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Use differentials to approximate the change in \(z\) for the given changes in the independent variables. \(z=e^{x+y}\) when \((x, y)\) changes from (0,0) to (0.1,-0.05)

Short Answer

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Question: Approximate the change in the function \(z = e^{x+y}\) when \((x, y)\) changes from \((0, 0)\) to \((0.1, -0.05)\) using differentials. Answer: The approximate change in \(z\) for the given changes in the independent variables is \(dz = 0.05\).

Step by step solution

01

Compute the partial derivatives of \(z\) with respect to \(x\) and \(y\).

To find the partial derivatives of \(z\) with respect to \(x\) and \(y\), we can use the chain rule and Exponential rule. Since \(z = e^{x+y}\), we have: \(\frac{\partial z}{\partial x} = e^{x+y}\) \(\frac{\partial z}{\partial y} = e^{x+y}\)
02

Evaluate the partial derivatives at \((x, y) = (0, 0)\).

We need to evaluate the partial derivatives at \((x, y) = (0, 0)\) to use them to approximate the change in \(z\). Based on our partial derivatives calculated earlier: \(\frac{\partial z}{\partial x}(0, 0) = e^{0+0} = 1\) \(\frac{\partial z}{\partial y}(0, 0) = e^{0+0} = 1\)
03

Calculate the change in \(x\) and \(y\).

To approximate the change in \(z\), we need to determine the change in \(x\) and \(y\). Since \((x, y)\) changes from \((0, 0)\) to \((0.1, -0.05)\), we have: \(\Delta x = 0.1 - 0 = 0.1\) \(\Delta y = -0.05 - 0 = -0.05\)
04

Use differentials to approximate the change in \(z\).

Now that we have the partial derivatives and the change in \(x\) and \(y\), we can use differentials to approximate the change in \(z\). The differential \(dz\) is given by: \(dz = \frac{\partial z}{\partial x} \Delta x + \frac{\partial z}{\partial y} \Delta y\) Substituting our values for partial derivatives, \(\Delta x\), and \(\Delta y\): \(dz = (1)(0.1) + (1)(-0.05) = 0.1 - 0.05 = 0.05\) Thus, the approximate change in \(z\) for the given changes in the independent variables is \(dz = 0.05\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Derivatives
Partial derivatives are a foundational concept in multivariable calculus. They represent the rate at which a function changes as one variable changes while the others are held constant. For example, if we have a function like the one given in the exercise, \( z = e^{x+y} \), the partial derivative with respect to \( x \), denoted by \( \frac{\partial z}{\partial x} \), tells us how much \( z \) will change for a small change in \( x \) keeping \( y \) constant, and vice versa for \( \frac{\partial z}{\partial y} \).

In the context of the problem, finding these derivatives at the point (0,0) and using them to approximate changes in \( z \) is a practical application of partial derivatives that can give insights into how a system reacts to slight variations in multiple parameters.
Exponential Functions
Exponential functions, such as \( e^{x} \), are pivotal in calculus for modeling growth and decay processes. The function in this exercise, \( z = e^{x+y} \), is an exponential function where the exponent is itself a function of two variables, \( x \) and \( y \). Exponential functions have a unique property where the derivative is proportional to the function's value, which makes them particularly manageable when it comes to differentiation. In simple terms, no matter the complexity of the exponent, if you differentiate an exponential function, you end up with a multiple of the same exponential function.
Approximating Change
Approximating change using differentials is a powerful tool in calculus when exact calculations are either unnecessary or not feasible. This technique involves using the values of derivatives at a certain point to estimate the change in a function's value as its inputs slightly vary. In this exercise, by computing \( \Delta x \) and \( \Delta y \), and then applying the partial derivatives, we can predict how much \( z \) will change. The key is that differentials provide a linear approximation, which tends to be enough for small changes, as seen with \( \Delta x = 0.1 \) and \( \Delta y = -0.05 \). This is a practical approach often used in engineering and the sciences to predict outcomes without complex calculations.
Chain Rule
The chain rule is a fundamental rule in calculus for handling the derivatives of composite functions. When you have a function inside another function, like \( z = e^{x+y} \), the chain rule guides you through the process of finding the derivative. It states that to differentiate the outer function, you multiply the derivative of the outer function by the derivative of the inner function. Although the chain rule was not explicitly used in the given solutions, understanding this rule is crucial for recognizing how partial derivatives of more complex compositions are taken. In this exercise, however, the partial derivatives turned out to be straightforward due to the nature of the exponential function.

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Most popular questions from this chapter

A classical equation of mathematics is Laplace's equation, which arises in both theory and applications. It governs ideal fluid flow, electrostatic potentials, and the steadystate distribution of heat in a conducting medium. In two dimensions, Laplace's equation is $$\frac{\partial^{2} u}{\partial x^{2}}+\frac{\partial^{2} u}{\partial y^{2}}=0.$$ Show that the following functions are harmonic; that is, they satisfy Laplace's equation. $$u(x, y)=\tan ^{-1}\left(\frac{y}{x-1}\right)-\tan ^{-1}\left(\frac{y}{x+1}\right)$$

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