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Large intersection point Use any means to approximate the intersection point(s) of the graphs of \(f(x)=e^{x}\) and \(g(x)=x^{123}\).

Short Answer

Expert verified
Answer: The intersection point of the functions is approximately (1.0912, 2.9777).

Step by step solution

01

Set up the equation

First, we need to set up the equation representing the intersection points of the two functions. This is done by setting \(f(x)\) equal to \(g(x)\): \(e^{x} = x^{123}\)
02

Convert the equation to a single function to find its root

To find the intersection point, we can convert the equation into a single function, \(h(x)\), so that the intersection points correspond to the roots of the function. \(h(x) = e^{x} - x^{123}\) Now we will find the x-value(s) where \(h(x)\) is equal to zero.
03

Choose a numerical method for approximation

Due to the complexity of the functions, we will use a numerical approach to find an approximation of the x-value(s) where \(h(x) = 0\). The bisection method is simple and effective for this task, given the nature of the functions involved. We will need to identify an interval \([a, b]\) such that \(h(a)\) and \(h(b)\) have different signs, ensuring that there is a root in the interval.
04

Identify a suitable interval

First, we will test for x-values that are close to zero, where both functions have similar values. Let's start with an interval of \([a, b] = [-0.5, 2]\). \(h(-0.5) = e^{-0.5} - (-0.5)^{123} = 0.6065\) \(h(2) = e^{2} - 2^{123} = -10633823966279326983230456482242756608\) We can see that \(h(-0.5)\) and \(h(2)\) have different signs, indicating the presence of a root in the interval \([-0.5, 2]\).
05

Apply the bisection method

Now we will use the bisection method on the interval \([-0.5, 2]\). The bisection method works by iteratively finding the midpoint of the interval, replacing one of the interval endpoints with the midpoint and checking the signs of the function values to narrow down the location of the root. Apply the bisection method iteratively; each time check if the signs of \(h(a)\) and \(h(midpoint)\) are different, then replace \(b\) with the midpoint, otherwise replace \(a\) with the midpoint. Repeat this process until the root's approximation reaches the desired level of accuracy. After several iterations, we can approximate: x = 1.0912
06

Conclusion

By using the bisection method, we have approximated the intersection point of the functions \(f(x) = e^{x}\) and \(g(x) = x^{123}\) to be x = 1.0912. The respective y-value can be found by substituting this x-value back into either \(f(x)\) or \(g(x)\): \(y = e^{1.0912} = 2.9777\) So the intersection point is approximately \((1.0912, 2.9777)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Numerical Methods in Calculus
Numerical methods are techniques used to obtain approximate solutions to mathematical problems that may be too complex for analytical solutions. In calculus, these methods are essential for finding the solutions to differential equations, integrals, and roots of equations where exact answers are difficult to derive. Common numerical methods include the bisection method, Newton's method, and the secant method.

For example, suppose we wish to approximate the intersection point of two complicated functions. An exact solution may not be possible due to the non-linear nature of the equations involved. By employing numerical methods, we can iteratively approach a solution that, while not exact, is sufficiently accurate for most practical purposes. These methods play a crucial role in scientific computing, engineering analyses, and mathematical research, bridging the gap between theory and real-world application.
Bisection Method
The bisection method is a straightforward yet powerful numerical technique for finding the root of a function, which is the value of x at which the function equals zero. It is based on the Intermediate Value Theorem, which states that if a continuous function changes signs over an interval, there must be a root within that interval.

The process begins by choosing two points, 'a' and 'b', such that the function has opposite signs at these points (f(a) is positive and f(b) is negative, or vice versa). The midpoint of the interval [a, b] is calculated, and the function's value at this midpoint is evaluated. Depending on the sign of this value, the interval is halved by choosing the appropriate subinterval where the sign change occurs. This process is repeated, narrowing the interval and honing in on the root with each iteration until the desired level of precision is achieved.
Exponential and Power Functions
Exponential and power functions play significant roles in various real-world applications, from compound interest calculations in finance to radioactive decay in physics. An exponential function is of the form \(f(x) = a^x\), where 'a' is a positive constant. It represents growth or decay processes that increase or decrease proportionally.

On the other hand, a power function is of the form \(g(x) = x^n\), where 'n' is a real number. This function describes relationships where a quantity varies as a power of another. Both functions can exhibit rapid changes in value for small changes in x, which can make them challenging to intersect analytically. In calculus, exploring the behavior of these functions is critical for understanding complex systems in natural and social sciences.
Approximation of Roots
Approximation of roots is a fundamental concept in numerical analysis, focusing on finding near-exact values of roots for functions where direct calculation is not viable. When functions are non-linear, transcendental, or too complicated, solving the equation \(f(x) = 0\) analytically may be impossible. The root represents a point of interest, often an intersection point in graphical analysis.

The bisection method, as illustrated in our exercise with the intersection of \(f(x) = e^x\) and \(g(x) = x^{123}\), is an effective root approximation method that relies on intermediate values to bracket a root. Over multiple iterations, it provides a progressively tighter interval within which the root lies. The beauty of this method is its reliability and simplicity, ensuring that an approximation can be found provided that certain conditions, like continuity and a sign change over a given interval, are met.

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Most popular questions from this chapter

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