/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 90 Consider the family of limaçons... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Consider the family of limaçons \(r=1+b \cos \theta .\) Describe how the curves change as \(b \rightarrow \infty\).

Short Answer

Expert verified
Answer: As the parameter \(b\) approaches infinity, the shape of the curve in a limaçon becomes closer to a circle with radius \(b\). The influence of the term \(1 + b\cos\theta\) diminishes, and the curves are mainly shaped by the term \(b \cos\theta\).

Step by step solution

01

Understand the formula of a limaçon

The formula for a limaçon is given as \(r = 1 + b\cos\theta\), where \(r\) is the radial distance from the origin, \(\theta\) is the angle from the x-axis in the polar coordinate system, and \(b\) is a parameter that affects the shape of the curve.
02

Analyze the behavior when \(b \rightarrow \infty\)

To inspect how the limaçon's curves change as \(b \rightarrow \infty\), we need to see what happens to the radial distance \(r\) as the parameter \(b\) becomes very large. First, let's consider the cosine term, \(\cos\theta\). Since the value of the cosine lies between \(-1\) and \(1\) for every value of \(\theta\), no matter how large the parameter \(b\) gets, the cosine term will always be within the range \([-b, b]\). Given that, the radial distance can be expressed as \(r = 1 + b\cos\theta \Rightarrow r - b\cos\theta = 1\). Now divide both sides by \(b\): $$\frac{r}{b} -\cos\theta = \frac{1}{b}$$ As \(b \rightarrow \infty\), consider the right-hand side of the equation: \(\frac{1}{b} \rightarrow 0\).
03

Describe the curve

As \(b \rightarrow \infty\), we can rewrite the equation to: $$\frac{r}{b} - \cos\theta \rightarrow 0$$ This implies that: $$\frac{r}{b} \rightarrow \cos\theta$$ Given that the right-hand side of the equation doesn't depend on the parameter \(b\) and has a range of \([-1,1]\), the ratio \(\frac{r}{b}\) must also be within the same range as \(b\) grows large. As the parameter \(b\) becomes larger, the radial distance \(r\) must adapt to maintain this ratio within the \([-1,1]\) range. Thus, as \(b \rightarrow \infty\), the shape of the curve is increasingly dominated by the term \(b\cos\theta\), ultimately resembling a circle of radius \(b\).
04

Conclusion:

In conclusion, as the parameter \(b\) approaches infinity, the curves of the limaçon family move closer towards becoming circles with radius \(b\). The influence of the term \(1 + b\cos\theta\) diminishes, and the curves are mainly shaped by the term \(b \cos\theta\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polar Coordinates
To engage with limaçon curves, one must first grasp the concept of polar coordinates. This coordinate system is vastly different from the traditional Cartesian system you might be familiar with. Imagine you're standing in the middle of a large, empty field. In Cartesian coordinates, you'd locate a point by measuring how far left or right (x-axis) and how far forward or backward (y-axis) you need to walk. In polar coordinates, however, you consider how far away the point is from where you're standing—the radial distance—and the direction you need to turn to face that point, specified as an angle from a specific direction, usually the positive x-axis.

In mathematical terms, a polar coordinate is written as \(r, \theta\), where \(r\) is the radial distance, and \(\theta\) is the angular coordinate, measured in radians. For instance, if you describe the position \(3, \pi/2\), it means you should turn 90 degrees from the x-axis (since \(\pi/2\) radians equals 90 degrees) and then walk three units straight ahead. This system is especially useful for describing curves that are naturally circular or spiral, like limaçon curves.
Parametric Equations
When you hear 'parametric equations,' think of them as a way of expressing coordinates using a third variable, often denoted as \(t\) or in the case of polar equations, \(\theta\). Rather than expressing y in terms of x or vice versa, both \(x\) and \(y\) are expressed in terms of this third variable, which can be thought of as time or another independent parameter.

Parametric equations are akin to a set of instructions that describe a path: as the parameter changes, the equations provide us with a new set of \(x\) and \(y\) values, tracing out a curve. For polar equations, like the limaçon represented by \(r=1+b\cos\theta\), the radius \(r\) and angle \(\theta\) are dependent on the parameter \(b\). As you alter \(b\), you're essentially shaping the path of the curve, much like changing your walking pace affects your trajectory on a hike.
Cosine Function
Limaçon curves have a special relationship with the cosine function, which is at the heart of their equation: \(r=1+b\cos\theta\). The cosine function oscillates between -1 and 1, providing a rhythm to the movement of the curve as \(\theta\) changes. It dictates the harmonic motion, much like the steady beats of a drum in a song.

What happens when you adjust the volume of the beat? In the limaçon's equation, increasing \(b\) boosts the 'loudness' of the cosine function's influence, stretching the curve further away or closer to the center, depending on the angle \(\theta\). If you imagine increasing \(b\) indefinitely, \(b\cos\theta\) takes the limelight, and the curve begins to resemble a perfect circle—the ultimate steady beat, with no variation in radius as you walk full circle around the field.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A simplified model assumes that the orbits of Earth and Mars are circular with radii of 2 and \(3,\) respectively, and that Earth completes one orbit in one year while Mars takes two years. When \(t=0,\) Earth is at (2,0) and Mars is at (3,0) both orbit the Sun (at (0,0) ) in the counterclockwise direction. The position of Mars relative to Earth is given by the parametric equations \(x=(3-4 \cos \pi t) \cos \pi t+2, \quad y=(3-4 \cos \pi t) \sin \pi t\) a. Graph the parametric equations, for \(0 \leq t \leq 2\) b. Letting \(r=(3-4 \cos \pi t),\) explain why the path of Mars relative to Earth is a limaçon (Exercise 89).

Find a polar equation for each conic section. Assume one focus is at the origin.

Consider an ellipse to be the set of points in a plane whose distances from two fixed points have a constant sum 2 \(a .\) Derive the equation of an ellipse. Assume the two fixed points are on the \(x\) -axis equidistant from the origin.

Show that the polar equation $$r^{2}-2 r r_{0} \cos \left(\theta-\theta_{0}\right)=R^{2}-r_{0}^{2}$$ describes a circle of radius \(R\) whose center has polar coordinates \(\left(r_{0}, \theta_{0}\right)\).

Find parametric equations (not unique) of the following ellipses (see Exercises \(75-76\) ). Graph the ellipse and find a description in terms of \(x\) and \(y.\) An ellipse centered at (-2,-3) with major and minor axes of lengths 30 and \(20,\) parallel to the \(x\) - and \(y\) -axes, respectively, generated counterclockwise (Hint: Shift the parametric equations.)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.