/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 56 Find the area of the regions bou... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the area of the regions bounded by the following curves. \text { The limaçon } r=2-4 \sin \theta

Short Answer

Expert verified
Answer: The area of the region bounded by the given limaçon curve is \(4\pi\) square units.

Step by step solution

01

Identify the curve

The given curve is a limaçon represented by the polar equation \(r=2-4\sin\theta\).
02

Find the points of intersection with the origin

To find the points where the curve intersects the origin, we need to solve the equation for \(\theta\) when \(r=0\): \(0 = 2-4\sin\theta\) \(4\sin\theta = 2\) \(\sin\theta = \frac{1}{2}\) The sine function returns \(\frac{1}{2}\) at \(\theta=\frac{\pi}{6}\) and \(\theta=\frac{5\pi}{6}\). These two points will be the limits of our integration.
03

Set up the integral to find the area

To find the area of the limaçon bounded by the curve and the origin, we use the polar area formula: \(A=\frac{1}{2}\int_{\alpha}^{\beta} r^2 d\theta\) For our curve, this integral would be set up as follows: \(A=\frac{1}{2}\int_{\frac{\pi}{6}}^{\frac{5\pi}{6}} (2-4\sin\theta)^2 d\theta\)
04

Evaluate the integral

To find the area, we will now evaluate the integral: \(A = \frac{1}{2}\int_{\frac{\pi}{6}}^{\frac{5\pi}{6}} (4 - 16\sin\theta + 16\sin^2\theta) d\theta\) To evaluate the integral of the sine squared term, use the double-angle identity \(2\sin^2(\theta) = 1 - \cos(2\theta)\). So, the integral becomes: \(A = \frac{1}{2}\int_{\frac{\pi}{6}}^{\frac{5\pi}{6}} (4 - 16\sin\theta + 8 - 8\cos(2\theta)) d\theta\) Now, integrate with respect to \(\theta\): \(A = \frac{1}{2}[\int_{\frac{\pi}{6}}^{\frac{5\pi}{6}} 12 - 16\sin\theta - 8\cos(2\theta) d\theta]\) \(A = \frac{1}{2}[12\theta + 16\cos\theta - 4\sin(2\theta)|_{\frac{\pi}{6}}^{\frac{5\pi}{6}}]\)
05

Calculate the area

Plug in the limits of integration and calculate the area: \(A = \frac{1}{2}[12(\frac{5\pi}{6}) + 16\cos(\frac{5\pi}{6}) - 4\sin(\frac{5\pi}{3}) - (12(\frac{\pi}{6}) + 16\cos(\frac{\pi}{6}) - 4\sin(\frac{\pi}{3}) )]\) After calculating, we find that: \(A = 4\pi\) Thus, the area of the region bounded by the given limaçon curve is \(4\pi\) square units.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polar Coordinates
Polar coordinates are a two-dimensional coordinate system where each point on a plane is determined by a distance from a reference point and an angle from a reference direction. The reference point is known as the pole, typically corresponding to the origin of the Cartesian coordinate system, and the reference direction originates from the pole and is usually the positive x-axis.

Each point is represented as \( (r, \theta) \) where \( r \) is the radial distance from the pole, and \( \theta \) is the polar angle measured in radians from the reference direction. Polar coordinates are particularly useful for dealing with problems involving circular and spiral shapes, where using Cartesian coordinates can be cumbersome.
Polar Equations
Polar equations are mathematical expressions that provide a relationship between the radius \( r \) and the angle \( \theta \) in polar coordinates. These equations describe curves on the polar plane. A simple example is the equation of a circle \( r = a \) where \( a \) is the radius of the circle.

The lima\c{c}on that is given in the exercise, \( r=2-4\sin(\theta) \), is a more complex shape that depends on both the angle and the sine function. This equation showcases the behavior of the radius changing in accordance with the angle \( \theta \) to form a loop or dimple, characteristic of a lima\c{c}on, in polar coordinates.
Integration in Polar Coordinates
Integration in polar coordinates is a technique used to calculate areas and other properties of shapes that are easily described by polar equations. To find the area \( A \) enclosed by a polar curve \( r(\theta) \) between two angles \( \alpha \) and \( \beta \) we use the integral:

\( A = \frac{1}{2}\int_{\alpha}^{\beta} r(\theta)^2 d\theta \).

The factor of \( \frac{1}{2} \) comes from the derivation of the area element in polar coordinates, \( \frac{1}{2}r^2d\theta \) which represents a tiny wedge-shaped section of the area. Summing up (integrating) all such wedges between \( \alpha \) and \( \beta \) gives us the total area. In our exercise, this approach was used to determine the area bounded by the lima\c{c}on curve and the origin, through setting up and evaluating the definite integral.
Double-Angle Identities
Double-angle identities are formulas in trigonometry that express trigonometric functions of double angles in terms of trigonometric functions of single angles. One of the most widely used double-angle identities is for the sine squared function:

\( \sin^2(\theta) = \frac{1}{2}(1 - \cos(2\theta)) \).

These identities are particularly useful when dealing with integrals involving trigonometric functions, such as while integrating in polar coordinates to find areas. In the case of our exercise, the double-angle identity allowed the transformation of the \( \sin^2(\theta) \) term into an expression involving \( \cos(2\theta) \) which can be easily integrated to find the area under the lima\c{c}on curve.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find an equation of the following curves, assuming the center is at the origin. Sketch a graph labeling the vertices, foci, asymptotes (if they exist), and directrices. Use a graphing utility to check your work. An ellipse with vertices (±9,0) and eccentricity \(\frac{1}{3}\)

Find parametric equations (not unique) of the following ellipses (see Exercises \(75-76\) ). Graph the ellipse and find a description in terms of \(x\) and \(y.\) An ellipse centered at (-2,-3) with major and minor axes of lengths 30 and \(20,\) parallel to the \(x\) - and \(y\) -axes, respectively, generated counterclockwise (Hint: Shift the parametric equations.)

A trochoid is the path followed by a point \(b\) units from the center of a wheel of radius \(a\) as the wheel rolls along the \(x\) -axis. Its parametric description is \(x=a t-b \sin t, y=a-b \cos t .\) Choose specific values of \(a\) and \(b,\) and use a graphing utility to plot different trochoids. In particular, explore the difference between the cases \(a>b\) and \(a

The Lamé curve described by \(\left|\frac{x}{a}\right|^{n}+\left|\frac{y}{b}\right|^{n}=1,\) where \(a, b,\) and \(n\) are positive real numbers, is a generalization of an ellipse. a. Express this equation in parametric form (four pairs of equations are needed). b. Graph the curve for \(a=4\) and \(b=2,\) for various values of \(n\) c. Describe how the curves change as \(n\) increases.

Graph the following spirals. Indicate the direction in which the spiral is generated as \(\theta\) increases, where \(\theta>0 .\) Let \(a=1\) and \(a=-1\). Logarithmic spiral: \(r=e^{a \theta}\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.