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Verify that \(f_{x y}=f_{y x}\) for the following functions. $$f(x, y)=e^{x+y}$$

Short Answer

Expert verified
Question: Verify that the mixed partial derivatives of the function \(f(x, y) = e^{x+y}\) are equal. Answer: After calculating the mixed partial derivatives \(f_{xy}\) and \(f_{yx}\), we found that both are equal to \(e^{x+y}\). Therefore, we have verified that the mixed partial derivatives of the given function \(f(x, y) = e^{x+y}\) are equal.

Step by step solution

01

Compute \(f_x\) and \(f_y\)

First, let's compute the first partial derivatives of f(x, y) with respect to x and y. To find \(f_x\), we'll differentiate f with respect to x while treating y as a constant: $$ f_x = \frac{\partial}{\partial x} (e^{x+y}) = e^{x+y} $$ Likewise, to find \(f_y\), we'll differentiate f with respect to y while treating x as a constant: $$ f_y = \frac{\partial}{\partial y} (e^{x+y}) = e^{x+y} $$
02

Compute \(f_{xy}\) and \(f_{yx}\)

Now we will compute the second partial derivatives \(f_{xy}\) and \(f_{yx}\). To compute \(f_{xy}\), we'll differentiate \(f_x\) with respect to y while treating x as a constant: $$ f_{xy} = \frac{\partial}{\partial y} (e^{x+y}) = e^{x+y} $$ To compute \(f_{yx}\), we'll differentiate \(f_y\) with respect to x while treating y as a constant: $$ f_{yx} = \frac{\partial}{\partial x} (e^{x+y}) = e^{x+y} $$
03

Verify \(f_{xy} = f_{yx}\)

Comparing the expressions we have obtained for \(f_{xy}\) and \(f_{yx}\), we notice that they are both equal to \(e^{x+y}\). Since these expressions are equal, we can conclude that: $$ f_{xy} = f_{yx} $$ Therefore, we have verified that the mixed partial derivatives of the given function \(f(x, y) = e^{x+y}\) are equal.

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