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Determine whether the following pairs of planes are parallel, orthogonal, or neither. $$2 x+2 y-3 z=10 \text { and }-10 x-10 y+15 z=10$$

Short Answer

Expert verified
Answer: The given planes are parallel.

Step by step solution

01

Identify the normal vectors

For the given plane equations, identify the normal vectors by extracting the coefficients of the variables (x, y, and z). \\ Plane 1: \(2x + 2y - 3z = 10\) has normal vector \(\bold{N}_1 = \begin{bmatrix}2\\2\\-3\end{bmatrix}\) \\ Plane 2: \(-10x - 10y + 15z = 10\) has normal vector \(\bold{N}_2 = \begin{bmatrix}-10\\-10\\15\end{bmatrix}\)
02

Determine the relationship between the normal vectors

Determine if the normal vectors are parallel or orthogonal. \\ To check if the normal vectors are parallel, we can see if they are scalar multiples of each other. \\ $$\frac{-10}{2} = \frac{-10}{2} = \frac{15}{-3} = 5 \implies \bold{N}_1 = -5\bold{N}_2$$ \\ Since \(\bold{N}_1 = -5\bold{N}_2\), the normal vectors are parallel. Thus, the planes are parallel. To verify that the normal vectors are not orthogonal, we can calculate their dot product and see if it is equal to zero. \\ $$\bold{N}_1 \cdot \bold{N}_2 = 2(-10) + 2(-10) - 3(15) = -60$$ \\ Since \(\bold{N}_1 \cdot \bold{N}_2 \neq 0\), the normal vectors are not orthogonal. Thus, the planes are not orthogonal. The pair of planes are
03

parallel

, since their normal vectors are scalar multiples of each other and their dot product is not equal to zero.

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Most popular questions from this chapter

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