/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 Give an equation of the plane wi... [FREE SOLUTION] | 91Ó°ÊÓ

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Give an equation of the plane with a normal vector \(\mathbf{n}=\langle 1,1,1\rangle\) that passes through the point (1,0,0)

Short Answer

Expert verified
Answer: The equation of the plane is x + y + z = 1.

Step by step solution

01

Write the general equation of the plane

Using the given normal vector \(\mathbf{n}=\langle 1, 1, 1 \rangle\), we can write the general equation of the plane as: \(1x + 1y + 1z = D\)
02

Plug in the given point (1,0,0)

Substitute the given point (1,0,0) into the equation of the plane: \(1(1) + 1(0) + 1(0) = D\) Now, solve for D: \(1 + 0 + 0 = 1\)
03

Write the final equation of the plane

Now that we have found the value of D, we can write the final equation of the plane: \(x + y + z = 1\) So the equation of the plane with a normal vector \(\mathbf{n}=\langle 1, 1, 1 \rangle\) that passes through the point (1,0,0) is: \(x + y + z = 1\)

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