/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 Evaluate the following limits. ... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the following limits. $$\lim _{(x, y) \rightarrow(3,1)} \frac{x^{2}-7 x y+12 y^{2}}{x-3 y}$$

Short Answer

Expert verified
Answer: The value of the limit is -1.

Step by step solution

01

Check if the expression is continuous at the given point

Before we proceed to compute the limit, it is essential to evaluate if the expression is continuous or discontinuous at the given point, (x, y) = (3, 1). Plugging these values into the given expression, we observe that the denominator becomes zero: \(x - 3y = 3 - 3(1) = 0\) In order to proceed with finding the limit, we need to simplify the expression further to eliminate any discontinuities related to the denominator.
02

Factor the numerator

To simplify the expression, we need to find common factors between the numerator and the denominator. In this case, we need to factor the numerator: \(x^2 - 7xy + 12y^2\) Factoring the quadratic expression in terms of x: \((x - 3y)(x - 4y)\) Thus, the expression becomes: $$\frac{(x - 3y)(x - 4y)}{x - 3y}$$
03

Cancel out the common factors

Now, we can simplify the expression by canceling out the common factors. In the current case, it is (x-3y): $$\frac{(x - 3y)(x - 4y)}{x - 3y} = x - 4y $$ The aforementioned simplification removes the discontinuity, and we can now directly evaluate the limit at the given point (x, y) = (3, 1).
04

Evaluate the limit

With the simplified expression, we can now directly substitute the values for x and y into the expression: $$x - 4y = 3 - 4(1) = 3 - 4 = -1$$ Finally, we have found the value of the limit: $$\lim _{(x, y) \rightarrow(3,1)} \frac{x^{2}-7 x y+12 y^{2}}{x-3 y} = -1$$

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