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Use what you learned about surfaces in Section 12.1 to sketch a graph of the following functions. In each case identify the surface and state the domain and range of the function. $$h(x, y)=2 x^{2}+3 y^{2}$$

Short Answer

Expert verified
Answer: The function h(x,y) = 2x^2 + 3y^2 represents an elliptic paraboloid surface. Its domain is the set of all ordered pairs of real numbers: Domain(h) = {(x, y) | x 鈭 鈩, y 鈭 鈩潁. Its range is all real numbers greater than or equal to 0: Range(h) = {h(x, y) | h(x, y) 鈮 0}.

Step by step solution

01

Identify the surface

In this case, h(x, y) is a quadratic form, which means the surface can be represented as an equation that only contains terms with squared variables, without any products of different variables. This surface can be classified as an elliptic paraboloid.
02

Sketch the graph cross sections

At the cross sections, we can view the graph by fixing one of the variables and sketching the resulting quadratic function. For instance, if we let x = 0, the function becomes h(0, y) = 3y^2, which is a parabola opening upwards, located along the y-axis. If we let y = 0, the function becomes h(x, 0) = 2x^2, which is a parabola opening upwards, located along the x-axis. When sketching these cross sections, notice that the parabolas have different coefficients, indicating that the surface is wider along the x-axis than along the y-axis. The combination of these cross sections represents an elliptical paraboloid, with the bottom vertex at the origin and opening upwards.
03

Domain of the function

The domain of the function is the set of all possible input values (x, y) for which the function is defined. Since there are no restrictions on the values of x and y in the given equation, both x and y can take any real number. Therefore, the domain of the function h(x, y) is the set of all ordered pairs of real numbers, which can be represented as: Domain(h) = {(x, y) | x 鈭 鈩, y 鈭 鈩潁
04

Range of the function

The range of the function is the set of all possible output values h(x, y) produced by the inputs from the domain. Since the surface is an elliptic paraboloid opening upwards, the minimum value for h(x, y) occurs at the vertex (0, 0) where h(0, 0) = 0. As x and y increase or decrease, h(x, y) also increases, and since there is no upper bound on the values they can take, there is no upper bound on the values of h(x, y). Thus, the range of the function is all real numbers greater than or equal to 0: Range(h) = {h(x, y) | h(x, y) 鈮 0}

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Forms
A quadratic form is a specific type of mathematical expression that includes terms of squared variables. You鈥檝e likely encountered these forms in algebra with equations like \( ax^2 + by^2 \). What makes them unique is that they contain variables raised to the second power only, without involving products of different variables. This structure allows us to categorize surfaces based on the behavior and relationships of these squared terms.

In the exercise about the function \( h(x, y) = 2x^2 + 3y^2 \), we are working with a quadratic form, meaning it can be visualized as a type of 3D surface called an elliptic paraboloid. Because each variable is squared and added, rather than multiplied together, it gives a smooth, curved surface that looks somewhat like an elongated dome or bowl.

Understanding quadratic forms helps in analyzing and sketching these surfaces, revealing properties like symmetry and curvature. Recognizing and interpreting these forms is crucial for solving mathematical problems involving 3D surfaces.
Domain and Range
When dealing with functions, especially those that define 3D surfaces, it's important to understand the domain and range. The domain of a function refers to all the possible input values, and in this exercise, \( h(x, y) = 2x^2 + 3y^2 \), any real number is valid for both \( x \) and \( y \). This is because there are no restrictions like denominators or square roots that could limit the values \( x \) and \( y \) can take.

Therefore, the domain is expressed as all pairs \( (x, y) \) where \( x \) and \( y \) are elements of real numbers, denoted by \( x \in \mathbb{R}, y \in \mathbb{R} \).

The range, on the other hand, is all the possible output values the function can produce. For \( h(x, y) \), since the elliptic paraboloid opens upwards, the minimum value occurs at the vertex where \( x = 0 \) and \( y = 0 \). Here, \( h(0, 0) = 0 \) and as we move away from this point, both \( x \) and \( y \) grow, making \( h(x, y) \) larger without an upper bound. Thus, the range consists of all real numbers \( h(x, y) \geq 0 \).

Knowing the domain and range provides a complete picture of where the function can "live" in the coordinate plane and how it behaves in 3D space.
Cross Sections
To grasp more about the shape of the surface described by \( h(x, y) = 2x^2 + 3y^2 \), examining cross sections is very helpful. Cross sections are like taking slices of the surface to see its internal structure and curvature. This is done by holding one of the two variables constant and analyzing the resulting shape.

If you set \( x = 0 \), the cross section becomes \( h(0, y) = 3y^2 \), clearly showing a parabola that opens upwards along the y-axis. If instead, you let \( y = 0 \), the cross section transforms into \( h(x, 0) = 2x^2 \), which also sketches a parabola opening upwards, but this time along the x-axis.

The difference in coefficients gives each parabola a distinct "wideness." Notice that the \( 2x^2 \) term is wider than \( 3y^2 \) due to the smaller coefficient, indicating that the elliptic paraboloid is stretched more in the direction of the x-axis.

Obtaining this understanding is vital for visualizing and graphing complex 3D surfaces, helping to predict their behavior and appearance without sophisticated graphing tools.

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Most popular questions from this chapter

Potential functions arise frequently in physics and engineering. A potential function has the property that \(a\) field of interest (for example, an electric field, a gravitational field, or a velocity field is the gradient of the potential (or sometimes the negative of the gradient of the potential). (Potential functions are considered in depth in Chapter 14 .) The electric field due to a point charge of strength \(Q\) at the origin has a potential function \(\varphi=k Q / r,\) where \(r^{2}=x^{2}+y^{2}+z^{2}\) is the square of the distance between a variable point \(P(x, y, z)\) and the charge, and \(k>0\) is a physical constant. The electric field is given by \(\mathbf{E}=-\nabla \varphi,\) where \(\nabla \varphi\) is the gradient in three dimensions. a. Show that the three-dimensional electric field due to a point charge is given by $$ \mathbf{E}(x, y, z)=k Q\left\langle\frac{x}{r^{3}}, \frac{y}{r^{3}}, \frac{z}{r^{3}}\right\rangle $$ b. Show that the electric field at a point has a magnitude \(|\mathbf{E}|=k Q / r^{2} .\) Explain why this relationship is called an inverse square law.

Potential functions arise frequently in physics and engineering. A potential function has the property that \(a\) field of interest (for example, an electric field, a gravitational field, or a velocity field is the gradient of the potential (or sometimes the negative of the gradient of the potential). (Potential functions are considered in depth in Chapter 14 .) In two dimensions, the motion of an ideal fluid (an incompressible and irrotational fluid) is governed by a velocity potential \(\varphi .\) The velocity components of the fluid, \(u\) in the \(x\) -direction and \(v\) in the \(y\) -direction, are given by \(\langle u, v\rangle=\nabla \varphi .\) Find the velocity components associated with the velocity potential \(\varphi(x, y)=\sin \pi x \sin 2 \pi y\).

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