

We start by applying the implicit function theorem on the given function, \(F(x, y, z(x, y)) = 0\). According to the theorem, since \(F\) continuously differentiable and its partial derivative with respect to \(z\), namely \(F_{z}\), is nonzero, there exist continuous partial derivatives of \(z(x, y)\) with respect to \(x\) and \(y\). Next, we apply the chain rule on the implicit function to find the desired partial derivatives.
02

2. Partial differentiation with respect to x

To find \(\frac{\partial z}{\partial x}\), we differentiate \(F(x, y, z(x, y))\) with respect to \(x\), keeping \(y\) constant: $$\frac{\partial F}{\partial x} = \frac{\partial F}{\partial x}\frac{\partial x}{\partial x} + \frac{\partial F}{\partial y}\frac{\partial y}{\partial x} + \frac{\partial F}{\partial z}\frac{\partial z}{\partial x} = F_x + 0 + F_z\frac{\partial z}{\partial x}$$ Since \(F(x, y, z(x, y))=0\), the partial derivative with respect to \(x\) should also be zero: $$0 = F_x + F_z\frac{\partial z}{\partial x}$$ Now, we can algebraically solve for \(\frac{\partial z}{\partial x}\): $$\frac{\partial z}{\partial x}=-\frac{F_{x}}{F_{z}}$$
03

3. Partial differentiation with respect to y

To find \(\frac{\partial z}{\partial y}\), we differentiate \(F(x, y, z(x, y))\) with respect to \(y\), keeping \(x\) constant: $$\frac{\partial F}{\partial y} = \frac{\partial F}{\partial x}\frac{\partial x}{\partial y} + \frac{\partial F}{\partial y}\frac{\partial y}{\partial y} + \frac{\partial F}{\partial z}\frac{\partial z}{\partial y} = 0 + F_y + F_z\frac{\partial z}{\partial y}$$ Since \(F(x, y, z(x, y))=0\), the partial derivative with respect to \(y\) should also be zero: $$0 = F_y + F_z\frac{\partial z}{\partial y}$$ Now, we can algebraically solve for \(\frac{\partial z}{\partial y}\): $$\frac{\partial z}{\partial y}=-\frac{F_{y}}{F_{z}}$$ #Conclusion# By extending Theorem 12.9 and using the implicit function theorem, we have shown that the partial derivatives of \(z(x, y)\) with respect to \(x\) and \(y\) are: $$\frac{\partial z}{\partial x}=-\frac{F_{x}}{F_{z}} \text { and } \frac{\partial z}{\partial y}=-\frac{F_{y}}{F_{z}}$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Implicit Function Theorem
The implicit function theorem plays a crucial role in understanding how variables in equations relate to one another when the relationship is not given explicitly. It states that if we have an equation in the form of \( F(x, y, z) = 0 \) that involves a continuously differentiable function \( F \), and if the partial derivative with respect to \( z \), denoted \( F_z \), is non-zero, then near a point where these conditions hold, we can solve for \( z \) as a function of \( x \) and \( y \) — even if we don't have an explicit formula for \( z \). This theorem allows us to treat \( z \) as implicitly defined by \( x \) and \( y \) and perform differentiation on \( z \) as though it were an explicit function.

When the theorem is applied to the given equation \( F(x, y, z(x, y)) = 0 \), it tells us that the partial derivatives of \( z \) exist. This understanding is vital because it sets the stage for using other calculus tools, such as the chain rule, to find the actual values of these derivatives. To put it simply, the implicit function theorem is a gateway that lets us differentiate implicitly defined functions, which is particularly handy in many areas of mathematics and applied sciences.
Partial Derivatives
Partial derivatives are a foundational concept in multivariable calculus. They measure how a function changes in one direction, holding all other variables constant. When dealing with functions that have more than one variable, like \( F(x, y, z) \), it can be insightful to see how the function changes as we tweak just one of those variables, while keeping the others fixed. This is the essence of a partial derivative.

For example, the symbol \( F_x \) represents the partial derivative of \( F \) with respect to \( x \), meaning how \( F \) changes as \( x \) varies slightly with \( y \) and \( z \) held constant. When we say that \( F_x \) and \( F_y \) are involved in the calculation of \( \frac{\partial z}{\partial x} \) and \( \frac{\partial z}{\partial y} \), we're looking at how these partial changes contribute to the overall change in \( z \). Understanding partial derivatives is not only key in solving implicit differentiation problems like the given exercise but also in numerous applications across physics, engineering, and economics where multidimensional phenomena are studied.
Chain Rule
The chain rule is a rule in calculus that is used to find the derivative of the composition of two or more functions. It tells us that to differentiate a composite function, we multiply the derivative of the outer function by the derivative of the inner function. This concept becomes immensely important when we apply it to partial differentiation and implicit functions, as seen in our textbook exercise.

In the context of the exercise, where we have \( F(x, y, z(x, y)) = 0 \), the chain rule allows us to break down the change in \( F \) when \( x \) is varied into its constituent parts: how \( F \) changes directly with \( x \), how it changes as \( y \) changes, and importantly, how \( F \) changes through its relationship with \( z \), which in turn changes with \( x \). This layered approach, where the chain rule manages to parse through the intertwined variable changes, is what enables us to express \( \frac{\partial z}{\partial x} \) and \( \frac{\partial z}{\partial y} \) in terms of the partial derivatives of \( F \), ultimately helping us understand the relationship between these variables even when they are not laid out explicitly.

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